Problem 52
Question
\(\bullet\) A beam of light strikes a sheet of glass at an angle of \(57.0^{\circ}\) with the normal in air. You observe that red light makes an angle of \(38.1^{\circ}\) with the normal in the glass, while violet light makes a \(36.7^{\circ}\) angle. (a) What are the indexes of refraction of this glass for these colors of light? (b) What are the speeds of red and violet light in the glass?
Step-by-Step Solution
Verified Answer
The indexes of refraction are 1.357 for red and 1.406 for violet. Speeds are approximately 2.21 x 10⁸ m/s for red light and 2.13 x 10⁸ m/s for violet light in glass.
1Step 1: Determine the Index of Refraction for Red Light
We will use Snell's law to find the index of refraction for red light. Snell's law states \(n_1 \sin \theta_1 = n_2 \sin \theta_2\). Here, the air's index of refraction \(n_1 = 1\), and the angle in air \(\theta_1 = 57.0^{\circ}\). The angle in the glass for red light \(\theta_2 = 38.1^{\circ}\). So, \(1 \cdot \sin(57.0^{\circ}) = n_2 \cdot \sin(38.1^{\circ})\). We solve for \(n_2\) (red):\[n_{red} = \frac{\sin(57.0^{\circ})}{\sin(38.1^{\circ})} = \frac{0.8387}{0.6181} \approx 1.357\]
2Step 2: Determine the Index of Refraction for Violet Light
Similarly, using Snell’s law for violet light, with \(\theta_2 = 36.7^{\circ}\), we calculate:\[n_2 \cdot \sin(36.7^{\circ}) = 1 \cdot \sin(57.0^{\circ})\]Thus, the index of refraction for violet light is:\[n_{violet} = \frac{\sin(57.0^{\circ})}{\sin(36.7^{\circ})} = \frac{0.8387}{0.5964} \approx 1.406\]
3Step 3: Calculate the Speed of Red Light in the Glass
The speed of light in a medium is given by \(v = \frac{c}{n}\), where \(c\) is the speed of light in a vacuum \((3 \times 10^8\, \text{m/s})\), and \(n\) is the index of refraction.For red light:\[v_{red} = \frac{3 \times 10^8}{1.357} \approx 2.21 \times 10^8\, \text{m/s}\]
4Step 4: Calculate the Speed of Violet Light in the Glass
Using the same formula for violet light:\[v_{violet} = \frac{3 \times 10^8}{1.406} \approx 2.13 \times 10^8\, \text{m/s}\]
Key Concepts
Index of RefractionSpeed of LightOpticsAngle of Incidence
Index of Refraction
The index of refraction is a fundamental concept in understanding how light behaves when it travels from one medium to another. Essentially, this index measures how much light bends, or refracts, as it enters a different medium. This bending happens due to a change in the speed of light.
The index of refraction, denoted as \( n \), is defined by the equation:
A higher index means light slows down more and bends more sharply. This is why different colors, such as red and violet, have different indexes in the same medium like glass. The difference in refraction is also why prisms can create rainbows by splitting white light into its component colors.
The index of refraction, denoted as \( n \), is defined by the equation:
- \( n = \frac{c}{v} \)
A higher index means light slows down more and bends more sharply. This is why different colors, such as red and violet, have different indexes in the same medium like glass. The difference in refraction is also why prisms can create rainbows by splitting white light into its component colors.
Speed of Light
The speed of light is a constant in a vacuum, approximately \( 3 \, \times \, 10^8 \, \text{m/s} \). However, when light travels through a medium, like glass or water, its speed decreases. This reduction in speed compared to a vacuum directly relates to the medium's index of refraction.
To find the speed of light in any medium, use the formula:
For instance, in glass, red light travels faster than violet light because the red light has a lower index of refraction. Hence, the speed at which light travels in a medium and its refraction index are tightly intertwined.
To find the speed of light in any medium, use the formula:
- \( v = \frac{c}{n} \)
For instance, in glass, red light travels faster than violet light because the red light has a lower index of refraction. Hence, the speed at which light travels in a medium and its refraction index are tightly intertwined.
Optics
Optics is the study of light, its behavior, and properties, and how it interacts with different materials. It involves understanding phenomena like reflection, refraction, and diffraction. Optics is paramount in designing various devices such as eyeglasses, cameras, and telescopes, which rely on controlling light.
In optics, Snell's Law is critical for explaining how light refracts at the boundary between two media. It is mathematically represented by:
By mastering the principles of optics and Snell’s Law, we gain insights into numerous real-world applications, from fiber optic communications to corrective eyewear, enhancing our ability to manipulate light for practical uses.
In optics, Snell's Law is critical for explaining how light refracts at the boundary between two media. It is mathematically represented by:
- \( n_1 \sin \theta_1 = n_2 \sin \theta_2 \)
By mastering the principles of optics and Snell’s Law, we gain insights into numerous real-world applications, from fiber optic communications to corrective eyewear, enhancing our ability to manipulate light for practical uses.
Angle of Incidence
The angle of incidence is vital in determining how light behaves when it hits a surface or another medium. It is the angle formed between the incoming light ray and an imaginary line perpendicular to the surface called the normal.
The significance of the angle of incidence is that it affects the angle at which light will refract, or bend, upon entering a new medium. Snell's Law utilizes this angle to calculate the refraction, helping us understand how lenses and various optical phenomena work.
The significance of the angle of incidence is that it affects the angle at which light will refract, or bend, upon entering a new medium. Snell's Law utilizes this angle to calculate the refraction, helping us understand how lenses and various optical phenomena work.
- For example, if light hits glass at an angle, like in our exercise where the angle of incidence is \( 57.0^{\circ} \), different colors of light are refracted at different angles due to their unique indices of refraction.
Other exercises in this chapter
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