Problem 52
Question
Factor each trinomial completely. See Examples 1 through 7. \(54 a^{2}+39 a b-8 b^{2}\)
Step-by-Step Solution
Verified Answer
The factored form is \((9a + 8b)(6a - b)\).
1Step 1: Identify the form of the trinomial
The given trinomial is in the form of a quadratic expression: \(54a^2 + 39ab - 8b^2\). We need to factor it completely, recognizing it resembles a quadratic expression in terms of \(a\).
2Step 2: Use factoring by grouping
We need to split the middle term \(39ab\) in such a way that the trinomial can be grouped into two binomials. To do this, find two numbers whose product is the coefficient of \(a^2\) and \(b^2\) terms multiplied (\(54 \times -8 = -432\)) and whose sum is \(39\) (the coefficient of \(ab\)). These numbers are \(48\) and \(-9\).
3Step 3: Rewrite the trinomial with grouped terms
Using the numbers \(48\) and \(-9\), rewrite the trinomial: \[54a^2 + 48ab - 9ab - 8b^2\]. This allows us to factor by grouping the terms.
4Step 4: Factor by grouping
Group the terms into two pairs: \((54a^2 + 48ab) + (-9ab - 8b^2)\). Factor out the greatest common factor from each pair: \(6a(9a + 8b) - b(9a + 8b)\).
5Step 5: Complete the grouping factorization
Notice \(9a + 8b\) is a common factor. Factor it out: \((9a + 8b)(6a - b)\). This gives us the completely factored form of the trinomial.
Key Concepts
Quadratic ExpressionsFactoring by GroupingGreatest Common Factor
Quadratic Expressions
Quadratic expressions are polynomials of degree two, typically having the form \(ax^2 + bx + c\). The expression we started with, \(54a^2 + 39ab - 8b^2\), is a quadratic in terms of \(a\), because of the \(a^2\) term. Quadratics can have various forms or disguises, such as the one in our exercise involving the term \(ab\), which can make them seem more complex. However, recognizing it as a quadratic is crucial.
Key features of quadratic expressions include:
Key features of quadratic expressions include:
- The presence of a squared term, which establishes it as a second-degree polynomial.
- The possibility of having single, double, or even triple variables, which influences how we factorize or solve them.
Factoring by Grouping
Factoring by grouping is a clever technique where we manipulate an expression to create common factors that can be grouped into pairs of terms. In our situation, the quadratic trinomial \(54a^2 + 39ab - 8b^2\) required us to split the middle term \(39ab\) into two terms, which made the expression easier to handle.
The process works as follows:
The process works as follows:
- First, we need numbers that multiply to give the product of the leading coefficient and the constant term. Here, \(54\times -8 = -432\).
- Then, we find two numbers that add up to the middle coefficient, \(39\). In this case, those numbers are \(48\) and \(-9\).
- Rewrite the middle term using these two numbers, resulting in \(54a^2 + 48ab - 9ab - 8b^2\).
- Group into pairs: \((54a^2 + 48ab) + (-9ab - 8b^2)\) and factor them separately.
Greatest Common Factor
The greatest common factor (GCF) is the largest factor that divides two or more numbers. When factoring expressions, obtaining the GCF is a crucial initial step to simplify and eventually solve the polynomial effectively. In the context of our exercise, finding the GCF allows one to see how the trinomial can be split conveniently.
To find the GCF in a grouped expression:
To find the GCF in a grouped expression:
- Look at the coefficients and variables independently, identifying the highest number that evenly divides all coefficients within the group.
- Identify the smallest power of the variable present in each term.
- Factor out this GCF from each group. For example, from \(54a^2 + 48ab\), the GCF is \(6a\), leading to the term \(6a(9a + 8b)\).
- For \(-9ab - 8b^2\), the GCF is \(-b\), simplifying it to \(-b(9a + 8b)\).
Other exercises in this chapter
Problem 52
Factor out the GCF from each polynomial. $$ q\left(b^{3}-5\right)+\left(b^{3}-5\right) $$
View solution Problem 52
Factor each trinomial completely. Some of these trinomials contain a greatest common factor (other than 1). Don't forget to factor out the GCF first. $$ x^{2}-4
View solution Problem 52
Solve each equation. $$ 12 x^{2}+7 x-12=0 $$
View solution Problem 53
Factor each completely. $$ 4 x^{2}+4 x+1-z^{2} $$
View solution