Problem 51
Question
Write a structural formula for the coordination compound \(\left[\mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2} \mathrm{I}_{2}\right],\) and give the coordination number for the central \(\mathrm{Cr}^{2+}\) ion.
Step-by-Step Solution
Verified Answer
The coordination number of \( \mathrm{Cr}^{2+} \) in the compound is 6.
1Step 1: Understand the components
The complex given is \( \left[ \mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2} \mathrm{I}_{2}\right] \). Here, \( \mathrm{Cr}^{2+} \) is the central metal ion, \( \mathrm{en} \) stands for ethylenediamine, a bidentate ligand, \( \mathrm{NH}_{3} \) is ammonia, and \( \mathrm{I} \) is iodide. The coordination compound consists of ligands \( \mathrm{en} \), \( \mathrm{NH}_{3} \), and \( \mathrm{I}^{-} \) bonding with the central metal ion \( \mathrm{Cr}^{2+} \).
2Step 2: Assign the coordination number
The coordination number of a metal in a complex is the total number of ligand attachment points. Ethylenediamine (\( \mathrm{en} \)) is a bidentate ligand, meaning it forms two bonds, contributing 2 coordination points. \( \mathrm{NH}_{3} \) is a monodentate ligand with each \( \mathrm{NH}_{3} \) contributing one coordination point, totaling 2 from \( (\mathrm{NH}_{3})_{2} \). \( \mathrm{I}^{-} \) is also a monodentate ligand, contributing 1 coordination point per atom, totaling 2 from \( \mathrm{I}_{2} \). Therefore, the coordination number is the sum: \( 2 + 2 + 2 = 6 \).
3Step 3: Draw the structural formula
In the structural formula, the central \( \mathrm{Cr}^{2+} \) is connected to each of its ligands based on the determined coordination points. Start by connecting one bidentate \( \mathrm{en} \) (which connects at two sites). Then attach two \( \mathrm{NH}_{3} \) molecules (one connection each), and finally, connect two \( \mathrm{I}^{-} \) ions (one connection each). This ensures the correct coordination number (6) and the structural integrity of the complex.
Key Concepts
Understanding the Coordination NumberExploring Bidentate LigandsStructural Formula of Coordination CompoundsDecoding Metal-Ligand Bonding
Understanding the Coordination Number
In coordination chemistry, the coordination number is a crucial concept as it defines the number of ligand attachment points around a metal ion. For instance, in the compound \( \left[ \mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2} \mathrm{I}_{2}\right] \), we have Chromium \( \mathrm{Cr}^{2+} \) as the central metal ion. The coordination number here is calculated by counting the total attachment points provided by all ligands surrounding the metal ion.
- Ethylenediamine (\( \mathrm{en} \)) is a bidentate ligand, meaning it can bond at two points, contributing 2 coordination points.
- Ammonia (\( \mathrm{NH}_{3} \)) is a monodentate ligand, providing 1 point each, summed up to 2 points for two \( \mathrm{NH}_{3} \) molecules.
- Iodide (\( \mathrm{I}^{-} \)) is also monodentate, with one iodide contributing 1 point, totaling to 2 points for two \( \mathrm{I}^{-} \).
Exploring Bidentate Ligands
Bidentate ligands are fascinating because they form two bonds with a central metal atom or ion, contributing significantly to the stability and geometry of coordination complexes.
- Ethylenediamine (\( \mathrm{en} \)) is a classic example of a bidentate ligand. It possesses two donor atoms which can each form a coordinate bond with the metal center.
- This dual bonding ability allows bidentate ligands to "chelate" the metal, forming a more stable ring-like structure due to the chelate effect. This enhances the stability of the coordination compound compared to those with monodentate ligands.
Structural Formula of Coordination Compounds
Creating a structural formula in coordination chemistry involves illustrating the connections between the central metal ion and its surrounding ligands to reflect physical arrangements and bonding.
For the compound \( \left[ \mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2} \mathrm{I}_{2}\right] \), the central \( \mathrm{Cr}^{2+} \) ion is encircled by:
For the compound \( \left[ \mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2} \mathrm{I}_{2}\right] \), the central \( \mathrm{Cr}^{2+} \) ion is encircled by:
- A bidentate ligand \( \mathrm{en} \), connected at two sites, forming a (nearly) closed loop with \( \mathrm{Cr}^{2+} \).
- Two \( \mathrm{NH}_{3} \) molecules, each connecting at one point, represented by simple lines radiating from the chromium ion.
- Two \( \mathrm{I}^{-} \) ions, each making a single connection line to the metal center.
Decoding Metal-Ligand Bonding
Metal-ligand bonding is at the heart of coordination chemistry, and it accounts for the way in which ligands attach to a central metal ion, such as \( \mathrm{Cr}^{2+} \) in our example compound. These bonds form through a mechanism known as coordinate or dative bonding.
- In a coordinate bond, the ligand donates a pair of electrons to the metal ion which can accept those electrons due to its nature.
- Bidentate ligands like ethylenediamine can use two pairs of lone electrons to form coordinate bonds, effectively surrounding the metal ion and stabilizing the complex.
- Monodentate ligands such as \( \mathrm{NH}_{3} \) or \( \mathrm{I}^{-} \) involve a single pair of electrons to form a bond with the metal center.
Other exercises in this chapter
Problem 49
Give the coordination number of the central metal ion in (a) \(\left[\mathrm{Pt}(\mathrm{en})_{2}\right]^{2+}\) (b) \(\left[\mathrm{Cu}\left(\mathrm{C}_{2} \mat
View solution Problem 50
Give the coordination number of the central metal ion in (a) \(\left[\mathrm{Ni}(\mathrm{cn})_{2}\left(\mathrm{NH}_{3}\right)_{2}\right]^{2+}\). (b) \(\left[\ma
View solution Problem 52
Give the formula of each of these coordination compounds formed with \(\mathrm{Pt}^{2+}\) (a) Two ammonia molecules and two bromide ions (b) One ethylenediamine
View solution Problem 53
Give the charge on the central metal ion in each of these. (a) \(\left[\mathrm{VCl}_{6}\right]^{4-}\) (b) \(\left[\mathrm{Sc}\left(\mathrm{H}_{2} \mathrm{O}\rig
View solution