Problem 52
Question
\(0.1914 \mathrm{~g}\) of an organic acid is dissolved in about 20 \(\mathrm{mL}\) of water \(25 \mathrm{~mL}\) of \(0.12 \mathrm{~N} \mathrm{NaOH}\) is required for the complete neutralization of the acid solution. The equivalent weight of the acid is (a) \(63.8\) (b) \(64.0\) (c) \(65.8\) (d) \(66.2\)
Step-by-Step Solution
Verified Answer
The equivalent weight of the acid is 63.8, option (a).
1Step 1: Understand the Given Problem
This problem involves determining the equivalent weight of an unknown organic acid using a titration method where a known volume and normality of sodium hydroxide (NaOH) is used to neutralize a given mass of the acid.
2Step 2: Identify the Relevant Formula
To find the equivalent weight of the acid, we use the formula: Equivalent weight of acid = (Mass of acid) / (Equivalent of NaOH used).
3Step 3: Calculate Equivalents of NaOH
We calculate the equivalents of NaOH used during the titration: Equivalents = Normality \( \times \) Volume in liters, hence \(0.12\, \text{N} \times 0.025\, \text{L} = 0.003\, \text{equivalents}\).
4Step 4: Solve for Equivalent Weight of the Acid
Using the formula from Step 2, substitute the values: Equivalent weight of acid = \( \frac{0.1914\, \text{g}}{0.003} = 63.8 \, \text{g/equiv}\).
5Step 5: Determine the Correct Option
Compare the calculated equivalent weight of \(63.8\, \text{g/equiv}\) to the options provided: (a) \(63.8\), (b) \(64.0\), (c) \(65.8\), (d) \(66.2\). The correct choice for the equivalent weight is option (a) \(63.8\).
Key Concepts
Understanding Organic Acid TitrationThe Role of Normality in ChemistryUnderstanding Neutralization Reactions
Understanding Organic Acid Titration
Titration is a method used to determine the concentration of a substance in a solution by reacting it with a solution of known concentration, called a titrant. In organic acid titration, an acid with an unknown concentration is reacted with a base of known concentration.
This titration process helps in determining the equivalent weight of the acid.
During titration:
This process helps in accurately calculating the equivalent weight, especially essential when dealing with organic acids whose chemical structure might be unknown or complex.
During titration:
- A known volume of the base (like NaOH) is added gradually to the acid solution.
- The addition continues until the reaction reaches its endpoint, signifying complete neutralization.
This process helps in accurately calculating the equivalent weight, especially essential when dealing with organic acids whose chemical structure might be unknown or complex.
The Role of Normality in Chemistry
Normality (N) is a measure of concentration equivalent to molarity but adjusted for the reactive capacity of the solute. Unlike molarity, which focuses solely on the number of moles of solute per liter of solution, normality considers the number of equivalents per liter.
In the context of acid-base reactions, like the one seen in titration, normality helps account for the number of hydrogen ions (protons) that each molecule of an acid can donate. Similarly, it reflects the capacity of a base to neutralize hydrogen ions.
For example:
In the context of acid-base reactions, like the one seen in titration, normality helps account for the number of hydrogen ions (protons) that each molecule of an acid can donate. Similarly, it reflects the capacity of a base to neutralize hydrogen ions.
For example:
- A 0.12 N NaOH solution means there are 0.12 equivalents of base per liter, illustrating how many protons it can neutralize.
- This comes into play in calculating the equivalents used during titration, which is crucial for determining the equivalent weight of an acid.
Understanding Neutralization Reactions
Neutralization is a chemical reaction between an acid and a base that results in the formation of water and a salt. It occurs when the number of moles of H\(^+\) ions from the acid equals the number of moles of OH\(^-\) ions provided by the base.
This reaction type is crucial in titrations, forming the basis for neutralizing acids with bases like sodium hydroxide. For instance, when NaOH (a strong base) neutralizes an acid, the reaction can be illustrated as:
Neutralization helps us find the equivalent points where the titrant neutralizes the analyte. This endpoint's measurement allows the calculation of equivalent weights, offering insights into the amount of substance involved in the reaction.
Thus, understanding this principle is crucial for determining specific properties like equivalent weight in acid-base titrations.
This reaction type is crucial in titrations, forming the basis for neutralizing acids with bases like sodium hydroxide. For instance, when NaOH (a strong base) neutralizes an acid, the reaction can be illustrated as:
- Acid + Base → Salt + Water
- Example: HCl + NaOH → NaCl + H\(_2\)O
Neutralization helps us find the equivalent points where the titrant neutralizes the analyte. This endpoint's measurement allows the calculation of equivalent weights, offering insights into the amount of substance involved in the reaction.
Thus, understanding this principle is crucial for determining specific properties like equivalent weight in acid-base titrations.
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