Problem 52
Question
If \(f(x)=3^{x}\), find each value. give an exact answer and a two-decimal-place approximation. See Sections 8.2 and \(10.2 .\) $$ f\left(\frac{1}{2}\right) $$
Step-by-Step Solution
Verified Answer
Exact: \(\sqrt{3}\); Approximation: \(1.73\).
1Step 1: Substitute the Input Value
To find \(f\left(\frac{1}{2}\right)\), substitute \(x = \frac{1}{2}\) into the function: \[f(x) = 3^{x} \Rightarrow f\left(\frac{1}{2}\right) = 3^{\frac{1}{2}}.\]
2Step 2: Express as a Square Root
The expression \(3^{\frac{1}{2}}\) can be rewritten using the square root notation: \[3^{\frac{1}{2}} = \sqrt{3}.\]
3Step 3: Calculate the Square Root
Using a calculator, approximate \(\sqrt{3}\) to two decimal places:\[\sqrt{3} \approx 1.73.\]
4Step 4: Present the Exact and Approximate Values
The exact value of \(f\left(\frac{1}{2}\right)\) is \(\sqrt{3}\). The approximate value, rounded to two decimal places, is \(1.73\).
Key Concepts
Square RootsApproximation TechniquesFunction Evaluation
Square Roots
When dealing with exponential functions like \( f(x) = 3^x \), understanding square roots becomes essential, especially when evaluating expressions like \( 3^{\frac{1}{2}} \). A square root is essentially a value that, when multiplied by itself, gives the original number. For example, the square root of 9 is 3 because \( 3 \times 3 = 9 \).
In mathematical terms, the square root of a number \( a \) is denoted as \( \sqrt{a} \). In our exercise, when we substitute \( x = \frac{1}{2} \) into the exponential function, we get \( 3^{\frac{1}{2}} \), which is equivalent to \( \sqrt{3} \). This is an exact expression of the value.
In mathematical terms, the square root of a number \( a \) is denoted as \( \sqrt{a} \). In our exercise, when we substitute \( x = \frac{1}{2} \) into the exponential function, we get \( 3^{\frac{1}{2}} \), which is equivalent to \( \sqrt{3} \). This is an exact expression of the value.
- It simplifies the understanding of the exponent \( \frac{1}{2} \) as a square root operation.
- Using square roots helps in representing non-whole number exponents in a more intuitive way.
Approximation Techniques
Approximating values is a key skill when the exact answer involves irrational numbers, like square roots. Since square roots often result in long, non-repeating decimals, calculators are used to find a useful approximation.
In our example, the exact value of \( \sqrt{3} \) is calculated to be approximately \( 1.7320508...\) in decimal form. For practical purposes, especially when precision isn't crucial, we often round this to two decimal places: \( 1.73 \).
In our example, the exact value of \( \sqrt{3} \) is calculated to be approximately \( 1.7320508...\) in decimal form. For practical purposes, especially when precision isn't crucial, we often round this to two decimal places: \( 1.73 \).
- Rounding involves reducing the number of decimal places while maintaining closeness to the actual number.
- This is especially useful in fields like science and engineering where exact values can oversimplify the models.
Function Evaluation
Function evaluation involves substituting a given input value into a function to find the corresponding output. For example, in the function \( f(x) = 3^x \), we want to evaluate it at \( x = \frac{1}{2} \).
To do this, follow these steps:
To do this, follow these steps:
- Identify the given function, which is \( f(x) = 3^x \).
- Substitute \( x = \frac{1}{2} \) into the function, resulting in \( f\left(\frac{1}{2}\right) = 3^{\frac{1}{2}} \).
- Recognize this expression represents a square root, \( \sqrt{3} \).
Other exercises in this chapter
Problem 52
Solve. $$ \log _{3} \frac{1}{81}=x $$
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Approximate each logarithm to four decimal places. $$ \log _{3} 2 $$
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Solve each equation. $$ 2-6 x=6(1-x) $$
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Write each expression as a sum or difference of logarithms. Assume that variables represent positive numbers. $$ \log _{3} \frac{(x+5)^{2}}{x} $$
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