Problem 51
Question
Indicate the hybridization of the central atom in (a) \(\mathrm{H}_{2} \mathrm{~S}\), (b) \(\mathrm{SeF}_{6}\) (c) \(\mathrm{P}(\mathrm{OH})_{3},\) (d) \(\mathrm{AlI}_{3} .\)
Step-by-Step Solution
Verified Answer
(a) sp3, (b) sp3d2, (c) sp3, (d) sp2.
1Step 1: Analyze the Central Atom
Identify the central atom for each compound: (a) Sulfur in H2S, (b) Selenium in SeF6, (c) Phosphorus in P(OH)3, (d) Aluminum in AlI3.
2Step 2: Determine Electron Groups Around the Central Atom
Count the number of bonded atoms and lone pairs around the central atom for each molecule:
(a) In H2S, sulfur has 2 bonds and 2 lone pairs, totaling 4 electron groups.
(b) In SeF6, selenium has 6 bonds and 0 lone pairs, totaling 6 electron groups.
(c) In P(OH)3, phosphorus has 3 bonds and 1 lone pair, totaling 4 electron groups.
(d) In AlI3, aluminum has 3 bonds and 0 lone pairs, totaling 3 electron groups.
3Step 3: Assign Hybridization Based on Electron Groups
Use the total number of electron groups to determine hybridization:
(a) For 4 electron groups (H2S), the hybridization is sp3.
(b) For 6 electron groups (SeF6), the hybridization is sp3d2.
(c) For 4 electron groups (P(OH)3), the hybridization is sp3.
(d) For 3 electron groups (AlI3), the hybridization is sp2.
Key Concepts
Central AtomElectron GroupsBonded AtomsLone Pairs
Central Atom
In molecular structures, the central atom plays a crucial role in determining the shape and hybridization of the molecule. The central atom is typically the one with the lowest electronegativity and is often capable of forming multiple bonds. It is the atom around which other atoms or groups are arranged.
For the given compounds:
For the given compounds:
- In \(\mathrm{H}_{2}\mathrm{S}\), sulfur (S) is the central atom.
- In \(\mathrm{SeF}_{6}\), selenium (Se) is the central atom.
- In \(\mathrm{P(OH)}_{3}\), phosphorus (P) is the central atom.
- In \(\mathrm{AlI}_{3}\), aluminum (Al) is the central atom.
Electron Groups
Electron groups around a central atom are crucial for determining hybridization. The concept of electron groups includes both bonded atoms and lone pairs.
Electron groups are:
Electron groups are:
- Bonded atoms, which are counted as one electron group each.
- Lone pairs, which also count as one electron group each.
- In \(\mathrm{H}_{2}\mathrm{S}\), sulfur has 4 electron groups (2 bonded atoms and 2 lone pairs).
- In \(\mathrm{SeF}_{6}\), selenium has 6 electron groups (6 bonded atoms and no lone pairs).
- In \(\mathrm{P(OH)}_{3}\), phosphorus has 4 electron groups (3 bonded atoms and 1 lone pair).
- In \(\mathrm{AlI}_{3}\), aluminum has 3 electron groups (3 bonded atoms and no lone pairs).
Bonded Atoms
Bonded atoms refer to the atoms that are directly linked to the central atom in a molecule. In the context of hybridization, each bonded atom contributes an electron group.
For the molecules:
For the molecules:
- In \(\mathrm{H}_{2}\mathrm{S}\), sulfur is bonded to 2 hydrogen atoms.
- In \(\mathrm{SeF}_{6}\), selenium is bonded to 6 fluorine atoms.
- In \(\mathrm{P(OH)}_{3}\), phosphorus is bonded to 3 hydroxyl (OH) groups.
- In \(\mathrm{AlI}_{3}\), aluminum is bonded to 3 iodine atoms.
Lone Pairs
Lone pairs consist of electrons that do not participate in bonding, yet they occupy space around the central atom. These lone pairs count as individual electron groups and play a significant role in determining hybridization and molecular shape.
In our examples:
In our examples:
- In \(\mathrm{H}_{2}\mathrm{S}\), sulfur possesses 2 lone pairs.
- In \(\mathrm{SeF}_{6}\), selenium has no lone pairs.
- In \(\mathrm{P(OH)}_{3}\), phosphorus comprises 1 lone pair.
- In \(\mathrm{AlI}_{3}\), aluminum has no lone pairs.
Other exercises in this chapter
Problem 48
How would you expect the extent of overlap of the bonding atomic orbitals to vary in the series IF, ICl, IBr, and \(\mathrm{I}_{2}\) ? Explain your answer.
View solution Problem 49
Consider the molecule \(\mathrm{BF}_{3} .\) (a) What is the electron configuration of an isolated B atom? (b) What is the electron configuration of an isolated
View solution Problem 52
What is the hybridization of the central atom in (a) \(\mathrm{PBr}_{5}\), (b) \(\mathrm{CH}_{2} \mathrm{O},(\mathbf{c}) \mathrm{O}_{3},\) (d) \(\mathrm{NO}_{2}
View solution Problem 54
(a) Which geometry and central atom hybridization would you expect in the series \(\mathrm{BH}_{4}^{-}, \mathrm{CH}_{4}, \mathrm{NH}_{4}^{+} ?(\mathbf{b})\) Wha
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