Problem 51
Question
Let \(x \in[0,1]\) be the incidence of a certain disease in the general population. For example, if 132 persons out of 100,000 have the disease, then \(x=0.00132\). Suppose that a screening procedure for the disease results in false positives \(1 \%\) of the time and in false negatives \(2 \%\) of the time. Then, according to Bayes's law, $$ P(x)=\frac{0.98 x}{0.97 x+0.01} $$ is the probability that a person who tests positive for the disease actually has the disease. Graph \(P\) in an appropriate window. What does this graph tell you about the value of routinely using this screening procedure if the disease is rare?
Step-by-Step Solution
Verified Answer
The graph shows that for rare diseases, the screening test may give many false positives, questioning its efficacy.
1Step 1: Interpret the Given Information
We have a function given by Bayes's law: \[P(x) = \frac{0.98x}{0.97x + 0.01},\]where \(x\) represents the incidence of a disease in the general population and ranges from 0 to 1.
2Step 2: Analyze the Graph
We need to graph this function to understand its behavior for small values of \(x\) (as the disease is rare). Start by plotting the function for \(x\) values between 0 and 0.05, since this range is appropriate for very low incidences in the population.
3Step 3: Identify Calculation Tools
To obtain the graph, you can use graphing software like Desmos or a graphing calculator. Input the function \( P(x) = \frac{0.98x}{0.97x + 0.01} \) and set the \(x\)-axis ranging from 0 to 0.05 and the \(y\)-axis from 0 to 1.
4Step 4: Observing the Graph
Notice how as \(x\) approaches 0, the probability \(P(x)\) also approaches 0. This means that if the disease incidence in the population is extremely low, the probability that a person who tests positive actually has the disease is also very low.
5Step 5: Conclusion from the Graph
The graph shows that for rare diseases, the probability of having the disease given a positive result is low primarily due to the low prevalence of the disease and small error rates. This implies that routinely using this screening might result in many false positives.
Key Concepts
False PositivesFalse NegativesDisease IncidenceGraphing Functions
False Positives
False positives in medical screening occur when a test indicates that a person has a disease, but in reality, they do not. In the example, the screening procedure results in false positives 1% of the time. This means that out of 100 tests conducted on people without the disease, 1 test will incorrectly suggest that the person has the disease.
Understanding false positives is crucial because they can lead to unnecessary stress, further medical tests, and increased healthcare costs. To minimize the impact of false positives:
Understanding false positives is crucial because they can lead to unnecessary stress, further medical tests, and increased healthcare costs. To minimize the impact of false positives:
- Healthcare strategies must include confirmatory tests.
- Doctors should communicate the possibility of false positives to patients.
- Efforts to improve test accuracy should be prioritized.
False Negatives
False negatives are another important aspect to consider in medical testing. They occur when a test fails to detect a disease that is actually present. In our exercise, the test has a false negative rate of 2%. This means that for every 100 people who truly have the disease, 2 may receive a result indicating they are disease-free.
False negatives can be more dangerous than false positives, especially for serious conditions, as they may delay critical treatment. To address false negatives, healthcare practitioners should:
False negatives can be more dangerous than false positives, especially for serious conditions, as they may delay critical treatment. To address false negatives, healthcare practitioners should:
- Utilize a combination of tests to cross-verify results.
- Monitor patients with symptoms closely, even after a negative test result.
- Seek improvements in both test technology and methodologies.
Disease Incidence
Disease incidence refers to the proportion of a population that is affected by a particular disease at a given time. In this scenario, the incidence is denoted by the variable \(x\), ranging from 0 to 1. For instance, if 132 out of 100,000 people have a disease, the incidence would be \(x=0.00132\).
Understanding disease incidence is important because it affects the probability calculations used in Bayes's Theorem. Low disease incidence, as in rare diseases, can drastically reduce the probability that a person actually has the disease, despite a positive test result. When considering screening for rare diseases, it's essential to:
Understanding disease incidence is important because it affects the probability calculations used in Bayes's Theorem. Low disease incidence, as in rare diseases, can drastically reduce the probability that a person actually has the disease, despite a positive test result. When considering screening for rare diseases, it's essential to:
- Weigh the benefits of early detection against the risks of numerous false positives.
- Understand that low incidence impacts test reliability and real-world outcomes.
- Design healthcare policies that reflect these statistical considerations to optimize patient care.
Graphing Functions
Graphing functions like the one used in Bayes's Theorem can offer valuable insights into how probabilities change with varying disease incidences. In this exercise, the function is \(P(x) = \frac{0.98x}{0.97x + 0.01}\), which helps us determine the probability that a positive test result means someone actually has the disease.
To effectively graph this:
To effectively graph this:
- Use a graphing tool or calculator to plot the range of \(x\) from 0 to 0.05, given the low incidence of the disease.
- Observe the behavior of the function, especially as \(x\) approaches 0, where \(P(x)\) also approaches 0.
- Identify any trends or asymptotes that may reflect real-world implications of the test accuracy.
Other exercises in this chapter
Problem 51
Suppose that \(A\) and \(B\) are constants. Use the Addition Formula for the sine to find an amplitude \(C\) and a phase shift \(\phi\) (both in terms of \(A\)
View solution Problem 51
Which of the equations are circles? Which are not? Give precise reasons for your answers. \(5 x^{2}+5 y^{2}=2 x-3 y+6\)
View solution Problem 51
If the set is given with absolute value signs, then write it without absolute value signs. If it is given without absolute value signs, then write it using abso
View solution Problem 52
Describe the curve that is the graph of the given parametric equations. \(x=1 /\left(1+t^{2}\right), y=1+t^{2}\)
View solution