Problem 51
Question
If \(\left\\{a_{n}\right\\}\) and \(\left\\{b_{n}\right\\}\) both diverge, does it follow that \(\left\\{a_{n}+b_{n}\right\\}\) diverges?
Step-by-Step Solution
Verified Answer
No, divergent sequences can be combined to form a convergent sequence.
1Step 1: Understanding Divergence
The sequences \( \{a_n\} \) and \( \{b_n\} \) are given to be divergent. This means neither sequence converges to a specific limit. Divergence could imply they tend toward infinity, negative infinity, or oscillate without settling.
2Step 2: Exploring Sum of Divergent Sequences
Consider what happens if we add two divergent sequences. For example, cumulative divergence could result in convergence (e.g., adding positively and negatively divergent sequences might result in a bounded and convergent sequence).
3Step 3: Example Counterexample with Oscillating Sequences
Suppose \( \{a_n\} = (-1)^n \) and \( \{b_n\} = (-1)^{n+1} \). Both sequences diverge due to oscillation between -1 and 1. Now consider the sequence \( \{a_n + b_n\} \), which yields \(((-1)^n + (-1)^{n+1}) = 0\) for all \( n \). The sequence \( \{a_n + b_n\} \) is constant at 0, showing convergence.
Key Concepts
Divergent SequencesSequence ConvergenceOscillating Sequences
Divergent Sequences
Divergent sequences are fascinating. These are sequences where the terms do not settle down to a single number as you continue adding more terms. In other words, a divergent sequence does not approach a specific limit.
There are a few ways a sequence might diverge:
There are a few ways a sequence might diverge:
- It may increase or decrease without bound, heading towards infinity or negative infinity.
- It may oscillate, never settling into a steady pattern or limit.
Sequence Convergence
Sequence convergence is a condition where a sequence approaches a certain number as more terms are added. Convergent sequences tend to become more predictable and less erratic.
For a sequence \( \{a_n\} \) to be considered convergent, it must approach a number \( L \) such thatthe difference between \( a_n \) and \( L \) becomes extremely small as \( n \) becomes large.
In simple terms, convergent sequences "settle down" to a specific value.
For a sequence \( \{a_n\} \) to be considered convergent, it must approach a number \( L \) such thatthe difference between \( a_n \) and \( L \) becomes extremely small as \( n \) becomes large.
In simple terms, convergent sequences "settle down" to a specific value.
- This behavior contrasts the unpredictability of divergent sequences.
- Mathematically, we say that \( \lim_{n \to \infty} a_n = L \).
Oscillating Sequences
Oscillating sequences are a specific type of divergent sequence. These sequences alternate between values instead of trending towards infinity or negative infinity.
An oscillating sequence can best be exemplified by the sequence \( \{a_n\} = (-1)^n \), where the terms flip between -1 and 1 as \( n \) increases. This sequence never settles to one number and thus diverges.
An oscillating sequence can best be exemplified by the sequence \( \{a_n\} = (-1)^n \), where the terms flip between -1 and 1 as \( n \) increases. This sequence never settles to one number and thus diverges.
- Oscillating sequences often appear in mathematical proofs and real-world phenomena, particularly those involving cyclic behavior.
- The regular pattern may seem manageable, yet it does not lead to a single limit.
Other exercises in this chapter
Problem 50
Find the sum of the series $$ \sum_{k=1}^{\infty} \frac{2^{k}}{\left(2^{k+1}-1\right)\left(2^{k}-1\right)} $$
View solution Problem 50
Prove that if \(\left\\{a_{n}\right\\}\) converges and \(\left\\{b_{n}\right\\}\) diverges then \(\left\\{a_{n}+b_{n}\right\\}\) diverges.
View solution Problem 52
A famous sequence \(\left\\{f_{n}\right\\}\), called the Fibonacci Sequence after Leonardo Fibonacci, who introduced it around A.D. 1200 , is defined by the rec
View solution Problem 54
If an object of rest mass \(m_{0}\) has velocity \(v\), then (according to the theory of relativity) its mass \(m\) is given by \(m=\) \(m_{0} / \sqrt{1-v^{2} /
View solution