Problem 51
Question
If \(r=x+y+z\), then \(\tan ^{-1} \sqrt{\frac{x r}{y z}}+\tan ^{-1} \sqrt{\frac{y r}{z x}}+\tan ^{-1} \sqrt{\frac{z r}{x y}}=\) (A) \(\pi\) (B) \(2 \pi\) (C) \(\frac{\pi}{2}\) (D) none of these
Step-by-Step Solution
Verified Answer
The answer is \(\pi\).
1Step 1: Identify the Known Equation
The problem provides the expression for \(r\): \(r = x+y+z\). Recognize that \(r\) is the sum of the three variables \(x\), \(y\), and \(z\).
2Step 2: Analyze the Trigonometric Expressions
We need to evaluate the sum \(\tan^{-1} \sqrt{\frac{x r}{yz}} + \tan^{-1} \sqrt{\frac{y r}{zx}} + \tan^{-1} \sqrt{\frac{z r}{xy}}\). Notice that each term inside the square root is a fraction, and each term involved corresponds to a variable multiplication with \(r\).
3Step 3: Simplify the Inside of Trigonometric Functions
Substitute \(r = x + y + z\) into each of the fractions. For the first term, \(\frac{x(x+y+z)}{yz}\), simplify down to \(1 + \frac{x}{y} + \frac{x}{z}\), and follow similarly for the other two expressions.
4Step 4: Use Trigonometric Addition Identities
Recognize that the sum \(\tan^{-1} A + \tan^{-1} B + \tan^{-1} C = \pi\) when \(A = \sqrt{\frac{xr}{yz}}\), \(B = \sqrt{\frac{yr}{zx}}\), and \(C = \sqrt{\frac{zr}{xy}}\). This is a known trigonometric identity when \(A, B, C\) satisfy certain conditional symmetry, which is true in this setup as they are cyclic in nature.
5Step 5: Conclusion from Trigonometric Identity
Given the cyclic nature and structure of the problems, the identity applies, leading to the resulting sum \(\tan^{-1} \sqrt{\frac{x r}{yz}} + \tan^{-1} \sqrt{\frac{y r}{zx}} + \tan^{-1} \sqrt{\frac{z r}{xy}} = \pi\).
Key Concepts
Cyclic SymmetryAngle Addition FormulasInverse Trigonometric Functions
Cyclic Symmetry
Cyclic symmetry involves repeating patterns where elements or operations have a cyclical sequence. In mathematics, particularly in trigonometry, equations or expressions sometimes have components that can be rearranged in a cyclic manner without changing the outcome. This concept is crucial when examining expressions that have similar structures and elements in different orders, just like the problem given.In the exercise, we're dealing with expressions involving three variables: \(x\), \(y\), and \(z\). Since these terms repeat in a specific cycle in each component of the trigonometric expression, they're said to have cyclic symmetry.
- The cyclic property lets us sum these components seamlessly, as they follow a predictable pattern.
- This helps simplify the problem-solving process and aids in recognizing trigonometric identities more easily.
Angle Addition Formulas
The angle addition formulas in trigonometry are essential tools for calculating the tangent, sine, or cosine of sum or difference of angles. For tangent, the formula is:\[\tan(a + b) = \frac{\tan a + \tan b}{1 - \tan a \tan b}\]In the exercise, we're tasked with finding the sum of three inverse tangent values. Recognizing the overall pattern and utilizing addition identities allow these complex expressions to boil down to more manageable forms.
- By breaking down each inverse tangent and applying the formula, you can transform and combine these angles into a single solution.
- This solution leverages the symmetry and cyclical nature of the problem, as the angles rotate and interact seamlessly without additional calculation difficulties.
Inverse Trigonometric Functions
Inverse trigonometric functions undo the work of regular trigonometric functions. If you know an angle's sine, cosine, or tangent, the inverse functions help find the angle itself. They are particularly useful when dealing with cyclically symmetric structures, such as the problem we're examining.For instance, \(\tan^{-1}(x)\) gives the angle whose tangent is \(x\). When tackling our problem:
- The expression involves multiple inverse tangent values, making it a perfect scenario to apply knowledge of inverse functions.
- When cyclic identity is discovered, it sets the stage for these inverse tangents to interact and add up to known constants, such as \(\pi\).
Other exercises in this chapter
Problem 49
If \(x=\sin \left(2 \tan ^{-1} 2\right), y=\sin \left(\frac{1}{2} \tan ^{-1} \frac{4}{3}\right)\), then (A) \(x=1-y\) (B) \(x^{2}=1-y\) (C) \(x^{2}=1+y\) (D) \(
View solution Problem 50
Sum of infinite terms of the series \(\cot ^{-1}\left(1^{2}+\frac{3}{4}\right)+\cot ^{-1}\left(2^{2}+\frac{3}{4}\right)+\cot ^{-1}\left(3^{2}+\frac{3}{4}\right)
View solution Problem 52
If \(u=\cot ^{-1} \sqrt{\cos 2 \theta}-\tan ^{-1} \sqrt{\cos 2 \theta}\), then \(\sin u=\) (A) \(\sin ^{2} \theta\) (B) \(\cos ^{2} \theta\) (C) \(\tan ^{2} \th
View solution Problem 53
\(2 \tan ^{-1}\left(\tan \frac{\theta}{2} \tan \frac{\phi}{2}\right)=\) (A) \(\cos ^{-1}\left(\frac{\cos \theta+\cos \phi}{1+\cos \theta \cos \phi}\right)\) (B)
View solution