Problem 51
Question
For a zero-order reaction, the plot of concentration vs time is linear with (a) +ve slope and zero intercept (b) -ve slope and zero intercept (c) +ve slope and non-zero intercept (d) -ve slope and non-zero intercept
Step-by-Step Solution
Verified Answer
(d) -ve slope and non-zero intercept.
1Step 1: Understanding the Zero Order Reaction
In a zero-order reaction, the rate of reaction is constant and does not depend on the concentration of the reactant. Thus, the rate law expression is given by \( R = k \), where \( k \) is the rate constant.
2Step 2: Zero Order Kinetics Equation
For a zero-order reaction, the concentration of the reactant \([A]\) at time \( t \) is given by the equation: \([A] = [A]_0 - kt\), where \([A]_0\) is the initial concentration and \( k \) is the rate constant.
3Step 3: Analyzing the Concentration vs Time Plot
The equation \([A] = [A]_0 - kt\) resembles the equation of a straight line \( y = mx + c \), where \( y \) corresponds to \([A]\), \( x \) corresponds to \( t \), \( m \) (the slope) corresponds to \(-k\) (negative because the concentration decreases over time), and \( c \) (the y-intercept) corresponds to \([A]_0\).
4Step 4: Determining the Slope and Intercept
From the equation \([A] = [A]_0 - kt\), the slope \(-k\) is negative indicating a negative slope, and the intercept \([A]_0\) is usually non-zero. Thus, for a zero-order reaction, the plot of concentration vs. time has a negative slope with a non-zero intercept.
5Step 5: Selecting the Correct Option
Given the explanation above, the plot of concentration vs time for a zero-order reaction has a negative slope (as the concentration decreases) and a non-zero intercept (as determined by \([A]_0\)). Therefore, the correct answer is option (d).
Key Concepts
Rate Law ExpressionConcentration vs Time PlotReaction KineticsRate Constant
Rate Law Expression
In chemical kinetics, the rate law expression plays a crucial role in understanding how the rate of a reaction depends on the concentration of reactants. For a zero-order reaction, the rate law is surprisingly straightforward. Unlike first or second-order reactions, where the rate depends on the concentration of reactants, a zero-order reaction means that the rate is constant, regardless of the concentration of any reactant. This can be mathematically represented as:
- \( R = k \)
Concentration vs Time Plot
A zero-order reaction is characterized by its linear concentration vs time plot. When you map concentration against time for zero-order kinetics, you get a straight line. This reflects the simplification that the concentration of reactants decreases at a constant rate over time. Using the equation derived from the zero-order kinetics:
- \([A] = [A]_0 - kt\)
- \(y = mx + c\)
Reaction Kinetics
Understanding reaction kinetics is fundamental when analyzing how reactions proceed over time. In the realm of zero-order reactions, kinetics simplify but reveal particular insights into how reactions behave.
In simple terms, in zero-order kinetics,
- The rate of product formation is constant because the reactants are consumed at a uniform rate.
- This generally occurs when a reaction is limited by some external factor, such as a saturated catalyst surface or when all reacting molecules are busy and cannot increase the rate despite an abundance of reactants.
Rate Constant
The rate constant is a pivotal part of the rate law and expresses how quickly a reaction proceeds. In a zero-order reaction, the rate constant \( k \) is especially important because the rate of reaction equals \( k \), as depicted in the equation:
- \( R = k \)
- It generally has units of concentration/time (e.g., M/s or mol/L/s).
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