Problem 52
Question
Find the limits in Problems Be sure to check whether you can apply I'Hospital's rule before you evaluate the limit. $$ \lim _{x \rightarrow 0^{+}} \frac{e^{x}}{x} $$
Step-by-Step Solution
Verified Answer
The limit is \( +\infty \).
1Step 1: Identify the Form
Firstly, identify the form of the limit \( \lim_{x \to 0^{+}} \frac{e^x}{x} \). As \( x \to 0^{+} \), the limit takes the form \( \frac{1}{0^{+}} = \infty \), which is not an indeterminate form of \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \), so directly L'Hôpital's rule is not applicable.
2Step 2: Evaluate the Limit Directly
Since the form is not indeterminate, evaluate the limit directly. As \( x \to 0^{+} \), \( e^x \rightarrow e^0 = 1 \). Therefore, the expression becomes \( \frac{1}{0^{+}} \), which indicates that the limit approaches \( +\infty \).
3Step 3: Conclude the Limit
Conclude that \( \lim_{x \to 0^{+}} \frac{e^x}{x} = +\infty \), since the numerator approaches 1 and the denominator approaches 0 from the positive side, indicating a vertical asymptote.
Key Concepts
L'Hôpital's ruleIndeterminate FormsAsymptotes
L'Hôpital's rule
L'Hôpital's rule is an important mathematical tool used to find limits that result in indeterminate forms like \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \). When you encounter these forms, you can apply L'Hôpital's rule to solve them much more easily. Here's how:
- Differentiate the numerator and the denominator of the function separately.
- After differentiating, re-evaluate the limit.
- If the result is still an indeterminate form, you can apply L'Hôpital's rule again.
Indeterminate Forms
Indeterminate forms are expressions in calculus that do not have a clear or immediate limit. These forms can occur when trying to apply limits, leading to a scenario where each component of the function approaches a limit, but the overall limit is not immediately apparent. The most common indeterminate forms are:
- \( \frac{0}{0} \)
- \( \frac{\infty}{\infty} \)
- \( 0 \times \infty \)
- \( \infty - \infty \)
- \( 0^0 \)
- \( 1^\infty \)
- \( \infty^0 \)
Asymptotes
An asymptote is a line that a curve approaches as it heads towards infinity. There are different types of asymptotes, including vertical, horizontal, and oblique. When you evaluate limits, recognizing asymptotes can help determine the behavior of a function as it approaches certain critical points.
- Vertical Asymptotes: These occur when the denominator of a rational function approaches zero, causing the function to go towards infinity, like in our example \( \lim_{x \to 0^{+}} \frac{e^x}{x} = +\infty \).
- Horizontal Asymptotes: Appear when the output of a function approaches a constant value as \( x \) moves towards positive or negative infinity.
- Oblique Asymptotes: Become apparent when a rational function's degree in the numerator is one higher than its degree in the denominator.
Other exercises in this chapter
Problem 51
In Problems 47-58, find the general solution of the differential equation. $$ \frac{d y}{d t}=t(1-t), t \geq 0 $$
View solution Problem 51
Denote the biomass at time \(t\) by \(B(t)\), and assume that \(B(0)=\) 3 and \(|d B / d t| \leq 1\) for all \(t \in[0,3]\). What can you say about \(B(3)\) ?
View solution Problem 52
In Problems 47-58, find the general solution of the differential equation. $$ \frac{d y}{d t}=t^{2}\left(1-t^{2}\right), t \geq 0 $$
View solution Problem 52
Suppose that \(f\) is differentiable for all \(x \in \mathbf{R}\) and, furthermore, that \(f\) satisfies \(f(0)=0\) and \(1 \leq f^{\prime}(x) \leq 2\) for all
View solution