Problem 52
Question
For Exercises 51 and \(52,\) use the following information. In an electrical circuit, if two resistors with resistance \(R_{1}\) and \(R_{2}\) are connected in parallel as shown, the relationship between these resistances and the resulting combination resistance \(R\) is \(\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}\). A circuit with two resistors connected in parallel has an effective resistance of 25 ohms. One of the resistors has a resistance of 30 ohms. Find the resistance of the other resistor.
Step-by-Step Solution
Verified Answer
The other resistor has a resistance of approximately 149.25 ohms.
1Step 1: Understand the Formula
The formula given in the problem is for two resistors connected in parallel. It describes the relationship between the individual resistances, \(R_1\) and \(R_2\), and the equivalent resistance, \(R\), of the circuit: \[\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}\]. This formula is key in solving for the unknown resistance.
2Step 2: Identify Known Values
We know the effective resistance \(R\) of the circuit is 25 ohms, and one resistor’s resistance \(R_1\) is 30 ohms. We need to find the value of the second resistor \(R_2\).
3Step 3: Substitute Known Values into the Formula
Substitute the known values into the formula: \[\frac{1}{25} = \frac{1}{30} + \frac{1}{R_2}\].
4Step 4: Solve for the Unknown Resistance
First, find \(\frac{1}{30}\): \(\frac{1}{30} = 0.0333\). Substitute back: \[\frac{1}{25} = 0.0333 + \frac{1}{R_2}\]. Calculate \(\frac{1}{25}\): \(\frac{1}{25} = 0.04\). Set up the equation: \[0.04 = 0.0333 + \frac{1}{R_2}\], which simplifies to \[\frac{1}{R_2} = 0.04 - 0.0333\]. Calculate \(\frac{1}{R_2}\): \(\frac{1}{R_2} = 0.0067\). Invert this to get \(R_2\): \[R_2 = \frac{1}{0.0067} \approx 149.25\] ohms.
Key Concepts
Resistance FormulaCircuit AnalysisElectric Circuits
Resistance Formula
When working with electrical circuits, especially those involving resistors in parallel, understanding the resistance formula is crucial. The formula at the heart of parallel resistors is:\[\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}\]This equation allows for the calculation of the total or equivalent resistance, denoted as \(R\), when two resistors \(R_1\) and \(R_2\) are connected side by side in a parallel configuration. Using the formula involves the following steps:
- Convert the resistance of each resistor into its reciprocal (or the inverse), which means you are doing \(\frac{1}{\text{resistor}}\).
- Add these reciprocals together.
- Convert the sum back into the total equivalent resistance by taking the reciprocal of the result.
Circuit Analysis
Circuit analysis involves understanding how the various components in an electric circuit work together. Specifically, for resistors in parallel, it's important to analyze the roles and impacts of each component on the total circuit. Here's how you can analyze a parallel circuit:
- Identify each resistor and note its resistance value.
- Use the resistance formula to determine how each individual resistor affects the total resistance.
- Consider how changes to one resistor impact the whole circuit, particularly its voltage and current distribution.
Electric Circuits
Electric circuits are pathways through which electric current flows. They are composed of various elements such as resistors, capacitors, and inductors, each with a specific function. In simple terms, a resistor is used to control the flow of electric current in the circuit.
In an electric circuit involving resistors in parallel:
- Each resistor has the same voltage across it but can carry different currents.
- Parallel configurations are beneficial for maintaining voltage consistency across components.
- Such circuits are commonly found in household wiring systems, where multiple appliances share the same voltage level.
Other exercises in this chapter
Problem 52
Find each product, if possible. $$ \left[\begin{array}{rrr}{4} & {-1} & {6} \\ {1} & {5} & {-8}\end{array}\right] \cdot\left[\begin{array}{cc}{1} & {3} \\ {9} &
View solution Problem 52
Find the LCM of each set of polynomials. \(a^{2}-2 a-3, a^{2}-a-6\)
View solution Problem 52
If \(a b=1\) and \(a\) is less than 0 which of the following statements cannot be true? F. \(b\) is negative. G. \(b\) is less than \(a\) H. As \(a\) increases,
View solution Problem 52
Simplify each expression. \(\frac{\frac{5 x^{2}-5 x-30}{45-15 x}}{\frac{6+x-x^{2}}{4 x-12}}\)
View solution