Problem 51 - Prealgebra and Introductory Algebra

Question

Evaluate the variable expression for \(a=-2, b=4, c=-1,\) and \(d=3\) $$(b+d)^{2}-4 a$$

Step-by-Step Solution

Answer

The evaluated variable expression for \(a=-2, b=4, c=-1,\) and \(d=3\) is \(57\)

Step 1: Substituting the given values

Substitute the given values into the expression. So, we have \((4+3)^{2} -4*(-2)\)

Step 2: Simplify inside the parentheses

Compute the addition inside the parentheses. So, we have \((7)^{2} -4*(-2)\)

Step 3: Square the value and simplify the expression

Compute the square of 7 and multiply 4 and -2. Then the expression will look like \(49 -(-8)\)

Step 4: Simplify the expression

Subtracting a negative will result in addition. Therefore, the expression simplifies to \(49+8\)

Step 5: Final Calculation

Perform final addition to get \(57\)