Problem 51
Question
Hydrogenation of benzoyl chloride in the presence of \(\mathrm{Pd}\) and \(\mathrm{BaSO}_{4}\) gives (a) benzyl alcohol (b) benzaldehyde (c) benzoic acid (d) phenol
Step-by-Step Solution
Verified Answer
The answer is (b) benzaldehyde.
1Step 1: Understanding the Reaction
The problem asks about the product of the hydrogenation of benzoyl chloride using \( \mathrm{Pd} \) and \( \mathrm{BaSO}_{4} \), known as the Rosenmund reduction. This is a catalytic hydrogenation process that converts acyl chlorides to aldehydes.
2Step 2: Identifying the Reaction Reagents
In this reaction, the reagents used are palladium (\( \mathrm{Pd} \)) as the hydrogenation catalyst, and barium sulfate (\( \mathrm{BaSO}_{4} \)) which is used as a surface to disperse the \( \mathrm{Pd} \) catalyst.
3Step 3: Recognizing the Product Formation
During the Rosenmund reduction, the benzoyl chloride is reduced to its corresponding aldehyde. Thus, benzoyl chloride (\( \mathrm{C_6H_5COCl} \)) will be converted to benzaldehyde (\( \mathrm{C_6H_5CHO} \)).
4Step 4: Choosing the Correct Option
The product benzaldehyde corresponds to option (b). Therefore, the correct answer is option (b) benzaldehyde.
Key Concepts
Catalytic HydrogenationBenzoyl ChlorideBenzaldehydePalladium Catalyst
Catalytic Hydrogenation
Catalytic hydrogenation is a crucial process in organic chemistry that involves the addition of hydrogen to compounds with the aid of a catalyst. This process is widely used to reduce multiple bonds like carbon-carbon double bonds (alkenes) or carbon-oxygen double bonds (carbonyls). By doing so, it helps transform unsaturated compounds into saturated ones.
This reaction is particularly important because it enables the conversion of various functional groups, ultimately transforming the structure and properties of the original compound.
This reaction is particularly important because it enables the conversion of various functional groups, ultimately transforming the structure and properties of the original compound.
- Catalysts commonly used in hydrogenation include metals like palladium, platinum, and nickel.
- The catalyst speeds up the reaction by lowering the energy barrier, making it more efficient.
Benzoyl Chloride
Benzoyl chloride is an organic compound with the formula \( \mathrm{C_6H_5COCl} \). It is an acyl chloride derived from benzoic acid and is a colorless liquid that emits a pungent odor. In chemical reactions, benzoyl chloride is highly reactive due to its effective leaving group, the chloride ion.
This reactivity makes it a valuable intermediate in the synthesis of other chemical compounds.
This reactivity makes it a valuable intermediate in the synthesis of other chemical compounds.
- It is commonly used in acylation reactions to introduce the benzoyl group into compounds.
- Besides, it serves as a starting material in the formation of benzaldehyde via Rosenmund reduction.
Benzaldehyde
Benzaldehyde \( (\mathrm{C_6H_5CHO}) \) is the simplest aromatic aldehyde and is characterized by its pleasant almond-like scent. It is a significant compound both in the laboratory and in various industries, especially in flavorings and as a precursor to several pharmaceuticals.
- In the Rosenmund reduction, benzoyl chloride is hydrogenated to benzaldehyde, highlighting the reaction's specificity.
- Benzaldehyde is known for maintaining its aromatic ring structure, making it stable and versatile.
Palladium Catalyst
The palladium catalyst is a significant component in hydrogenation reactions such as the Rosenmund reduction. Palladium is a precious metal often used in its metallic form or supported on various surfaces to increase its effectiveness.
- It aids in the activation of molecular hydrogen, facilitating its addition to the reactant.
- In Rosenmund reduction, palladium is typically supported on barium sulfate \((\mathrm{BaSO_4})\)\.
Other exercises in this chapter
Problem 49
Benzoyl chloride is prepared from benzoic acid by (a) \(\mathrm{Cl}_{2}\), hv (b) \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) (c) \(\mathrm{SOCl}_{2}\) (d) \(\mathrm{Cl
View solution Problem 50
Schiff's reagent gives pink colour with (a) acetone (b) acetaldehyde (c) acetic acid (d) methyl acetate
View solution Problem 53
The reagent that can be used to distinguished between methanoic acid and ethanoic acid is (a) sodium carbonate solution (b) ammonical silver nitrate solution (c
View solution Problem 54
\(\mathrm{X}+\mathrm{CH}_{3} \mathrm{COOH} \longrightarrow\) Ester \(+\mathrm{H}_{2} \mathrm{O}, \mathrm{X}\) is (a) alcohol (b) pyridine (c) alkane (d) acid
View solution