Problem 51
Question
For the following exercises, evaluate the natural logarithmic expression without using a calculator. $$\ln (1)$$
Step-by-Step Solution
Verified Answer
\( \ln(1) = 0 \).
1Step 1: Understanding the Natural Logarithm
The natural logarithm, denoted as \( ext{ln}(x)\), is the logarithm to the base \(e\), where \(e\) is approximately equal to 2.71828. The expression inside the natural logarithm function in this problem is \(1\).
2Step 2: Applying the Property of Logarithms
Recall the property of logarithms: the logarithm of \(1\) to any base is always \(0\) because any number raised to the power of \(0\) equals \(1\). Mathematically, this property is written as \( \ln(1) = 0 \).
3Step 3: Write the Final Answer
From the property of logarithms, we conclude that the natural logarithm of \(1\) is \(0\). Therefore, the solution to the expression \( \ln(1) \) is \(0\).
Key Concepts
Logarithm PropertiesEvaluating LogarithmsBase e in Logarithms
Logarithm Properties
Understanding the properties of logarithms helps simplify calculations and solve complex logarithmic equations. The primary property used in this case states that the logarithm of 1 to any base is always 0. This can be expressed mathematically as:
In addition to this, there are other useful logarithm properties, such as:
- For any base \( b \), \( \,\log_b (1) = 0 \)
In addition to this, there are other useful logarithm properties, such as:
- The product property: \( \log_b (MN) = \log_b (M) + \log_b (N) \)
- The quotient property: \( \log_b \left( \frac{M}{N} \right) = \log_b (M) - \log_b (N) \)
- The power property: \( \log_b (M^p) = p \cdot \log_b (M) \)
Evaluating Logarithms
Evaluating logarithms can often be simplified by using properties and breaking down the expression into more manageable parts. In the exercise, you are tasked with evaluating \( \ln(1) \) without a calculator.
Applying the logarithm property we discussed, you know that \( \ln(1) \) is 0 because any number to the power of 0 is 1.
Evaluating logarithms generally involves identifying relationships or utilizing properties that directly give you an answer or simplify your expression for easier computation.
For instance, if you know the base of the logarithm you’re dealing with, you can use known values and relationships:
Applying the logarithm property we discussed, you know that \( \ln(1) \) is 0 because any number to the power of 0 is 1.
Evaluating logarithms generally involves identifying relationships or utilizing properties that directly give you an answer or simplify your expression for easier computation.
For instance, if you know the base of the logarithm you’re dealing with, you can use known values and relationships:
- Logarithms of powers of the base are straightforward, for example \( \log_2 (8) = 3 \) because \( 2^3 = 8 \).
- Recognizing that \( \ln(e) = 1 \) can help simplify complex natural log evaluations.
Base e in Logarithms
Natural logarithms use \( e \) as the base, which is approximately 2.71828. This special number is integral to various areas of mathematics, particularly in calculus, because it simplifies the process of differentiation and integration in exponential functions.
The natural logarithm, denoted \( \ln(x) \), therefore refers to the logarithm with the base \( e \). You can think of \( \ln(x) \) as the power to which \( e \) must be raised to produce the number \( x \).
Just like how \( \log_{10}(x) \) uses 10 as its base, \( \ln(x) \) uniquely uses \( e \):
Understanding this base is crucial for working with logarithms in these fields, and recognizing \( \ln(1) = 0 \) is a fundamental result easy to remember, thanks to its simplicity and importance in confirming base properties.
The natural logarithm, denoted \( \ln(x) \), therefore refers to the logarithm with the base \( e \). You can think of \( \ln(x) \) as the power to which \( e \) must be raised to produce the number \( x \).
Just like how \( \log_{10}(x) \) uses 10 as its base, \( \ln(x) \) uniquely uses \( e \):
- If \( y = \ln(x) \), then \( e^y = x \).
Understanding this base is crucial for working with logarithms in these fields, and recognizing \( \ln(1) = 0 \) is a fundamental result easy to remember, thanks to its simplicity and importance in confirming base properties.
Other exercises in this chapter
Problem 51
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