Problem 52
Question
In Exercises 39-54, find the determinant of the matrix.Expand by cofactors on the row or column that appears to make the computations easiest. \(\left[ \begin{array}{r} 1 & 4 & 3 & 2 \\ -5 & 6 & 2 & 1 \\ 0 & 0 & 0 & 0 \\\ 3 & -2 & 1 & 5 \end{array} \right]\)
Step-by-Step Solution
Verified Answer
The determinant of the given matrix is 0.
1Step 1: Choosing the Row for Expansion
In this calculation, the third row will be selected for expansion as it contains all zeros, which simplifies the calculations.
2Step 2: Calculation of the Determinant
The determinant of a 4x4 matrix can be calculated by the rule of Sarrus for 4x4 matrices, or by expanding along a row or column. If expanding along the third row, the formula is \( Det(A) = a_{31}C_{31} + a_{32}C_{32} + a_{33}C_{33}+a_{34}C_{34}\) where \(a_{ij}\) are the elements of the matrix and \(C_{ij}\) are their corresponding cofactors. But since \( a_{31}=a_{32}=a_{33}=a_{34}=0\), the determinant of this matrix is 0.
Key Concepts
Cofactor Expansion4x4 MatrixZero Row Determinant
Cofactor Expansion
Cofactor expansion, also known as Laplace’s expansion, is a method used to compute the determinant of a matrix. It involves breaking down a larger matrix into smaller matrices, making it particularly handy as the size of the matrix increases.
To apply cofactor expansion, you choose a row or a column from the matrix. Then you calculate the determinant of the smaller matrices obtained by removing the chosen row and column element by element. Here's a simple way to think about the steps:
- Select a row or column to expand on (usually the one with the most zeros for simplicity).
- For each element in that row or column, determine its cofactor, which involves computing the determinant of a smaller matrix (also known as a minor), and then multiplying it by (-1) raised to the sum of the row and column indices.
- Multiply each element by its corresponding cofactor, and sum up these results to get the determinant of the original matrix.
4x4 Matrix
Understanding the nature of a 4x4 matrix is integral to grasping the calculation of determinants. Unlike a 2x2 or a 3x3 matrix, a 4x4 matrix allows for more complexity, but it follows the same foundational principles.
A 4x4 matrix is composed of four rows and four columns, meaning it has 16 elements. The determinant of such a matrix can be calculated using various methods including the cofactor expansion method mentioned before or other techniques like the Rule of Sarrus, typically for smaller matrices.
When tackling a matrix of this size, it's effective to:
- Check for rows or columns with zeros to simplify calculations since these make excellent candidates for cofactor expansion.
- Remember that the determinant results from the summation of expanded terms corresponding to either the rows or columns of the matrix.
Zero Row Determinant
A zero row within a matrix provides valuable insights when calculating the determinant. Specifically, if an entire row or column within a matrix is composed of zeros, the determinant of that matrix is zero. This principle is a direct consequence of cofactor expansion.
Here's why this happens:
- When performing cofactor expansion, you compute terms involving each element of the chosen row or column, each multiplied by its cofactor, and then summed up.
- If you choose a row or column filled with zeros in the matrix, then every term in the sum is zero since each involves multiplication by a zero element.
Other exercises in this chapter
Problem 51
In Exercises 49-54, use the matrix capabilities of a graphing utility to write the \(matrix\) in reduced row-echelon form. \( \left[\begin{array}{rrr} 1 & 2 & 3
View solution Problem 52
In Exercises 47-52, use a determinant to find an equation of the line passing through the points. \((\frac{2}{3}, 4)\), \((6, 12)\)
View solution Problem 52
In Exercises 51-58, use an inverse matrix to solve (if possible) the system of linear equations. \(\begin{cases} 18x + 12y = 13 \\ 30x + 24y = 23 \end{cases}\)
View solution Problem 52
In Exercises 47-52, if possible, find (a) \(AB\), (b) \(BA\), and (c) \(A^2\). (Note: \(A^2 = AA\).) \(A=\left[\begin{array}{r} 3 & 2 & 1 \end{array}\right]\),
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