Problem 50
Question
Write an equation of each line. Write the equation in standard form unless indicated otherwise. See Examples 1 through \(6 .\) Through (8,-3)\(;\) parallel to the line \(6 x+2 y=5\)
Step-by-Step Solution
Verified Answer
Equation: \(3x + y = 21\)
1Step 1: Identify the Slope
The given line is in standard form: \(6x + 2y = 5\). First, rewrite this equation in slope-intercept form, \(y = mx + b\), to identify the slope.\[2y = -6x + 5 \]\[y = -3x + \frac{5}{2}\]Thus, the slope \(m\) is \(-3\). Since parallel lines have the same slope, the line we are finding also has a slope of \(-3\).
2Step 2: Use the Point-Slope Form
Use the point-slope form of a line equation, \(y - y_1 = m(x - x_1)\), where \(m = -3\), \((x_1, y_1) = (8, -3)\). Substitute these values into the equation.\[y + 3 = -3(x - 8)\]
3Step 3: Simplify the Equation
Expand the equation from Step 2:\[y + 3 = -3x + 24\]Subtract 3 from both sides to solve for \(y\):\[y = -3x + 21\]
4Step 4: Convert to Standard Form
Rearrange the equation \(y = -3x + 21\) to standard form \(Ax + By = C\).Add \(3x\) to both sides:\[3x + y = 21\]Now, the equation is in standard form.
Key Concepts
Understanding Slope-Intercept FormIdentifying and Understanding Parallel LinesUtilizing the Point-Slope Form to Find a Line Equation
Understanding Slope-Intercept Form
The slope-intercept form of a linear equation is a way to express a straight line using just two key components: slope and y-intercept. This form is written as:
The variable \( b \) stands for the y-intercept, the point where the line crosses the y-axis.
This form is handy when you need to quickly identify how the line behaves in terms of direction and intersection with the y-axis. Using slope-intercept form is especially useful when comparing different lines or predicting their behavior at various x-values.
In practice, converting a given equation into this format can make solving problems easier and more intuitive. For example, in the provided exercise, transforming the standard equation \(6x + 2y = 5\) to slope-intercept form allows us to easily identify the slope, which is crucial for determining parallel lines.
- \( y = mx + b \)
The variable \( b \) stands for the y-intercept, the point where the line crosses the y-axis.
This form is handy when you need to quickly identify how the line behaves in terms of direction and intersection with the y-axis. Using slope-intercept form is especially useful when comparing different lines or predicting their behavior at various x-values.
In practice, converting a given equation into this format can make solving problems easier and more intuitive. For example, in the provided exercise, transforming the standard equation \(6x + 2y = 5\) to slope-intercept form allows us to easily identify the slope, which is crucial for determining parallel lines.
Identifying and Understanding Parallel Lines
Parallel lines are lines in a plane that never intersect and are always the same distance apart. They have the same slope, but different y-intercepts.
This means no matter how far they are extended, they'll never meet.
To determine if two lines are parallel, you simply compare their slopes.
Thus, the slope is \(-3\). Another line with the same slope \(-3\) would be parallel to this line.
Understanding this concept is essential when tasked with writing equations of lines parallel to a given line, as knowing the slope is the first step to correctly formulating the new line's equation.
This means no matter how far they are extended, they'll never meet.
To determine if two lines are parallel, you simply compare their slopes.
- If two lines have the same slope \( m \), they are parallel.
- If their slopes are different, they are not.
Thus, the slope is \(-3\). Another line with the same slope \(-3\) would be parallel to this line.
Understanding this concept is essential when tasked with writing equations of lines parallel to a given line, as knowing the slope is the first step to correctly formulating the new line's equation.
Utilizing the Point-Slope Form to Find a Line Equation
The point-slope form is particularly useful when you know the slope of a line and a point it passes through. This form is expressed as:
The point-slope form is valuable for constructing an equation when given a specific point and a slope, especially when you're working out the equation of a line that is supposed to be parallel to another.To illustrate, using the exercise's specified point \((8, -3)\) and slope \(-3\), we substitute these into the point-slope form, resulting in \( y + 3 = -3(x - 8) \).
This approach not only makes it straightforward to draft the linear equation but also keeps calculations organized as you work towards converting it into other forms, like slope-intercept or standard form. By mastering point-slope form, you gain a powerful tool for tackling various line equation exercises with confidence.
- \( y - y_1 = m(x - x_1) \)
The point-slope form is valuable for constructing an equation when given a specific point and a slope, especially when you're working out the equation of a line that is supposed to be parallel to another.To illustrate, using the exercise's specified point \((8, -3)\) and slope \(-3\), we substitute these into the point-slope form, resulting in \( y + 3 = -3(x - 8) \).
This approach not only makes it straightforward to draft the linear equation but also keeps calculations organized as you work towards converting it into other forms, like slope-intercept or standard form. By mastering point-slope form, you gain a powerful tool for tackling various line equation exercises with confidence.
Other exercises in this chapter
Problem 50
If \(f(x)=3 x+3, g(x)=4 x^{2}-6 x+3,\) and \(h(x)=5 x^{2}-7,\) find each function value. \(h(0)\)
View solution Problem 50
Sketch the graph of each piecewise-defined function. Write the domain and range of each function. $$ g(x)=\left\\{\begin{array}{ll} -|x+1|-1 & \text { if } \qua
View solution Problem 50
Graph: \(f(x)=\left\\{\begin{array}{cc}\frac{1}{3} x & \text { if } x
View solution Problem 51
If \(R(x)=x+5, Q(x)=x^{2}-2,\) and \(P(x)=5 x,\) find each function. $$ P(x) \cdot R(x) $$
View solution