Problem 51
Question
What product is formed by mixing the solution of \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) with the solution of \(\mathrm{FeCl}_{2} ?\) (a) ferric ferrocyanide (b) ferri ferricyanide (c) ferro ferricyanide (d) none of these
Step-by-Step Solution
Verified Answer
The product formed is ferric ferrocyanide, answer (a).
1Step 1: Write the Chemical Equations
First, identify the reactants involved in the chemical process: potassium ferrocyanide, \( \mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] \), and iron(II) chloride, \( \mathrm{FeCl}_{2} \). The typical reaction between these involves the exchange of ions.
2Step 2: Identify Ion Exchange
Both reactants are known to undergo an ion exchange, where iron ions form a complex compound with the ferrocyanide ions, producing a precipitate.
3Step 3: Determine Product Formation
The reaction typically forms an insoluble compound known as iron(III) ferrocyanide, commonly referred to as Prussian Blue, with the formula \( \mathrm{Fe}_{4}[\mathrm{Fe}(\mathrm{CN})_{6}]_{3} \). This compound is synonymous with ferric ferrocyanide.
4Step 4: Confirm Product Identity
The formation of a blue-colored precipitate when these solutions are mixed confirms the identity of the product as ferric ferrocyanide. This matches the description choice (a) in the options provided.
Key Concepts
Ionic ExchangeComplex CompoundsInsoluble CompoundsPrussian Blue
Ionic Exchange
Ionic exchange is a fundamental concept in chemistry where ions are swapped between two reactants. In the exercise provided, potassium ferrocyanide and iron(II) chloride undergo such a process.
- When these two compounds mix, their ions rearrange themselves to form a new substance.
- This rearrangement involves iron ions trading places, which significantly changes the resulting compounds.
Complex Compounds
Complex compounds are chemical structures that consist of a central metal atom bonded to surrounding molecules or ions. These structures are often more stable and have unique properties.
In our exercise, iron ions form a complex compound with ferrocyanide ions.
In our exercise, iron ions form a complex compound with ferrocyanide ions.
- The central metal atom here is iron (Fe), and the surrounding ions are cyanides (CN).
- Such compounds can have intriguing appearances and behaviors due to their intricate structures.
Insoluble Compounds
Insoluble compounds are those that do not dissolve well in water. Their formation is typically indicated by a solid precipitate in the reaction.
- In the described chemical reaction, the result is iron(III) ferrocyanide, which is insoluble, forming a solid precipitate.
- This solid appears as a distinct phase separate from the liquid solution, emphasizing its insolubility.
Prussian Blue
Prussian Blue is an iconic blue pigment formed through a fascinating chemical process. In this reaction, when potassium ferrocyanide meets iron(II) chloride, Prussian Blue materializes as a precipitate.
- Known scientifically as iron(III) ferrocyanide, it boasts a complex structure with a vibrant blue hue.
- This compound has been used historically in paints, inks, and even medical applications due to its color and properties.
Other exercises in this chapter
Problem 49
Which of the following combines with \(\mathrm{Fe}(\mathrm{II})\) ions to form a brown complex? (a) \(\mathrm{N}_{2} \mathrm{O}_{3}\) (b) \(\mathrm{N}_{2} \math
View solution Problem 50
Perssian blue is formed when (a) ammonium sulphate reacts with \(\mathrm{FeCl}_{3}\) (b) ferrous sulphate reacts with \(\mathrm{FeCl}_{3}\) (c) ferrous ammonium
View solution Problem 53
Nitrates of all metals are (a) unstable (b) coloured (c) insoluble in water (d) soluble in water
View solution Problem 54
The composition of golden spangles is (a) \(\mathrm{PbI}_{2}\) (b) \(\mathrm{BaCrO}_{4}\) (c) \(\mathrm{As}_{2} \mathrm{~S}_{3}\) (d) \(\mathrm{PbCrO}_{4}\)
View solution