Problem 51
Question
Find the slope and y-intercept of the line, and draw its graph. $$ y=4 $$
Step-by-Step Solution
Verified Answer
The slope is 0 and the y-intercept is (0, 4), representing a horizontal line at \( y = 4 \).
1Step 1: Identify the Equation Type
The given equation is in the form of a constant: \[ y = 4 \]This is a special linear equation that represents a horizontal line.
2Step 2: Determine the Slope
For a horizontal line described by the equation \( y = c \) where \( c \) is constant, the slope \( m \) is always 0.
3Step 3: Determine the Y-Intercept
The y-intercept occurs where the line crosses the y-axis. Since the equation is \( y = 4 \), the line crosses the y-axis at 4. Thus, the y-intercept is the point \((0, 4)\).
4Step 4: Sketch the Graph
To sketch the line \( y = 4 \):1. Plot the y-intercept at (0, 4).2. Draw a horizontal line across the graph that passes through y = 4, parallel to the x-axis.
Key Concepts
Slope of a LineY-InterceptGraphing Linear Equations
Slope of a Line
The slope of a line is a measure of how steep or flat the line is. It's sometimes referred to as the "rise over run" because it tells you how much the line goes up or down (rise) for a certain amount it goes across (run). A positive slope slants upward, while a negative slope slants downward.
In the case of the equation \( y = 4 \), we have a horizontal line. This means it does not go up or down as it runs left or right.
In the case of the equation \( y = 4 \), we have a horizontal line. This means it does not go up or down as it runs left or right.
- Horizontal lines always have a slope of zero.
- In mathematical terms, if the line doesn’t rise, the slope \( m = 0 \).
- This is because there is no change in the y-values, no matter the change in x.
Y-Intercept
The y-intercept of a line is the point where the line crosses the y-axis. It is a fundamental part of a line's equation in the slope-intercept form \( y = mx + b \), where \( b \) represents the y-intercept.
For the equation \( y = 4 \), it is already in its simplest form, showing that it directly intersects the y-axis at \( y = 4 \).
For the equation \( y = 4 \), it is already in its simplest form, showing that it directly intersects the y-axis at \( y = 4 \).
- The y-intercept here is \((0, 4)\).
- This is the point on the graph where the line will meet the y-axis, in this instance directly at the number 4.
- In graphical terms, it’s the starting point of the line when drawing it on a Cartesian plane.
Graphing Linear Equations
Graphing linear equations gives a visual representation of the relationships described by the equations. It involves plotting the y-intercept and using the slope to find other points on the line.
For the equation \( y = 4 \), this process is simple.
For the equation \( y = 4 \), this process is simple.
- Start by plotting the y-intercept, which is the point \((0, 4)\).
- Since the line is horizontal, no slope calculations are needed.
- Simply draw a straight, horizontal line that runs across the graph at \( y = 4 \), parallel to the x-axis.
Other exercises in this chapter
Problem 50
\(49-54\) . Find the center and radius of the circle, and sketch its graph. $$ x^{2}+y^{2}=5 $$
View solution Problem 50
Find the lengths of the medians of the triangle with vertices \(A(1,0), B(3,6),\) and \(C(8,2) .\) (A median is a line segment from a vertex to the midpoint of
View solution Problem 51
\(49-54\) . Find the center and radius of the circle, and sketch its graph. $$ (x-3)^{2}+y^{2}=16 $$
View solution Problem 51
Find the point that is one-fourth of the distance from the point \(P(-1,3)\) to the point \(Q(7,5)\) along the segment \(P Q\) .
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