Problem 52
Question
For exercises 49-52, simplify. $$ \frac{m^{3}}{m^{2}+12 m+27}+\frac{27}{m^{2}+12 m+27} $$
Step-by-Step Solution
Verified Answer
\[ \frac{m^2 - 3m + 9}{m + 9} \]
1Step 1: Identify Common Denominator
Notice that both fractions have the same denominator: \[ m^2 + 12m + 27 \].
2Step 2: Combine the Numerators
Since the denominators are the same, combine the numerators: \[ \frac{m^3 + 27}{m^2 + 12m + 27} \]
3Step 3: Factor the Numerator
Factor the numerator, which is a sum of cubes: \[ m^3 + 27 = (m + 3)(m^2 - 3m + 9) \]
4Step 4: Factor the Denominator
Factor the denominator: \[ m^2 + 12m + 27 = (m + 3)(m + 9) \]
5Step 5: Simplify the Expression
Rewrite the expression with the factors and cancel the common factor \ (m + 3): \[ \frac{(m + 3)(m^2 - 3m + 9)}{(m + 3)(m + 9)} \].Canceling out \ (m + 3), we get: \[ \frac{m^2 - 3m + 9}{m + 9} \]
Key Concepts
Common DenominatorSum of CubesFactoring PolynomialsCanceling Common Factors
Common Denominator
To simplify algebraic expressions involving fractions, the first step often involves finding a common denominator. A common denominator is a shared denominator between fractions, which allows us to combine the fractions easily.
In our problem, the given fractions both have:
In our problem, the given fractions both have:
- The same denominator: \b \b
- This checks off the first step and ensures the denominators align perfectly.
Sum of Cubes
The sum of cubes is a special type of polynomial factoring that you need to recognize. Generally, an expression like \( a^3 + b^3 \) can be factored into \( (a + b)(a^2 - ab + b^2) \).
In our problem, the numerator \( m^3 + 27 \) is actually the sum of cubes:
In our problem, the numerator \( m^3 + 27 \) is actually the sum of cubes:
- Identify: \( m \to m \) and \( b = 3 \) since \( 27 = 3^3 \)
- Apply the formula: \( (m + 3)(m^2 - 3m + 9) \)
Factoring Polynomials
Factoring polynomials is another key step in simplifying algebraic expressions. This process involves breaking down a polynomial into simpler 'factor' polynomials whose product is the original polynomial.
Looking at the denominator in our problem: \( m^2 + 12m + 27 \), we proceed by:
Looking at the denominator in our problem: \( m^2 + 12m + 27 \), we proceed by:
- Finding numbers that multiply to 27 and add up to 12. These numbers are 3 and 9
- Expressing the polynomial as: \( (m + 3)(m + 9) \)
Canceling Common Factors
Canceling common factors simplifies fractions. When a numerator and denominator share a common polynomial factor, they can be canceled out.
For our fraction, we have \( \frac{(m + 3)(m^2 - 3m + 9)}{(m + 3)(m + 9)} \):
For our fraction, we have \( \frac{(m + 3)(m^2 - 3m + 9)}{(m + 3)(m + 9)} \):
- The common factor is \( (m + 3) \)
- We cancel it out from both the numerator and the denominator.
Other exercises in this chapter
Problem 51
For exercises 1-66, simplify. $$ \frac{2 c^{2}-13 c-45}{2 c^{2}+13 c+20} $$
View solution Problem 52
For exercises \(35-86\), simplify. $$ \frac{v+1}{6 v-24}-\frac{v}{v-4} $$
View solution Problem 52
For exercises 39-82, simplify. $$ \frac{7 w}{9 p} \div \frac{7 w}{30 p} $$
View solution Problem 52
For exercises 1-66, simplify. $$ \frac{2 w^{2}+9 w+7}{2 w^{2}+13 w+21} $$
View solution