Problem 51
Question
In Exercises 49-58, find a mathematical model for the verbal statement. \(y\) varies inversely as the square of \(x\).
Step-by-Step Solution
Verified Answer
The mathematical model for the statement 'y varies inversely as the square of x' is \(y = k / x^2\).
1Step 1: Understand the formula for inverse variation
When \(y\) varies inversely as \(x\), it can be represented by the equation \(y = k / x\) where \(k\) is the constant of variation. However, in this case, \(y\) varies inversely as the square of \(x\), so the equation will be \(y = k / x^2\).
2Step 2: Formulate the equation
Since no specific values are given for \(y\) and \(x\) to find \(k\), the mathematical model for the statement 'y varies inversely as the square of \(x\)' becomes \(y = k / x^2\).
Key Concepts
Variation EquationsConstant of VariationMathematical Modeling
Variation Equations
Variation equations describe the relationship between two variables. There are different types of variation equations, including direct, inverse, joint, and combined variation.
For an inverse variation equation, one variable increases while the other decreases. In simpler terms, when one gets larger, the other gets smaller. For example, imagine a seesaw: if one side goes up, the other goes down. To express this mathematically, we use the equation format:
For an inverse variation equation, one variable increases while the other decreases. In simpler terms, when one gets larger, the other gets smaller. For example, imagine a seesaw: if one side goes up, the other goes down. To express this mathematically, we use the equation format:
- General inverse variation: \( y = \frac{k}{x} \)
- Specific to our problem, where \(y\) varies inversely with the square of \(x\): \( y = \frac{k}{x^2} \)
Constant of Variation
The constant of variation, represented by \(k\), is a key component in variation equations. It acts like a bridge between the variables \(x\) and \(y\). While \(x\) and \(y\) change with respect to each other, \(k\) remains fixed. This fixed nature allows us to write dependable equations.
In the case of inverse variation, \(k\) is calculated by multiplying one variable by the inverse (or reciprocal) of the other variable. So when \(y = \frac{k}{x^2} \), you could rearrange to find \(k\) if values for \(y\) and \(x\) were provided:
In the case of inverse variation, \(k\) is calculated by multiplying one variable by the inverse (or reciprocal) of the other variable. So when \(y = \frac{k}{x^2} \), you could rearrange to find \(k\) if values for \(y\) and \(x\) were provided:
- \(k = y \times x^2\)
Mathematical Modeling
Mathematical modeling involves crafting equations that represent real-world phenomena. It's a method for predicting behavior or outcomes of different systems. This process translates verbal descriptions into mathematical terms, allowing us to solve problems efficiently.In this exercise, the statement "\(y\) varies inversely as the square of \(x\)" is transformed into an equation. This equation, \(y = \frac{k}{x^2}\), represents a real-world scenario where understanding how \(y\) changes in relation to \(x\) is crucial.
By developing such models, we can:
By developing such models, we can:
- Predict how changes in \(x\) affect \(y\) without measuring \(y\) repeatedly.
- Use the model to compare different systems or scenarios logically.
Other exercises in this chapter
Problem 50
In Exercises 45-56, identify any intercepts and test for symmetry. Then sketch the graph of the equation. \( y = x^3 - 1 \)
View solution Problem 50
In Exercises 47-56, (a) plot the points, (b) find the distance between the points, and (c) find the midpoint of the line segment joining the points. \( (-7, -4)
View solution Problem 51
In Exercises 49-62, (a) find the inverse function of \(f\) (b) graph both \(f\) and \(f^{-1}\) on the same set of coordinate axes, (c) describe the relationship
View solution Problem 51
In Exercises 25-54, \(g\) is related to one of the parent functions described in Section 1.6. (a) Identify the parent function \(f\). (b) Describe the sequence
View solution