Problem 51
Question
Answer each of the following questions: (a) Of the elements S, Se, and Cl, which has the largest atomic radius? (b) Which has the larger radius, Br or \(\mathrm{Br}^{-} ?\) (c) Which should have the largest difference between the first and second ionization energy: Si, Na, P, or Mg? (d) Which has the largest ionization energy: \(\mathrm{N}, \mathrm{P}\), or As? (e) Which of the following has the largest radius: \(\mathrm{O}^{2-}\) \(\mathrm{N}^{3-},\) or \(\mathrm{F}^{-} ?\)
Step-by-Step Solution
Verified Answer
(a) Se, (b) \( \mathrm{Br}^{-} \), (c) Na, (d) N, (e) \( \mathrm{N}^{3-} \).
1Step 1: Understanding Atomic Radius
The atomic radius generally increases down a group and decreases across a period on the periodic table. When comparing S, Se, and Cl, Se is lower on the periodic table than S, and Cl is to the right. Thus, Se has the largest atomic radius.
2Step 2: Comparing Ion and Atom Sizes
For neutral atoms and their anions, like Br and \( \mathrm{Br}^{-} \), the anion has a larger radius. Anions gain electrons, resulting in increased electron-electron repulsion, which expands the electron cloud. Hence, \( \mathrm{Br}^{-} \) is larger than Br.
3Step 3: Ionization Energy Differences
The largest difference between the first and second ionization energy occurs when an electron is removed from a stable electron shell. Na has its first electron removal from the 3s sublevel, and the second from a full 2p shell, making this jump exceptionally large.
4Step 4: Highest Ionization Energy
Ionization energy decreases down a group and increases across a period. Therefore, \( \mathrm{N} \), being higher in the group than \( \mathrm{P} \) and \( \mathrm{As} \), has the highest ionization energy due to its smaller atomic radius and higher effective nuclear charge.
5Step 5: Comparing Ionic Radii
Among \( \mathrm{O}^{2-} \), \( \mathrm{N}^{3-} \), and \( \mathrm{F}^{-} \), the negative charge is greater on \( \mathrm{N}^{3-} \), resulting in greater electron-electron repulsion for the same number of protons, which makes its radius the largest.
Key Concepts
Ionization EnergyPeriodic TrendsElectron ConfigurationPeriodic Table Groups
Ionization Energy
Ionization energy is the amount of energy required to remove an electron from a gaseous atom or ion. This concept is essential because it helps us understand how different elements interact and form chemical bonds. In general, ionization energy increases across a period from left to right. This occurs because electrons added across a period fill the same principal energy level, and the increased nuclear charge holds the electrons more tightly, requiring more energy to remove one.
Down a group, however, ionization energy decreases. As we move downward, atoms have more electron shells, and valence electrons are further from the nucleus. The increase in distance reduces the nuclear pull felt by the outermost electrons, making them easier to remove. Understanding these trends allows us to predict which elements will have the highest or lowest ionization energies.
Down a group, however, ionization energy decreases. As we move downward, atoms have more electron shells, and valence electrons are further from the nucleus. The increase in distance reduces the nuclear pull felt by the outermost electrons, making them easier to remove. Understanding these trends allows us to predict which elements will have the highest or lowest ionization energies.
Periodic Trends
Periodic trends are patterns in the properties of elements that repeat across different periods and groups on the periodic table. These trends help us predict the behavior of different elements in terms of atomic size, ionization energy, and more.
For instance, across a period, atomic radii decrease due to the increasing positive charge in the nucleus, which pulls the electron cloud closer. Conversely, as you move down a group, the atomic radius increases because additional electron shells outweigh the increased nuclear charge. Familiarizing oneself with such trends is helpful for predicting the properties of unknown elements or understanding complex chemical reactions.
For instance, across a period, atomic radii decrease due to the increasing positive charge in the nucleus, which pulls the electron cloud closer. Conversely, as you move down a group, the atomic radius increases because additional electron shells outweigh the increased nuclear charge. Familiarizing oneself with such trends is helpful for predicting the properties of unknown elements or understanding complex chemical reactions.
Electron Configuration
Electron configuration is a representation of the arrangement of electrons within an atom. It adheres to the principle that electrons occupy the lowest energy orbitals available first. The configuration provides insight into the chemical properties of an element, primarily how it will bond with others.
A standard notation involves writing out each occupied energy level and sublevel according to increasing energy. For example, the configuration of magnesium is written as 1s^2 2s^2 2p^6 3s^2. Knowing electron configurations helps us understand periodic trends, such as ionization energy, as they determine the stability of an element's valence shell.
A standard notation involves writing out each occupied energy level and sublevel according to increasing energy. For example, the configuration of magnesium is written as 1s^2 2s^2 2p^6 3s^2. Knowing electron configurations helps us understand periodic trends, such as ionization energy, as they determine the stability of an element's valence shell.
Periodic Table Groups
The periodic table is arranged into columns known as groups. Each group contains elements with similar chemical properties due to their similar valence electron configurations. For instance, Group 1, known as the alkali metals, all have one electron in their outermost shell, making them highly reactive.
Different groups exhibit distinct trends:
Different groups exhibit distinct trends:
- Group 17 elements, called the halogens, have seven valence electrons and are very reactive non-metals.
- Group 18 contains the noble gases which are exceptionally stable due to having complete outer electron shells.
Other exercises in this chapter
Problem 49
Which of the following ions are unlikely to be found in a chemical compound: \(\mathrm{Cs}^{+}, \mathrm{In}^{4+}, \mathrm{Fe}^{6+}, \mathrm{Te}^{2-}, \mathrm{Sn
View solution Problem 50
Place the following elements and ions in order of decreasing size: \(\mathrm{K}^{+}, \mathrm{Cl}^{-}, \mathrm{S}^{2-},\) and \(\mathrm{Ca}^{2+}\).
View solution Problem 52
The following are isoelectronic species: \(\mathrm{Cl}^{-}, \mathrm{K}^{+},\) and \(\mathrm{Ca}^{2+}\) Rank them in order of increasing (a) size, (b) ionization
View solution Problem 53
Compare the elements Na, B, Al, and C with regard to the following properties: (a) Which has the largest atomic radius? (b) Which has the most negative electron
View solution