Problem 51
Question
Graph each function and then find the specified limits. When necessary, state that the limit does not exist. $$ f(x)=|x| ; \quad \text { find } \lim _{x \rightarrow 0} f(x) \text { and } \lim _{x \rightarrow-2} f(x). $$
Step-by-Step Solution
Verified Answer
\( \lim_{x \to 0} f(x) = 0 \) and \( \lim_{x \to -2} f(x) = 2 \).
1Step 1: Understanding the Function
The function given is the absolute value function, \( f(x) = |x| \). This function gives the non-negative value of \( x \), which means for \( x \geq 0 \), \( f(x) = x \) and for \( x < 0 \), \( f(x) = -x \).
2Step 2: Graphing the Function
The graph of \( f(x) = |x| \) is V-shaped. It has a vertex at the origin (0,0) and consists of two straight lines: \( y = x \) when \( x \geq 0 \) and \( y = -x \) when \( x < 0 \). This is a continuous function without any breaks or holes in the graph.
3Step 3: Finding \( \lim_{x \to 0} f(x) \)
To find \( \lim_{x \to 0} f(x) \), examine the behavior of \( f(x) \) as \( x \) approaches 0 from both sides. From the right, \( x \to 0^+ \), \( f(x) \) approaches 0 since \( f(x) = x \). From the left, \( x \to 0^- \), \( f(x) \) also approaches 0 since \( f(x) = -x \). Both one-sided limits are equal, so \( \lim_{x \to 0} f(x) = 0 \).
4Step 4: Finding \( \lim_{x \to -2} f(x) \)
Consider \( f(x) \) as \( x \) approaches \(-2\) from both sides. From the right, \( x \to -2^+ \), \( f(x) = -x \) approaches \( |-2| = 2 \). From the left, \( x \to -2^- \), \( f(x) = -x \) also approaches \( 2 \). Both one-sided limits are the same, thus \( \lim_{x \to -2} f(x) = 2 \).
Key Concepts
Absolute Value FunctionContinuous FunctionGraphing Functions
Absolute Value Function
The absolute value function, denoted as \( f(x) = |x| \), is a pivotal concept in understanding limits and behavior of functions in calculus. At its core, this function converts all inputs into non-negative outputs. That means whether you input a positive or negative number, the result will always be non-negative.
- If \( x \geq 0 \), then \( f(x) = x \)
- If \( x < 0 \), then \( f(x) = -x \)
Continuous Function
To describe a continuous function, think of a seamless line you can draw without stopping your pencil. The absolute value function \( f(x) = |x| \) is continuous because you can trace its path across its entire domain without lifting your pen. One of the distinctiveness of continuous functions is their predictability. As you approach any value on the graph, you should be able to confidently determine its exact behavior at that point. This behavior was beautifully illustrated in finding the limits at \( x = 0 \) and \( x = -2 \) for the absolute value function. Since the function does not have any holes, jumps, or asymptotes, its continuous nature is confirmed. Continuous functions like \( f(x) = |x| \) make limit evaluations straightforward, as both sides gather to meet at a single, predictable point.
Graphing Functions
Graphing functions is a powerful tool to visualize mathematical relationships. For the absolute value function \( f(x) = |x| \), the graph is V-shaped. This shape arises because the function pieces together two linear graphs:
- \( y = x \) for \( x \geq 0 \)
- \( y = -x \) for \( x < 0 \)
Other exercises in this chapter
Problem 51
Find \(y^{\prime}\) $$ \text { If } y=x+\frac{2}{x^{3}}, \text { find }\left.\frac{d y}{d x}\right|_{x-1} $$
View solution Problem 51
Consider the function \(k\) given by $$k(x)=|x-3|+2$$ a) For what \(x\) -value(s) is the function not differentiable? b) Evaluate \(k^{\prime}(0), k^{\prime}(1)
View solution Problem 51
Find an equation of the tangent line to the graph of \(y=x^{2}+3 /(x-1)\) at (a) \(x=2 ;\) (b) \(x=3\).
View solution Problem 51
Find \(\frac{d y}{d x}\) for each pair of functions. $$ y=5 u^{2}+3 u, \text { where } u=x^{3}+1 $$
View solution