Problem 50
Question
Use a graphing utility to graph the function. Use the graph to determine any \(x\) -value(s) at which the function is not continuous. Explain why the function is not continuous at the \(x\) -value(s). \(f(x)=\left\\{\begin{array}{ll}3 x-1, & x \leq 1 \\ x+1, & x>1\end{array}\right.\)
Step-by-Step Solution
Verified Answer
The function \(f(x)\) is not continuous at \(x = 1\) because the function is defined by two different expressions at this \(x\) - value and hence, there is a 'jump' or discontinuity at \(x = 1\).
1Step 1: Understand the piecewise function
A piecewise function is a function that is defined by several subfunctions, each corresponding to a certain interval of the independent variable. Here, the function \(f(x)\) is defined by two different expressions; \(3x - 1\) for \(x \leq 1\) and \(x + 1\) for \(x > 1\).
2Step 2: Plot the piecewise function
First, graph the function \(3x - 1\) on the interval \(x \leq 1\). Then, graph the function \(x + 1\) on the interval \(x > 1\). Remember to include the breakpoint \(x = 1\) in the graph.
3Step 3: Analyze the graph for discontinuities
Look for any breaks, jumps, or disconnects along the graph which would indicate points of discontinuity. A function is not continuous at a point if it is not defined at that point, or if a limit does not exist at that point.
4Step 4: Identify the \(x\) - value(s) at which the function is not continuous
Determine any \(x\) - value(s) at which the piecewise function is not continuous from the graph. In a piecewise function, potential discontinuity may occur at the breakpoints, i.e., where the definition of the function changes.
Key Concepts
Graphing Piecewise FunctionsDiscontinuities in FunctionsLimits and Continuity
Graphing Piecewise Functions
Graphing piecewise functions might appear challenging at first, but with a systematic approach, it can be simplified. A piecewise function is defined by multiple sub-functions, each applicable over certain segments of the domain.
The function given, \(f(x) = \begin{cases} 3x-1, & x \leq 1 \ x+1, & x>1 \end{cases}\), involves two distinct linear expressions. For \(x \leq 1\), the function is \(3x-1\), and for \(x > 1\), the function is \(x+1\).
Begin graphing by managing each segment separately:
The function given, \(f(x) = \begin{cases} 3x-1, & x \leq 1 \ x+1, & x>1 \end{cases}\), involves two distinct linear expressions. For \(x \leq 1\), the function is \(3x-1\), and for \(x > 1\), the function is \(x+1\).
Begin graphing by managing each segment separately:
- Start with \(3x-1\) when \(x \leq 1\). Plot by finding key points like \(x=1\) and check its corresponding \(y\)-value, which is 2.
- Next, graph \(x+1\) for \(x > 1\). Select \(x=2\) and place its point at \((2, 3)\).
Discontinuities in Functions
Discontinuities are specific points where a function behaves unexpectedly. Such points might be where the function isn't defined, or when the graph jumps suddenly. In piecewise functions, discontinuities may arise at the breakpoints where the function changes its defining equation.
Analyze the piecewise function \(f(x)\) at \(x=1\), which is the breakpoint here. Here’s how you can assess it:
Analyze the piecewise function \(f(x)\) at \(x=1\), which is the breakpoint here. Here’s how you can assess it:
- For the left section \(3x-1\), as \(x\) approaches 1, \(f(x) = 2\).
- For the right section \(x+1\), as \(x\) approaches 1, \(f(x) = 2\) also.
Limits and Continuity
Understanding limits is essential for analyzing continuity in functions. When evaluating a limit, we explore the function’s behavior as \(x\) nears a particular point. For piecewise functions, these evaluations determine continuity.
In our example, consider the function \(f(x)\) at the breakpoint \(x=1\):
In our example, consider the function \(f(x)\) at the breakpoint \(x=1\):
- Find the limit from the left: As \(x\) approaches 1 from the left (\(x\leq1\)), \(f(x) = 3x - 1\), so the limit is 2.
- Find the limit from the right: As \(x\) approaches 1 from the right (\(x>1\)), \(f(x) = x + 1\), thus the limit is 2.
Other exercises in this chapter
Problem 50
Find the point(s), if any, at which the graph of \(f\) has a horizontal tangent. $$ f(x)=\frac{x^{4}+3}{x^{2}+1} $$
View solution Problem 50
Find an equation of the tangent line to the graph of the function at the given point, (b) use a graphing utility to graph the function and its tangent line at t
View solution Problem 50
Find an equation of the line that is tangent to the graph of \(f\) and parallel to the given line. $$ f(x)=x^{2}-x \quad x+2 y-6=0 $$
View solution Problem 50
find the limit $$ \lim _{x \rightarrow 2} \frac{|x-2|}{x-2} $$
View solution