Problem 51
Question
What is the hybridization state of the central atom in the conjugate base of \(\mathrm{NH}_{4}^{+}\)ion? (a) sp (b) \(\mathrm{sp}^{3}\) (c) \(\mathrm{sp}^{3}\) (d) \(\mathrm{dsp}^{2}\)
Step-by-Step Solution
Verified Answer
The hybridization state of the central atom in \(\mathrm{NH}_3\) is \(\mathrm{sp}^3\).
1Step 1: Determine the Conjugate Base
The conjugate base of the ammonium ion \(\mathrm{NH}_4^+\) is the species formed after the donation of a proton (\(\mathrm{H}^+\)). When \(\mathrm{NH}_4^+\) loses a proton, it becomes \(\mathrm{NH}_3\) (ammonia).
2Step 2: Analyze the Central Atom's Geometry
The central atom in \(\mathrm{NH}_3\) is nitrogen. In \(\mathrm{NH}_3\), three hydrogen atoms are bonded to nitrogen, and there is one lone pair of electrons on the nitrogen. This makes the geometry a trigonal pyramidal shape.
3Step 3: Determine the Hybridization
The trigonal pyramidal geometry in \(\mathrm{NH}_3\) suggests that the nitrogen uses \(\mathrm{sp}^3\) hybrid orbitals to form bonds. This hybridization involves one \(\mathrm{s}\) orbital and three \(\mathrm{p}\) orbitals combining to form four equivalent \(\mathrm{sp}^3\) hybrid orbitals.
Key Concepts
Conjugate BaseAmmonium IonTrigonal Pyramidal Geometry
Conjugate Base
A conjugate base is the result of losing a proton (\(H^+\!\)) from an acid. In this context, the acid in question is the ammonium ion \(NH_4^+\!\), which is quite common in chemistry. When an acid donates a proton, the species that remains is known as its conjugate base. For the ammonium ion \(NH_4^+\!\), the loss of a proton directly forms ammonia, represented chemically as \(NH_3\!\).
- The key change here is the removal of one hydrogen ion (proton), shifting the atom's balance and forming a neutral \(NH_3\!\) molecule.
- This process transforms the positively charged ammonium ion into a neutral ammonia molecule.
Ammonium Ion
The ammonium ion is a positively charged, polyatomic ion with the formula \(NH_4^+\!\). It plays a crucial role in many biological and chemical systems. It is the product of ammonia accepting a proton.
- This ion is commonly found in nature, mainly in soil, fertilizers, and as a vital component in the nitrogen cycle.
- Chemically, \(NH_4^+\!\) is formed by the protonation of ammonia \(NH_3\!\).
- The addition of the proton leads to a tetrahedral geometry where the nitrogen is surrounded by four hydrogen atoms.
Trigonal Pyramidal Geometry
Trigonal pyramidal geometry is a common geometrical arrangement observed in certain molecular structures where a central atom is connected to three peripheral atoms, with one lone pair of electrons occupying one of the positions that would make up a tetrahedral geometry. In the case of \(NH_3\!\), or ammonia, the nitrogen atom is in the center, with three hydrogen atoms surrounding it.
- The presence of a lone pair of electrons on nitrogen pushes the hydrogen atoms closer together.
- This lone pair creates a repulsion that alters the bond angles, reducing them from the ideal tetrahedral angle of 109.5° to about 107°.
- Thus, ammonia takes on a trigonal pyramidal shape rather than a perfect tetrahedral shape.
Other exercises in this chapter
Problem 49
The most polar bond is (a) \(\mathrm{C}-\mathrm{F}\) (b) \(\mathrm{C}-\mathrm{O}\) (c) \(\mathrm{C}-\mathrm{Br}\) (d) \(\mathrm{C}-\mathrm{S}\)
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Which one of the following is the correct set with reference to molecular formula, hybridization of central atom and shape of the molecule? (a) \(\mathrm{CO}_{2
View solution Problem 52
Which one of the following molecules contains both ionic and covalent bonds? (a) \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) (b) \(\mathrm{K}_{2} \mathrm{SO}_{4}\) (c)
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Which one of the following is a correct set with respect to molecule, hybridization and shape? (a) \(\mathrm{BeCl}_{2}, \mathrm{sp}^{2}\), linear (b) \(\mathrm{
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