Problem 52
Question
Factor the expression completely. $$ 4 t^{2}-9 s^{2} $$
Step-by-Step Solution
Verified Answer
The expression factors to \((2t-3s)(2t+3s)\).
1Step 1: Identify the Structure
Recognize that the given expression is of the form \( a^2 - b^2 \), which is the difference of squares. In this case, we have \( a = 2t \) and \( b = 3s \), because \( (2t)^2 = 4t^2 \) and \( (3s)^2 = 9s^2 \).
2Step 2: Use the Difference of Squares Formula
Apply the difference of squares formula: \( a^2 - b^2 = (a-b)(a+b) \). Substitute \( a = 2t \) and \( b = 3s \) into the formula to get the factors: \((2t-3s)(2t+3s)\).
3Step 3: Verify Your Solution
Ensure correctness by expanding \((2t-3s)(2t+3s)\) to check if it results back in \(4t^2 - 9s^2\). Using the distributive method, \((2t-3s)(2t+3s) = (2t)^2 - (3s)^2 = 4t^2 - 9s^2\). It matches the original expression, confirming the solution is correct.
Key Concepts
Difference of SquaresAlgebraic ExpressionsPolynomial Equations
Difference of Squares
The difference of squares is a fundamental concept in algebraic expressions. It simplifies certain polynomial equations by breaking them into smaller, more manageable parts. When you have an expression of the form \( a^2 - b^2 \), it is called the difference of squares. This is because you are essentially looking at the subtraction of two perfect square terms.
To factor such an expression, you use the formula:
Using the difference of squares formula simplifies the factoring process and helps you solve polynomial equations more efficiently.
To factor such an expression, you use the formula:
- \( a^2 - b^2 = (a - b)(a + b) \)
Using the difference of squares formula simplifies the factoring process and helps you solve polynomial equations more efficiently.
Algebraic Expressions
Algebraic expressions are mathematical phrases that can include numbers, variables, and operations. They form the building blocks for polynomial equations that you often work with in algebra.
An expression like \( 4t^2 - 9s^2 \) can be seen as an algebraic expression because it involves variables \( t \) and \( s \), coefficients \( 4 \) and \( 9 \), and the subtraction operation.
Here are some important points to consider when dealing with algebraic expressions:
An expression like \( 4t^2 - 9s^2 \) can be seen as an algebraic expression because it involves variables \( t \) and \( s \), coefficients \( 4 \) and \( 9 \), and the subtraction operation.
Here are some important points to consider when dealing with algebraic expressions:
- Identify the terms: Each part of the expression separated by a plus or minus sign is a term. In our example, \( 4t^2 \) and \( 9s^2 \) are terms.
- Simplify the expression: Look for patterns such as the difference of squares to simplify.
- Factor completely: Whenever possible, break down the expression further as in rewriting \( 4t^2 - 9s^2 \) to \( (2t-3s)(2t+3s) \).
Polynomial Equations
Polynomial equations are equations that involve polynomials, which are expressions consisting of variables raised to whole-number exponents and having coefficients. They can be classified based on their degree, which is the highest power of the variable in the equation.
In our example, \( 4t^2 - 9s^2 \) is a polynomial expression, and it can be set equal to zero to form a polynomial equation, \( 4t^2 - 9s^2 = 0 \). Here's how we can approach solving it:
In our example, \( 4t^2 - 9s^2 \) is a polynomial expression, and it can be set equal to zero to form a polynomial equation, \( 4t^2 - 9s^2 = 0 \). Here's how we can approach solving it:
- Use the factored form: From our previous factoring, the expression becomes \((2t-3s)(2t+3s)\).
- Set each factor to zero: This gives the equations \(2t-3s = 0\) and \(2t+3s = 0\).
- Solve for the variable: Solve these equations separately to find the values of \( t \) and \( s \).
Other exercises in this chapter
Problem 52
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