Problem 51
Question
Simplify the radical expression. $$ \frac{\sqrt{5}}{3-\sqrt{5}} $$
Step-by-Step Solution
Verified Answer
The simplified form of the expression is \(\frac{3\sqrt{5} + 5} {4}\)
1Step 1: Identify and rewrite the expression
After understanding the problem, the radical expression can be written as \(\frac{\sqrt{5}}{3-\sqrt{5}}\)
2Step 2: Rationalize the denominator
Rationalizing the denominator involves multiplying both numerator and denominator by the conjugate of the denominator. Here, the conjugate of \(3-\sqrt{5}\) is \(3+\sqrt{5}\). Thus the expression becomes \(\frac{\sqrt{5}(3+\sqrt{5})} {(3-\sqrt{5})(3+\sqrt{5})}\)
3Step 3: Expand the terms in the numerator and denominator
For the numerator: \(\sqrt{5}*3 + \sqrt{5}*\sqrt{5}\) which can be simplified to \(3\sqrt{5} + 5\). For the denominator, it's a perfect square of a binomial which solves to \(3^2 - (\sqrt{5})^2\), which simplifies to \(9-5\)
4Step 4: Simplify the expression
The expression now becomes \(\frac{3\sqrt{5} + 5} {4}\)
Key Concepts
Radical ExpressionsConjugatesSimplifying Fractions
Radical Expressions
A radical expression includes a square root (or other roots), and in our problem, involves the square root of 5. Understanding radical expressions is key to solving problems where we need to simplify or manipulate square roots.
A square root is a factor of a number that, when multiplied by itself, gives the original number. For instance, in \(\sqrt{5}\), the expression represents the number which, when squared, equals 5.
Working with radicals involves several operations:
A square root is a factor of a number that, when multiplied by itself, gives the original number. For instance, in \(\sqrt{5}\), the expression represents the number which, when squared, equals 5.
Working with radicals involves several operations:
- Adding or subtracting radicals requires them to have the same radicand and index, which is similar to combining like terms in algebra.
- Multiplying and dividing radicals is often simpler, as different radicands can be multiplied or divided, and then simplified if possible.
Conjugates
Conjugates are an essential concept in rationalizing the denominator, especially with expressions involving square roots. In mathematics, the conjugate of a binomial is derived by changing the sign between two terms. For example, the conjugate of \(a - b\) is \(a + b\).
When dealing with a denominator like \(3-\sqrt{5}\), we use its conjugate, \(3+\sqrt{5}\), to multiply the numerator and denominator of the fraction. The multiplication with its conjugate helps, because:
When dealing with a denominator like \(3-\sqrt{5}\), we use its conjugate, \(3+\sqrt{5}\), to multiply the numerator and denominator of the fraction. The multiplication with its conjugate helps, because:
- The product of a binomial and its conjugate yields a difference of squares, eliminating the radical in the denominator.
- It results in a rational number, making the fraction easier to work with.
Simplifying Fractions
Simplifying fractions is a fundamental process in mathematics, allowing us to express a fraction in its simplest form. Doing this involves reducing a fraction to its lowest terms or ensuring there are no remaining radicals or complex numbers in the denominator.
In our current problem, after multiplying by the conjugate, we reach a simplified form: \(\frac{3\sqrt{5} + 5}{4}\). Here, every part of the expression has been simplified:
In our current problem, after multiplying by the conjugate, we reach a simplified form: \(\frac{3\sqrt{5} + 5}{4}\). Here, every part of the expression has been simplified:
- The numerator involves straightforward arithmetic with radicals, resulting in terms like \(3\sqrt{5}\) and 5.
- The denominator becomes a straightforward whole number, as the square root is effectively removed through conjugate multiplication.
Other exercises in this chapter
Problem 51
Solve the quadratic equation. $$ x^{2}+20 x+2=0 $$
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Solve the equation. Write the solutions as integers if possible. Otherwise, write them as radical expressions. $$ 4 x^{2}-144=0 $$
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Find the domain of the function. Then sketch its graph and find the range. $$y=5 \sqrt{x}-2$$
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Solve the equation. Check for extraneous solutions. $$ x=\sqrt{2 x+3} $$
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