Problem 51
Question
Prove that every function \(f\) that has an inverse function \(g\) is one-to-one. I Hint: The proof of the Round-Trip Theorem on page 223 shows that \(f\) and \(g\) have the round-trip properties; use Exercise \(50(\mathrm{a}) .]\)
Step-by-Step Solution
Verified Answer
Question: Prove that every function with an inverse function is one-to-one.
Answer: To prove that a function with an inverse function is one-to-one, we showed that for any \(x_1\) and \(x_2\) in the domain of the function, if \(f(x_1) = f(x_2)\) then \(x_1 = x_2\). We used the round-trip properties of the function and its inverse to show this result. It means that the function assigns a unique output to each input, and thus, the function is one-to-one.
1Step 1: Define the given functions and their properties
Let \(f\) be a function with an inverse function \(g\). This means that:
1. \(g(f(x)) = x\) for all \(x\) in the domain of \(f\)
2. \(f(g(y)) = y\) for all \(y\) in the domain of \(g\)
2Step 2: Assume \(f(x_1) = f(x_2)\) for some \(x_1\) and \(x_2\) in the domain of \(f\)
Let's assume that there are two values, \(x_1\) and \(x_2\), in the domain of \(f\) such that \(f(x_1) = f(x_2)\). We want to show that \(x_1 = x_2\).
3Step 3: Apply the inverse function \(g\) to both sides of the equation \(f(x_1) = f(x_2)\)
Apply the inverse function \(g\) to both sides of the equation:
\(g(f(x_1)) = g(f(x_2))\)
4Step 4: Use the round-trip property of \(f\) and \(g\) to simplify the equation
Now, we can use the round-trip property of \(f\) and \(g\), which states that \(g(f(x)) = x\) for all \(x\) in the domain of \(f\). Thus:
\(g(f(x_1)) = x_1\)
\(g(f(x_2)) = x_2\)
5Step 5: Conclude that \(x_1 = x_2\)
Since \(g(f(x_1)) = x_1\) and \(g(f(x_2)) = x_2\), and we previously found that \(g(f(x_1)) = g(f(x_2))\), we can conclude that:
\(x_1 = x_2\)
6Step 6: State that the function \(f\) is one-to-one
Since we have shown that for any \(x_1\) and \(x_2\) in the domain of \(f\), if \(f(x_1) = f(x_2)\) then \(x_1 = x_2\), we can conclude that the function \(f\) is one-to-one.
Key Concepts
One-to-One FunctionRound-Trip TheoremFunction PropertiesProof Techniques
One-to-One Function
Understanding the concept of a one-to-one function is essential when discussing inverses. A function is considered one-to-one (injective) if different inputs always lead to different outputs. In simpler terms, if you plug two different values into the function, you will get two different results. This property is central to the idea of functions having inverses because only one-to-one functions can have inverses that are also functions.
- If function \( f \) satisfies \( f(x_1) = f(x_2) \), then it must be that \( x_1 = x_2 \).
- This means no two distinct points in the domain map to the same point in the codomain.
Round-Trip Theorem
The Round-Trip Theorem is a stepping stone in understanding the nature of inverse functions. It states that if a function \( f \) has an inverse \( g \), then composing them in specific directions will always return you to your starting point.
- In symbols, \( g(f(x)) = x \) for all \( x \) in \( f \)'s domain and \( f(g(y)) = y \) for all \( y \) in \( g \)'s domain.
- This effectively means moving around the function world in a loop: from a point \( x \) through \( f \) to \( g \), and back to \( x \) again.
Function Properties
Functions have various properties that help us understand their behavior and characteristics. Some critical properties include:
- Domain: The set of all possible inputs for the function.
- Codomain: The set of all possible outputs.
- Injective (One-to-One): Different inputs produce different outputs.
- Surjective (Onto): Every element in the codomain is mapped by at least one element in the domain.
- Bijective (One-to-One Correspondence): Both injective and surjective, meaning every element in one set is paired with exactly one element in the other.
Proof Techniques
When proving mathematical properties, particularly in functional analysis, several methods and techniques can be employed. A direct proof is the most straightforward, where you start with known facts or assumptions and logically deduce the conclusion.
- The solution provided follows a direct proof strategy. It begins with the given that \( f \) has an inverse \( g \), and uses their round-trip properties.
- Assume \( f(x_1) = f(x_2) \) and apply the inverse \( g \) to show \( x_1 = x_2 \).
Other exercises in this chapter
Problem 51
Sketch the graph of a function \(f\) that satisfies these five conditions: (i) \(f(-1)=2\) (ii) \(f(x) \geq 2\) when \(x\) is in the interval \(\left(-1, \frac{
View solution Problem 51
Example \(11(b)\) showed how we create a table of values for a function when you get to choose all the values of the inputs. The technique presented does not wo
View solution Problem 52
Determine the domain of the function according to the usual convention. $$h(x)=\frac{\sqrt{x-1}}{x^{2}-1}$$
View solution Problem 52
True or false: If a function has an inverse, then its inverse has an inverse. Justify your answer.
View solution