Problem 51
Question
Use the sum-of-two-cubes or the difference-of-two-cubes pattern to factor each of the following. $$1-27 a^{3}$$
Step-by-Step Solution
Verified Answer
The factored form is \((1 - 3a)(1 + 3a + 9a^2)\).
1Step 1: Recognize the Difference of Cubes Pattern
The given expression is a difference: \(1 - 27a^3\). This can be expressed in the form \(x^3 - y^3\), where \(x = 1\) and \(y = 3a\). Recognizing this pattern is crucial for factoring the expression properly using the difference of cubes formula.
2Step 2: Recall the Difference of Cubes Formula
The difference of cubes formula states that \(x^3 - y^3 = (x - y)(x^2 + xy + y^2)\). This will be used to factor the expression once we have identified \(x\) and \(y\).
3Step 3: Substitute Values into the Formula
Substitute \(x = 1\) and \(y = 3a\) into the difference of cubes formula. This gives us:\[1 - (3a)^3 = (1 - 3a)(1^2 + 1 \cdot 3a + (3a)^2)\]
4Step 4: Simplify the Factored Expression
Simplify the terms inside the parentheses after substitution:\[(1 - 3a)(1 + 3a + 9a^2)\] Now, combine the terms in the second parentheses to complete the factoring process.
Key Concepts
Difference of CubesAlgebraic ExpressionsPolynomial Identities
Difference of Cubes
The "difference of cubes" is a technique used in algebra to factor expressions like the one given in the exercise. When you encounter a problem such as \(1 - 27a^3\), it's helpful to notice that it fits the pattern of \(x^3 - y^3\). In this case, identify \(x = 1\) (since \(1^3 = 1\)) and \(y = 3a\) (since \((3a)^3 = 27a^3\)). This recognition allows you to use a special factoring formula efficiently.
The difference of cubes can be broken down using the formula:
The difference of cubes can be broken down using the formula:
- \(x^3 - y^3 = (x - y)(x^2 + xy + y^2)\)
Algebraic Expressions
Algebraic expressions consist of numbers, variables, and operations combined in a meaningful way. In simple terms, they are mathematical phrases that can represent real-world quantities. For example, \(1 - 27a^3\) is an algebraic expression that consists of a constant term "1" and the term "27a^3," where 27 is a coefficient, and "a" is a variable raised to the power of three.
Recognizing types of algebraic expressions, like the one above, is key to navigating more complex algebraic tasks. Important components of these expressions include:
Recognizing types of algebraic expressions, like the one above, is key to navigating more complex algebraic tasks. Important components of these expressions include:
- Coefficients: Numbers that are multiplied by the variables.
- Variables: Symbols like \(a\) that can represent unknown values.
- Exponents: Numbers that tell you how many times to multiply the variable by itself.
Polynomial Identities
Polynomial identities are like algebraic shortcuts. They offer pre-set formulas that help you factor or simplify polynomials efficiently. Knowing these identities is extremely beneficial, particularly in algebra, since they save time and effort, allowing you to focus on more critical problem-solving steps.
The difference of cubes identity is one such shortcut used in the original exercise. The full identity is:
The difference of cubes identity is one such shortcut used in the original exercise. The full identity is:
- \(x^3 - y^3 = (x - y)(x^2 + xy + y^2)\)
Other exercises in this chapter
Problem 51
Solve each equation. You will need to use the factoring techniques that we discussed throughout this chapter. $$(3 x-1)^{2}-16=0$$
View solution Problem 51
Factor completely each of the polynomials and indicate any that are not factorable using integers. $$x^{4}-9 x^{2}+8$$
View solution Problem 51
Factor by grouping. $$3 a x-3 b x-a y+b y$$
View solution Problem 51
Find each indicated product. Remember the shortcut for multiplying binomials and the other special patterns we discussed in this section. $$(5 x-2 a)(5 x+2 a)$$
View solution