Problem 52
Question
Let \(f(x)=(x-\pi) \cos \pi x\). a. Try to find \(\lim _{x \rightarrow \infty} f(x)\) by letting \(x=10^{2}, 10^{3}\), and \(10^{4}\). b. Does \(\lim _{x \rightarrow \infty} f(x)\) exist? Support your answer.
Step-by-Step Solution
Verified Answer
The limit \( \lim_{x \to \infty} f(x) \) does not exist because the function oscillates indefinitely.
1Step 1: Express the Function
The function is given as \( f(x) = (x - \pi) \cos (\pi x) \). We need to find the behavior of this function as \( x \to \infty \).
2Step 2: Analyze Function Behavior for Large x
Consider \( x = 10^2, 10^3, \) and \( 10^4 \) to estimate the limit. For large values of \( x \), \(x - \pi \approx x \). The term \( \cos(\pi x) \) oscillates between -1 and 1.
3Step 3: Estimate Function Values
Calculate \( f(10^2) = (10^2 - \pi) \cos(\pi \times 10^2) \approx 100 \cos(\pi \times 10^2) \) which oscillates between -100 and 100.
4Step 4: Generalize for Larger Values
Similarly, \( f(10^3) \) and \( f(10^4) \) result in similar oscillations since \( \cos(\pi x) \) will always be bounded between -1 and 1. Thus, \( f(x) = (x - \pi) \cos(\pi x) \) oscillates between \(- \infty\) and \(+ \infty\) as \( x \to \infty \).
5Step 5: Determine the Limit Existence
Since \( f(x) \) oscillates indefinitely without approaching a particular value, \( \lim_{x \to \infty} f(x) \) does not exist.
Key Concepts
OscillationBehavior of FunctionsTrigonometric Functions
Oscillation
In mathematics, oscillation refers to a phenomenon where a function moves back and forth between certain bounds. This behavior is often seen in trigonometric functions, like sine and cosine, which repetitively fluctuate between -1 and 1. When studying limits and the behavior of functions, oscillation means that instead of the function settling towards a specific value, it keeps varying within certain limits, making it difficult or impossible for the function to converge to a single value.
In the given exercise, the function involves the term \(\cos(\pi x)\), which oscillates between -1 and 1. The term \(x - \pi\) grows larger as \(x\) increases. Thus, combining an oscillating term with an unbounded one results in \(f(x)\) traveling between increasingly larger positive and negative values. That means the function never settles down - it keeps "swinging" back and forth, indicating strong oscillatory behavior.
In the given exercise, the function involves the term \(\cos(\pi x)\), which oscillates between -1 and 1. The term \(x - \pi\) grows larger as \(x\) increases. Thus, combining an oscillating term with an unbounded one results in \(f(x)\) traveling between increasingly larger positive and negative values. That means the function never settles down - it keeps "swinging" back and forth, indicating strong oscillatory behavior.
- This type of movement occurs indefinitely as \(x\) approaches infinity.
- Because of this indefinite oscillation, the limit \(\lim_{x \to \infty} f(x)\) does not exist.
Behavior of Functions
Understanding the behavior of functions as they approach infinity reveals important insights about their tendencies and constraints. Functions can generally do one of three things: grow without bounds (positively or negatively), approach a finite limit, or oscillate indefinitely. The behavior of a function depends significantly on its components and how they interact as the inputs become large.
In the exercise with \(f(x) = (x - \pi) \cos(\pi x)\), two major influences shape the function's behavior:
In the exercise with \(f(x) = (x - \pi) \cos(\pi x)\), two major influences shape the function's behavior:
- **Growth Influence:** The term \(x - \pi\) behaves much like \(x\) when \(x\) is very large, contributing to making the function potentially unbounded.
- **Oscillatory Influence:** As previously discussed, \(\cos(\pi x)\) oscillates between -1 and 1.
Trigonometric Functions
Trigonometric functions, like sine, cosine, and tangent, are fundamental in understanding waves and oscillations. These functions are periodic, meaning their values repeat at regular intervals. Their periodic nature makes them invaluable in multiple areas of science and engineering, especially when modeling anything cyclic or oscillatory, such as sound waves, light waves, and even tidal patterns.
In our exercise, the trigonometric component \(\cos(\pi x)\) plays a crucial role. It maintains a constant oscillation between -1 and 1 regardless of the value of \(x\). This periodic repetition is essential in computational scenarios where precise cycles are modeled. Yet, it is this same feature that prevents the function \(f(x) = (x - \pi) \cos(\pi x)\) from having a limit as \(x\) goes to infinity.
In our exercise, the trigonometric component \(\cos(\pi x)\) plays a crucial role. It maintains a constant oscillation between -1 and 1 regardless of the value of \(x\). This periodic repetition is essential in computational scenarios where precise cycles are modeled. Yet, it is this same feature that prevents the function \(f(x) = (x - \pi) \cos(\pi x)\) from having a limit as \(x\) goes to infinity.
- Knowing this about trigonometric functions helps in anticipating their role in composite functions.
- The periodic behavior underscores the importance of these functions in limit analysis and other areas where cyclic patterns are present.
Other exercises in this chapter
Problem 51
A company plans to invest \(\$ 50,000\) for the next 4 years, initially buying oil stocks. If it seems profitable to do so, the oil stocks will be sold before t
View solution Problem 51
Find a point \(c\) such that \(f^{\prime}(c)=f^{\prime \prime}(c)=0\) Using the derivative of \(f\), show that \(f\) does not have a relative extreme value at \
View solution Problem 52
Graph each pair of functions. Shade the region(s) the graphs enclose. $$ f(x)=x^{2}+4 \text { and } g(x)=12-x^{2} $$
View solution Problem 52
Let \(h(t)\) denote the height at time \(t\) of an object moving in a vertical direction above the ground. Assume that the object is subject only to the force o
View solution