Problem 50
Question
Use the product and quotient rules for exponents to simplify each expression. $$ \frac{h^{3} h^{6} h}{h^{9}} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \( h \).
1Step 1: Apply the Product Rule
The product rule for exponents states that when you multiply two expressions with the same base, you add their exponents. Apply this rule to the terms in the numerator: \( h^{3} \times h^{6} \times h \). Add the exponents: \[ h^{3+6+1} = h^{10} \].Now, the expression simplifies to \[ \frac{h^{10}}{h^{9}} \].
2Step 2: Apply the Quotient Rule
The quotient rule for exponents states that when you divide two expressions with the same base, you subtract the exponents. Apply the rule to the simplified expression:\( \frac{h^{10}}{h^{9}} \).Subtract the exponents: \[ h^{10-9} = h^{1} \], which further simplifies to \( h \).
Key Concepts
Product RuleQuotient RuleSimplifying Expressions
Product Rule
The product rule is an essential part of simplifying expressions with exponents. It's a simple yet powerful tool. When multiplying two or more terms that have the same base, you can simply add their exponents.
This rule can greatly simplify your calculations. Imagine you have terms like \( h^3 \times h^6 \times h \). Since all terms have the same base \( h \), apply the product rule: add up the exponents \(3\), \(6\), and \(1\), giving you \( h^{3+6+1} = h^{10} \).
Here's a quick breakdown of the product rule steps:
This rule can greatly simplify your calculations. Imagine you have terms like \( h^3 \times h^6 \times h \). Since all terms have the same base \( h \), apply the product rule: add up the exponents \(3\), \(6\), and \(1\), giving you \( h^{3+6+1} = h^{10} \).
Here's a quick breakdown of the product rule steps:
- Check if bases are the same.
- Add the exponents together.
- Simplify to a single term with the added exponent.
Quotient Rule
The quotient rule for exponents is equally useful when simplifying expressions involving division. When you divide terms with the same base, subtract the exponent of the denominator from the exponent of the numerator. This will give you a quick simplified expression.
For example, take the expression \( \frac{h^{10}}{h^{9}} \). Here, both terms have the same base \( h \), so you subtract the exponents: \( 10 - 9 = 1 \), leaving you with \( h^1 \), or simply \( h \).
Steps for applying the quotient rule:
For example, take the expression \( \frac{h^{10}}{h^{9}} \). Here, both terms have the same base \( h \), so you subtract the exponents: \( 10 - 9 = 1 \), leaving you with \( h^1 \), or simply \( h \).
Steps for applying the quotient rule:
- Ensure both terms have the same base.
- Subtract the exponents (numerator exponent minus denominator exponent).
- Write the result as a single term with the subtracted exponent.
Simplifying Expressions
Simplifying expressions with exponents involves using rules to make the expression as straightforward as possible. The goal is to combine like terms and apply rules such as the product and quotient rules we discussed earlier.
When starting with an expression like \( \frac{h^3 h^6 h}{h^9} \), the idea is to first simplify the numerator using the product rule \( h^3 \times h^6 \times h = h^{10} \). Then, apply the quotient rule to divide by the denominator \( h^9 \), giving \( h^{10-9} = h^1 \), which is simply \( h \).
In essence, simplifying expressions means:
When starting with an expression like \( \frac{h^3 h^6 h}{h^9} \), the idea is to first simplify the numerator using the product rule \( h^3 \times h^6 \times h = h^{10} \). Then, apply the quotient rule to divide by the denominator \( h^9 \), giving \( h^{10-9} = h^1 \), which is simply \( h \).
In essence, simplifying expressions means:
- Applying the product rule to multiply terms effectively.
- Using the quotient rule to divide terms correctly.
- Combining like terms to achieve the simplest form of the expression.
Other exercises in this chapter
Problem 50
Perform the operations. See Example 4. $$ -2 h(7 h-2)^{2} $$
View solution Problem 50
Multiply. See Examples 4 and 5. $$ (2.6 x-3)(2 x-1) $$
View solution Problem 50
Subtract the polynomials. $$ \left(2 b^{2}+3 b-5\right)-\left(2 b^{2}-4 b-9\right) $$
View solution Problem 50
Evaluate each expression. See Example 2 and \(3 .\) \(x^{2}-x+7\) for a. \(x=6\) b. \(x=-2\)
View solution