Problem 52
Question
For the following problems, replace \(N\) with the proper quantity. $$ \frac{y-3}{y+3}=\frac{N}{y^{2}-9} $$
Step-by-Step Solution
Verified Answer
Answer: N = y - 3
1Step 1: Factor the denominator on the right side
We first want to factor the denominator on the right side of the equation, \(y^2 - 9\), which is a difference of squares. This can be factored as \((y - 3)(y + 3)\).
So the equation becomes:
$$
\frac{y-3}{y+3}=\frac{N}{(y-3)(y+3)}
$$
2Step 2: Compare the numerators
Now that we have factored the denominator on the right side of the equation, we can compare the numerators of both fractions.
We see that the numerators must be equal for the two fractions to be equivalent, that is:
$$
y - 3 = N
$$
3Step 3: Replace N with the proper quantity
Now that we have determined that \(N = y - 3\), we can replace \(N\) with this quantity in the original equation. Doing so, we get:
$$
\frac{y-3}{y+3}=\frac{y-3}{(y-3)(y+3)}
$$
Key Concepts
Factoring PolynomialsEquivalent FractionsDifference of Squares
Factoring Polynomials
Factoring polynomials is an essential technique in algebra that involves rewriting a polynomial as a product of its simpler factors. This process is helpful because it can simplify complex equations and expressions. When you factor a polynomial, you are essentially reversing the process of expansion. For instance, if you have expanded to obtain a polynomial, factoring allows you to find the original expressions that were multiplied together.
To successfully factor a polynomial, you should look for:
To successfully factor a polynomial, you should look for:
- Common factors: Numbers or variables that appear in all the terms of the polynomial.
- Special patterns: Recognize patterns such as the difference of squares or perfect square trinomials.
- Grouping terms: Often useful when a polynomial has four or more terms. Group terms to help find common factors.
Equivalent Fractions
Equivalent fractions are fractions that have the same value, even though they may look different at first glance. To determine if two fractions are equivalent, their cross-products should be equal. This means that multiplying the numerator of one fraction by the denominator of the other should yield the same result as the cross multiplication in the other direction.
In the initial exercise, the task is to ensure the fractions on both sides of the equation are equivalent. By using the steps in factoring, we equate the original fraction to the transformed one. Here’s a simple breakdown:
In the initial exercise, the task is to ensure the fractions on both sides of the equation are equivalent. By using the steps in factoring, we equate the original fraction to the transformed one. Here’s a simple breakdown:
- The fraction \( \frac{y-3}{y+3} \) is the original expression.
- The objective is to find \( N \) such that \( \frac{N}{y^2 - 9} \) remains unchanged in its value from the original.
Difference of Squares
The difference of squares is a specific pattern in algebra where you have an expression in the form \( a^2 - b^2 \). This pattern can be transformed using the identity formula \( a^2 - b^2 = (a - b)(a + b) \). This is a commonly used technique since recognizing this form allows you to quickly factor expressions.
For the problem at hand, the expression \( y^2 - 9 \) is a classic example of the difference of squares:
For the problem at hand, the expression \( y^2 - 9 \) is a classic example of the difference of squares:
- It can be rewritten as \( y^2 - 3^2 \).
- Applying the identity formula gives \( (y - 3)(y + 3) \).
Other exercises in this chapter
Problem 52
For the following problems, perform the indicated operations. $$ \frac{4}{a+3}+\frac{6}{a-5} $$
View solution Problem 52
For the following problems, solve the rational equations. $$ \frac{36}{y^{2}}=1 $$
View solution Problem 52
For the following problems, perform the multiplications and divisions. $$ (y+6)^{3} \div \frac{(y+6)^{2}}{y-6} $$
View solution Problem 52
For the following problems, add or subtract the rational expressions. $$ \frac{x-1}{x-3}+\frac{x+4}{x-4} $$
View solution