Problem 51
Question
Convert the point from rectangular coordinates into polar coordinates with \(r \geq 0\) and \(0 \leq \theta<2 \pi\). $$ (-5,-12) $$
Step-by-Step Solution
Verified Answer
The polar coordinates are approximately (13, 4.29).
1Step 1: Determine the Value of r
To convert from rectangular to polar coordinates, we need to determine the radius \( r \), which is the distance from the origin to the point \((-5,-12)\). The formula to calculate \( r \) in polar coordinates is: \[ r = \sqrt{x^2 + y^2} \] Substitute the given values \( x = -5 \) and \( y = -12 \):\[ r = \sqrt{(-5)^2 + (-12)^2} = \sqrt{25 + 144} = \sqrt{169} = 13 \] Therefore, \( r = 13 \).
2Step 2: Determine the Angle θ
Next, we find the angle \( \theta \) using the arctangent function \( \tan^{-1} \), where \( \tan \theta = \frac{y}{x} \):\[ \theta = \tan^{-1}\left(\frac{-12}{-5}\right) \]This simplifies to \[ \theta = \tan^{-1}(2.4) \].On evaluating, we consider that our point lies in the third quadrant (since both coordinates are negative). The angle in radians that makes \( \tan \theta = 2.4 \) is approximately \( 1.15 \). Thus, to adjust for the third quadrant:\[ \theta_{polar} = \theta + \pi = 1.15 + 3.14 = 4.29 \] Hence, \( \theta \approx 4.29 \) radians.
3Step 3: Express Polar Coordinates
Now that we have both the radius and the angle, the polar coordinates \((r, \theta)\) can be written as:\[ (13, 4.29) \]
Key Concepts
Understanding Rectangular CoordinatesApplying the Distance FormulaIdentifying Quadrants
Understanding Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, denote a point's location in a plane using two values. These values, commonly represented as \((x, y)\), specify horizontal and vertical distances from the origin \((0, 0)\).
- The first number in the pair, \(x\), indicates the position relative to the vertical axis. Positive values of \(x\) mean the point is right of the origin, while negative values indicate it is to the left.
- The second number, \(y\), determines how far the point is from the horizontal axis. Positive \(y\) values place it above the origin, and negative values place it below.
Applying the Distance Formula
The distance formula is an essential tool for calculating the straight-line distance between two points in a plane. In this context, it is used to determine the radius \(r\) when converting rectangular coordinates to polar coordinates.The formula is:\[ r = \sqrt{x^2 + y^2}\]Here's how it works:- Each coordinate \((x, y)\) is squared, eliminating negative signs and reflecting how far the point is horizontally and vertically from the origin.- These squares add together, and the square root of the sum gives the distance, \(r\).For example, consider the point \((-5, -12)\):
- Square each coordinate: \((-5)^2 = 25\) and \((-12)^2 = 144\)
- Add the squares: \(25 + 144 = 169\)
- Take the square root: \(\sqrt{169} = 13\)
Identifying Quadrants
The plane in rectangular coordinates is divided into four quadrants. These quadrants help in identifying the position of a point and are numbered counterclockwise:
- Quadrant I: \(x > 0\) and \(y > 0\)
- Quadrant II: \(x < 0\) and \(y > 0\)
- Quadrant III: \(x < 0\) and \(y < 0\)
- Quadrant IV: \(x > 0\) and \(y < 0\)
Other exercises in this chapter
Problem 51
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$$ r=\ln (\theta), 1 \leq \theta \leq 12 \pi $$
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For the given vector \(\vec{v}\), find the magnitude \(\|\vec{v}\|\) and an angle \(\theta\) with \(0 \leq \theta
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