Problem 51
Question
Convert the rectangular equation to polar form. Assume \(a<0\) $$y=a$$
Step-by-Step Solution
Verified Answer
The polar form of the equation \(y = a\), with \(a < 0\) is \(r = -a\).
1Step 1: Understanding the Direction
The given equation is \(y=a\), a parallel line to the x-axis that runs through the point (0, a). Because a is negative \(y=a\) will be below the origin, which means that in a polar coordinate system the angle θ would be \(\frac{3\pi}{2}\) radians or 270°.
2Step 2: Conversion to Polar Coordinates
To convert this equation into the polar form we need to use the relation \(y=r\sin(\theta)\) which is the conversion formula from rectangular to polar coordinates for the y-coordinate. Substituting y by \(r\sin(\theta)\), the equation becomes \(r\sin(\theta) = a\). Division by a gives \(r = \frac{a}{\sin(\theta)}\). Considering the direction, we have \(\theta = \frac{3\pi}{2}\), which gives \(r = \frac{a}{\sin(\frac{3\pi}{2})}\). Because \(\sin(\frac{3\pi}{2}) = -1\), then the polar form is \(r = -a\).
Key Concepts
Rectangular Coordinate SystemPolar Coordinate SystemSine Function in Polar Coordinates
Rectangular Coordinate System
The rectangular coordinate system, also known as the Cartesian coordinate system, is one of the most widely used systems for representing points in a plane. Each point is determined by an ordered pair of numbers \( (x, y) \) that stand for its horizontal (x-coordinate) and vertical positions (y-coordinate) relative to two perpendicular lines called axes, namely the x-axis and the y-axis. The point where these axes intersect is called the origin, denoted as \( (0, 0) \).
In the context of the given exercise, the equation \( y = a \) represents a horizontal line that is parallel to the x-axis. The negative value of \( a \) indicates that this line is below the x-axis. Understanding how the line is positioned in a rectangular coordinate system is crucial when converting it into its polar counterpart.
In the context of the given exercise, the equation \( y = a \) represents a horizontal line that is parallel to the x-axis. The negative value of \( a \) indicates that this line is below the x-axis. Understanding how the line is positioned in a rectangular coordinate system is crucial when converting it into its polar counterpart.
Polar Coordinate System
Unlike the rectangular system, the polar coordinate system represents points in a plane using a distance and an angle. Each point is defined by a radial distance \( r \) from the origin and an angle \( θ \) measured from the positive x-axis, also referred to as the polar axis. Distance \( r \) is always non-negative, while angle \( θ \) is typically measured in radians and can range between \( 0 \) and \( 2π \) radians, or \( 0^\circ \) to \( 360^\circ \) in degrees.
For our exercise, converting the rectangular equation \( y = a \) into polar form required understanding that when \( y \) is negative, \( θ \) is \( \frac{3π}{2} \) radians, because angles in polar coordinates are measured counterclockwise from the positive x-axis. The polar coordinates represent not just a position, but also a direction of approach to that position.
For our exercise, converting the rectangular equation \( y = a \) into polar form required understanding that when \( y \) is negative, \( θ \) is \( \frac{3π}{2} \) radians, because angles in polar coordinates are measured counterclockwise from the positive x-axis. The polar coordinates represent not just a position, but also a direction of approach to that position.
Sine Function in Polar Coordinates
The sine function plays a key role in translating between rectangular and polar coordinates. It describes the relationship between the y-coordinate of a point in rectangular coordinates and the angle \( θ \) and radius \( r \) in polar coordinates using the formula \( y = r \sin(θ) \).
In our example, using this relationship allowed the conversion of the equation \( y = a \) into polar form. By replacing \( y \) with \( r \sin(θ) \) and considering that for \( θ = \frac{3π}{2} \) radians, the sine function yields \( \sin(\frac{3π}{2}) = -1 \) — this helped us arrive at the polar equation \( r = -a \) when \( a < 0 \). The sine function helps visualize how a point's height (y-coordinate) is related to its position on the unit circle, further solidifying one's understanding of how the polar coordinate system captures the essence of a point's location.
In our example, using this relationship allowed the conversion of the equation \( y = a \) into polar form. By replacing \( y \) with \( r \sin(θ) \) and considering that for \( θ = \frac{3π}{2} \) radians, the sine function yields \( \sin(\frac{3π}{2}) = -1 \) — this helped us arrive at the polar equation \( r = -a \) when \( a < 0 \). The sine function helps visualize how a point's height (y-coordinate) is related to its position on the unit circle, further solidifying one's understanding of how the polar coordinate system captures the essence of a point's location.
Other exercises in this chapter
Problem 50
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