Problem 51
Question
The volume of a quantity of gas at 1.00 atm is compressed from \(3.25 \mathrm{L}\) to \(2.24 \mathrm{L} .\) What is the final pressure of the gas if there is no change in temperature?
Step-by-Step Solution
Verified Answer
Answer: The final pressure of the gas is approximately 1.45 atm.
1Step 1: List the given information and write down the formula for Boyle's Law
We are given the following information:
Initial pressure, P1 = 1.00 atm
Initial volume, V1 = 3.25 L
Final volume, V2 = 2.24 L
We are asked to find the final pressure, P2.
The formula for Boyle's Law is:
P1 x V1 = P2 x V2
2Step 2: Rearrange the formula to find the final pressure
We want to solve for the final pressure, P2. Therefore, we need to rearrange Boyle's Law formula:
P2 = (P1 x V1) / V2
3Step 3: Plug in the given values and solve for the final pressure
Now, we can substitute the given values into the formula:
P2 = (1.00 atm x 3.25 L) / 2.24 L
P2 = 3.25 atm/L
4Step 4: Calculate the final pressure
Now, we can calculate the final pressure:
P2 = (3.25 atm) / 2.24 L
P2 ≈ 1.45 atm
The final pressure of the gas after it has been compressed and its volume has decreased to 2.24 L is approximately 1.45 atm.
Key Concepts
Pressure calculationGas lawsVolume and pressure relationship
Pressure calculation
To find the pressure of a gas after compression or expansion, we use specific mathematical formulas. One of these is derived from Boyle's Law, which deals with changes in pressure as volume changes at a constant temperature. In this exercise, we calculated the final pressure of a gas after its volume shifted from 3.25 L to 2.24 L, given an initial pressure of 1.00 atm. The desired quantity, the final pressure \( P_2 \), was found using the equation:
\[ P_2 = \frac{P_1 \times V_1}{V_2} \]
To solve, simply plug the known values into this equation. Math manipulation remains straightforward:
\[ P_2 = \frac{P_1 \times V_1}{V_2} \]
To solve, simply plug the known values into this equation. Math manipulation remains straightforward:
- First, multiply the initial pressure \( P_1 \) by the initial volume \( V_1 \).
- Then divide that product by the final volume \( V_2 \).
- In this problem, the final pressure came out to approximately 1.45 atm.
Gas laws
Gas laws are fundamental to understanding how gases behave under different conditions of temperature, volume, and pressure. An important gas law, Boyle's Law, articulates that if temperature remains constant during a change in volume, the pressure of a gas will adjust inversely.
Key ideas when dealing with gas laws include:
Key ideas when dealing with gas laws include:
- Boyle's Law: Focuses on pressure and volume at constant temperature.
- Charles's Law: Deals with temperature and volume, keeping pressure constant.
- Avogadro's Law: Relates the volume of gas to the number of molecules.
Volume and pressure relationship
Understanding the volume and pressure relationship is pivotal in predicting what will happen to a gas when its surroundings change. Boyle's Law aptly illustrates that when the volume of a gas decreases, its pressure increases, provided the temperature remains consistent.
The relationship hinges on a simple inverse proportion:
The relationship hinges on a simple inverse proportion:
- If volume decreases, pressure increases, keeping product \( P \times V \) constant.
- This inverse relationship explains why pressing down on a sealed syringe results in a higher internal pressure.
- The functioning of our respiratory system where lungs operate under changing pressures.
- Engineering calculations for pressure vessels and storage tanks.
Other exercises in this chapter
Problem 48
Explain Boyle's law using kinetic molecular theory.
View solution Problem 49
A hot-air balloonist is rising too fast for her liking. Should she increase or decrease the temperature of the gas in the balloon?
View solution Problem 52
The pressure on a sample of an ideal gas is increased from \(715 \mathrm{mmHg}\) to 3.55 atm at constant temperature. If the initial volume of the gas is \(485
View solution Problem 53
A \(4.66 \mathrm{L}\) sample of gas is warmed from \(273 \mathrm{K}\) to a final temperature of \(398 \mathrm{K}\). Assuming no change in pressure, what is the
View solution