Problem 52
Question
Find the indicated term of each binomial expansion. \((y+4)^{7} ;\) fifth term
Step-by-Step Solution
Verified Answer
The fifth term of the binomial expansion \((y+4)^7\) is \(\boxed{8960y^3}\).
1Step 1: Identify the binomial terms and the term index
From the given expression, we identify:
- \(a = y\)
- \(b = 4\)
- \(n = 7\)
- \(k = 4\)
2Step 2: Use the binomial theorem formula
Now plug the values of \(a\), \(b\), \(n\), and \(k\) into the binomial theorem formula:
\[\binom{n}{k}a^{n-k}b^k = \binom{7}{4}y^{7-4}4^4\]
3Step 3: Calculate the binomial coefficient
Calculate the binomial coefficient using the formula \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\):
\[\binom{7}{4} = \frac{7!}{4!(3)!} = \frac{7\times6\times5}{4\times3\times2} = 35\]
4Step 4: Calculate the y exponent
Subtract \(k\) from \(n\):
\[7 - 4 = 3\]
5Step 5: Calculate the power of 4
Calculate \(4^4\):
\[4^4 = 256\]
6Step 6: Combine the results
Now, combine the results of Step 3, Step 4, and Step 5:
\[35 \cdot y^3 \cdot 256\]
So, the fifth term of the binomial expansion \((y+4)^7\) is \(\boxed{8960y^3}\).
Other exercises in this chapter
Problem 51
Evaluate each series. $$\sum_{i=3}^{6}\left(i^{2}\right)$$
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Find \(S_{8}\) for each arithmetic sequence described below. $$a_{1}=-1, a_{8}=-29$$
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Find the sum of the first four terms of the geometric sequence with \(a_{1}=6\) and \(r=3\)
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Evaluate each series. $$\sum_{i=2}^{7}(i-1)^{2}$$
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