Problem 51
Question
In Exercises \(51-58,\) determine whether each equation is an identity, a conditional equation, or an inconsistent equation. $$ 4(x-7)=4 x-28 $$
Step-by-Step Solution
Verified Answer
The given equation is an identity because it holds true for all real numbers.
1Step 1: Distribute the multiplication
Begin by distributing the multiplication on the left hand side to eliminate parentheses: \(4x - 28\). Now, the equation looks like \(4x - 28 = 4x - 28\).
2Step 2: Analyze the equation
From Step 1, you can observe that both sides of the equation are identical. This means that no matter what real number value we substitute for \(x\), both sides of the equation will remain equal.
Key Concepts
Conditional EquationsInconsistent EquationsAlgebraic Equations
Conditional Equations
A conditional equation is an equation that holds true only for specific values of the variable involved. It's like a puzzle that only fits when you have the right piece. In mathematical terms, a conditional equation is true only for certain values of its variable, and false for others.
For example, consider the equation \(x + 2 = 5\). This equation is considered conditional because it will only be true when \(x = 3\). For any other value of \(x\), the equation won't balance, making it false.
For example, consider the equation \(x + 2 = 5\). This equation is considered conditional because it will only be true when \(x = 3\). For any other value of \(x\), the equation won't balance, making it false.
- If you replace \(x\) with 3, both sides become equal: \(3 + 2 = 5\).
- Unlike identity equations, conditional equations only work for specific numbers.
Inconsistent Equations
Inconsistent equations pose quite a challenge, as these are equations that are never true. No matter what value you assign to the variable, the equation will not hold. It's like trying to fit a square peg into a round hole - it just won't work.
These equations have no solution because they set up an equality that cannot be satisfied. A simple example is the equation \(x + 2 = x + 3\). No value for \(x\) will make the two sides equal.
These equations have no solution because they set up an equality that cannot be satisfied. A simple example is the equation \(x + 2 = x + 3\). No value for \(x\) will make the two sides equal.
- For \(x + 2\), even if \(x\) is 0, 1, or any other number, the right side \(x + 3\) will always be greater by 1.
- Inconsistent equations often highlight contradictions or unresolvable conflicts in algebraic expressions.
Algebraic Equations
Algebraic equations are vital components of algebra, representing statements where two expressions are set equal to one another. They typically include one or more variables, constants, and mathematical operations. Algebraic equations come in different forms:
Algebraic equations form the backbone of algebra, offering powerful tools to model and solve real-world problems. They are an essential part of mathematics, helping us explore relationships and make predictions based on given data.
- Linear equations, such as \(2x + 3 = 7\), have one variable raised to the first power.
- Quadratic equations, like \(x^2 - 4x + 4 = 0\), have variables raised to the second power.
- Polynomial equations may include higher powers, such as \(x^3 + 2x^2 - x - 5 = 0\).
Algebraic equations form the backbone of algebra, offering powerful tools to model and solve real-world problems. They are an essential part of mathematics, helping us explore relationships and make predictions based on given data.
Other exercises in this chapter
Problem 51
Solve each equation in Exercises \(39-54\) by completing the square. $$ 4 x^{2}-4 x-1=0 $$
View solution Problem 51
Solve each inequality in Exercises 49-56 and graph the solution set on a number line. Express the solution set using interval notation. $$-3 \leq x-2
View solution Problem 52
Explain the error in Exercises \(51-52\) \((\sqrt{-9})^{2}=\sqrt{-9} \cdot \sqrt{-9}=\sqrt{81}=9\)
View solution Problem 52
Use the position formula $$ s=-16 t^{2}+v_{0} t+s_{0} $$ \(\left(v_{0}=\text { initial velocity, } s_{0}=\text { initial position, } t=\text { time }\right)\) t
View solution