Problem 51
Question
Find a rectangular equation that has the same graph as the given polar equation. $$ r=2 \sec \theta $$
Step-by-Step Solution
Verified Answer
The rectangular equation is \( x = 2 \).
1Step 1: Understand the Polar Equation
The given polar equation is \( r = 2 \sec \theta \). In this equation, \( r \) represents the radius, and \( \theta \) is the angle from the positive x-axis to the line connecting the origin to the point. The goal is to convert this into a rectangular (Cartesian) equation.
2Step 2: Recall the Polar to Rectangular Conversion Formulas
We will use the conversion formulas between polar and rectangular coordinates: \( x = r \cos \theta \) and \( y = r \sin \theta \). Another useful identity is \( \sec \theta = \frac{1}{\cos \theta} \), and we know \( r = \frac{x}{\cos \theta} \).
3Step 3: Substitute \( r = 2 \sec \theta \) into the Conversion Formulas
Since \( \sec \theta = \frac{1}{\cos \theta} \), we can rewrite the equation \( r = 2 \sec \theta \) as \( r = \frac{2}{\cos \theta} \). Therefore, \( r \cos \theta = 2 \).
4Step 4: Substitute for \( r \cos \theta \) in Rectangular Equation
Since \( r \cos \theta = x \), substitute in the equation: \( x = 2 \).
5Step 5: Simplify and Confirm the Rectangular Equation
The expression \( x = 2 \) is already in its simplest form and describes a vertical line in a Cartesian coordinate system where every point on the graph has an x-coordinate of 2.
Key Concepts
Polar CoordinatesRectangular CoordinatesSecant Function
Polar Coordinates
Polar coordinates are a two-dimensional coordinate system, which is different from the familiar Cartesian (or rectangular) coordinates. Instead of defining a point by its horizontal and vertical distances from the origin, polar coordinates identify points based on:
The polar equation from our exercise, \( r = 2 \sec \theta \), expresses how the distance of points from the origin varies depending on the angle br>. Understanding the concept is crucial when converting to rectangular coordinates.
- The distance from the origin (radius, denoted as \( r \)).
- The angle from the positive x-axis (denoted as \( \theta \)).
The polar equation from our exercise, \( r = 2 \sec \theta \), expresses how the distance of points from the origin varies depending on the angle br>. Understanding the concept is crucial when converting to rectangular coordinates.
Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, use an x-axis and a y-axis to define the position of a point in a plane. Every point in a Cartesian system is represented by two numbers:
In the problem, we were tasked to convert the polar equation \( r = 2 \sec \theta \) into a rectangular one. Using the relationships:
- \( x \) (horizontal distance from the origin).
- \( y \) (vertical distance from the origin).
In the problem, we were tasked to convert the polar equation \( r = 2 \sec \theta \) into a rectangular one. Using the relationships:
- \( x = r \cos \theta \)
- \( y = r \sin \theta \)
Secant Function
The secant function originates from trigonometry and is related to the cosine function. Defined as \( \sec \theta = \frac{1}{\cos \theta} \), it represents the reciprocal of the cosine angle di>. Recall that cosine is a key function in representing horizontal distances in a unit circle. Therefore, the secant function describes how waves or oscillations might behave when extended beyond a circle's bounds.
In our exercise, the polar equation \( r = 2 \sec \theta \) can be rewritten using the identity \( \sec \theta = \frac{1}{\cos \theta} \). This becomes \( r = \frac{2}{\cos \theta} \). When converted to rectangular coordinates, it simplifies to \( x = 2 \), reflecting that the secant function translates the dependency on an angle into a fixed horizontal position in Cartesian coordinates dd>. Understanding this relationship allows for a smoother transition between polar and rectangular equations, highlighting the versatility of trigonometric functions.
In our exercise, the polar equation \( r = 2 \sec \theta \) can be rewritten using the identity \( \sec \theta = \frac{1}{\cos \theta} \). This becomes \( r = \frac{2}{\cos \theta} \). When converted to rectangular coordinates, it simplifies to \( x = 2 \), reflecting that the secant function translates the dependency on an angle into a fixed horizontal position in Cartesian coordinates dd>. Understanding this relationship allows for a smoother transition between polar and rectangular equations, highlighting the versatility of trigonometric functions.
Other exercises in this chapter
Problem 50
Use \((4)\) to parameterize the curve whose polar equation is given. Use a graphing utility to obtain the graph of the resulting set of parametric equations. $$
View solution Problem 51
Use a CAS to obtain graphs of the polar equation \(r=a+\cos \theta\) for \(a=0, \frac{1}{4}, \frac{1}{2}, \frac{3}{4}, 1, \frac{5}{4}, \ldots, 3\).
View solution Problem 52
Find a rectangular equation that has the same graph as the given polar equation. $$ r \cos \theta=-4 $$
View solution Problem 53
Suppose \(r=f(\theta)\) is a polar equation. Graphically interpret the given property. $$ f(-\theta)=f(\theta) \text { (even function) } $$
View solution