Problem 51
Question
For Exercises 51 and \(52,\) use the following information. In an electrical circuit, if two resistors with resistance \(R_{1}\) and \(R_{2}\) are connected in parallel as shown, the relationship between these resistances and the resulting combination resistance \(R\) is \(\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}\). If \(R_{1}\) is \(x\) ohms and \(R_{2}\) is 4 ohms less than twice \(x\) ohms, write an expression for \(\frac{1}{R}\).
Step-by-Step Solution
Verified Answer
\(\frac{1}{R} = \frac{1}{x} + \frac{1}{2x - 4}\)
1Step 1: Identify Given Variables
We have two resistors: \(R_1\) is given as \(x\) ohms and \(R_2\) is given as 4 ohms less than twice \(x\) ohms. Hence, \(R_2 = 2x - 4\).
2Step 2: Substitute Resistances in Formula
We know that the formula for resistors in parallel is \(\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}\). Substitute \(R_1 = x\) and \(R_2 = 2x - 4\) into this formula.
3Step 3: Write the Expression for \(\frac{1}{R}\)
Substituting in the values, we get \(\frac{1}{R} = \frac{1}{x} + \frac{1}{2x - 4}\).
4Step 4: Simplification of the Expression
There is no further simplification necessary for this step in terms of expressing \(\frac{1}{R}\), this is the required expression with given values.
Key Concepts
Resistance FormulaElectrical CircuitsAlgebraic Expressions
Resistance Formula
In an electrical circuit, when resistors are connected in parallel, it changes the way the current flows through the circuit compared to when they are connected in series. In parallel circuits, the voltage across each resistor is the same, but the total current is the sum of the currents through each resistor. To find the equivalent resistance (a single resistor that could replace the multiple resistors without changing the current or voltage in the circuit), we use the resistance formula. The formula for two resistors is:
- \(\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}\)
Electrical Circuits
An electrical circuit is a pathway that allows electricity to flow. It consists of various components such as resistors, wires, batteries, and switches. These components create a closed loop, allowing electricity to flow through. Circuits can be open or closed, depending on whether the path is complete. There are two primary types of circuit arrangements: parallel and series.
In a parallel circuit, all components are connected across the same two points forming a distinct loop. Each component has its own direct path to the power source. This design provides distinct advantages such as:
- The ability to maintain voltage across all components.
- Ensuring that if one resistor fails, the others can still function.
- In homes and buildings, parallel circuits allow different outlets and lights to operate independently.
Algebraic Expressions
Algebraic expressions are a way of representing relationships using symbols and numbers. They are used extensively in mathematics to simplify and solve problems. In the context of electrical circuits, algebraic expressions allow us to symbolize relationships, like those among resistors.In this exercise, you are given the expression:
- \(R_1 = x\)
- \(R_2 = 2x - 4\)
- \(\frac{1}{R} = \frac{1}{x} + \frac{1}{2x - 4}\)
Other exercises in this chapter
Problem 51
Find each product, if possible. $$ \left[\begin{array}{rr}{3} & {-5} \\ {2} & {7}\end{array}\right] \cdot\left[\begin{array}{rrr}{5} & {1} & {-3} \\ {8} & {-4}
View solution Problem 51
Find the LCM of each set of polynomials. \(x^{2}-y^{2}, 3 x+3 y\)
View solution Problem 51
REASONING Compare and contrast the graphs of \(f(x)=\frac{(x-1)(x+5)}{x-1}\) and \(g(x)=x+5\)
View solution Problem 51
Suppose \(b\) varies inversely as the square of \(a\) . If \(a\) is multiplied by \(9,\) which of the following is true for the value of \(b ?\) A. It is multip
View solution