Problem 50
Question
Use a calculator to find the acute angles between the planes in Exercises \(49-52\) to the nearest hundredth of a radian. $$ x+y+z=1, \quad z=0 \quad \text (the\quad xy-plane) $$
Step-by-Step Solution
Verified Answer
The acute angle between the planes is approximately 0.955 radians.
1Step 1: Identify the Normal Vectors
The normal vector to the plane given by the equation \(x+y+z=1\) is \(\mathbf{n}_1 = \langle 1, 1, 1 \rangle\). The xy-plane, represented by \(z=0\), has a normal vector \(\mathbf{n}_2 = \langle 0, 0, 1 \rangle\).
2Step 2: Use Dot Product to Find the Angle
The angle \(\theta\) between the two planes' normal vectors is given by the formula \(\cos \theta = \frac{\mathbf{n}_1 \cdot \mathbf{n}_2}{\|\mathbf{n}_1\| \|\mathbf{n}_2\|}\).
3Step 3: Calculate the Dot Product
Compute the dot product \(\mathbf{n}_1 \cdot \mathbf{n}_2 = \langle 1, 1, 1 \rangle \cdot \langle 0, 0, 1 \rangle = 1 \times 0 + 1 \times 0 + 1 \times 1 = 1\).
4Step 4: Calculate the Magnitudes of the Vectors
Find \(\|\mathbf{n}_1\| = \sqrt{1^2 + 1^2 + 1^2} = \sqrt{3}\) and \(\|\mathbf{n}_2\| = \sqrt{0^2 + 0^2 + 1^2} = 1\).
5Step 5: Solve for the Cosine of the Angle
Substitute these values into the equation: \(\cos \theta = \frac{1}{\sqrt{3}\times 1} = \frac{1}{\sqrt{3}}\).
6Step 6: Calculate the Angle in Radians
Use a calculator to find \(\theta = \cos^{-1}\left(\frac{1}{\sqrt{3}}\right) \approx 0.955\) radians.
Key Concepts
Normal VectorsDot ProductPlanes Angle Calculation
Normal Vectors
A normal vector is a vector that is perpendicular to a surface or a plane. It helps us understand the orientation of the plane in three-dimensional space. Consider a plane defined by an equation like \(x + y + z = 1\). The coefficients of \(x, y, \text{and } z\) (in this case, 1, 1, and 1) become the components of the normal vector \(\mathbf{n}_1 = \langle 1, 1, 1 \rangle\).
For the xy-plane, described by \(z=0\), the normal vector \(\mathbf{n}_2\) is \(\langle 0, 0, 1 \rangle\). This vector points directly along the z-axis, indicating that the xy-plane is flat and spans the x and y directions entirely.
Normal vectors are crucial because they simplify the process of finding the angle between planes and are used extensively in 3D modeling, physics simulations, and engineering designs. By using normal vectors, we can determine properties such as the distance between planes or whether they are parallel or perpendicular.
For the xy-plane, described by \(z=0\), the normal vector \(\mathbf{n}_2\) is \(\langle 0, 0, 1 \rangle\). This vector points directly along the z-axis, indicating that the xy-plane is flat and spans the x and y directions entirely.
Normal vectors are crucial because they simplify the process of finding the angle between planes and are used extensively in 3D modeling, physics simulations, and engineering designs. By using normal vectors, we can determine properties such as the distance between planes or whether they are parallel or perpendicular.
Dot Product
The dot product, also called the scalar product, is a way to multiply two vectors that results in a scalar (a single number). This value gives us insight into the relationship between the direction of the vectors. It is crucial in calculating angles and determining orthogonal properties of vectors.
For two vectors \(\mathbf{a} = \langle a_1, a_2, a_3 \rangle\) and \(\mathbf{b} = \langle b_1, b_2, b_3 \rangle\), their dot product is given by:
For two vectors \(\mathbf{a} = \langle a_1, a_2, a_3 \rangle\) and \(\mathbf{b} = \langle b_1, b_2, b_3 \rangle\), their dot product is given by:
- \(\mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 + a_3b_3\)
- \(\mathbf{n}_1 \cdot \mathbf{n}_2 = 1 \times 0 + 1 \times 0 + 1 \times 1 = 1\)
Planes Angle Calculation
To find the angle between two planes, we first need their normal vectors. The relationship between these vectors is key, as the angle between the planes is the same as the angle between their normal vectors.
To find this angle \(\theta\), we use:
This angle between the planes helps us understand their spatial relationship and is used in fields like robotics and computer graphics to control angles and rotations.
To find this angle \(\theta\), we use:
- \(\cos \theta = \frac{\mathbf{n}_1 \cdot \mathbf{n}_2}{\|\mathbf{n}_1\| \|\mathbf{n}_2\|}\)
- \(\|\mathbf{n}_1\| = \sqrt{1^2 + 1^2 + 1^2} = \sqrt{3}\)
- \(\|\mathbf{n}_2\| = \sqrt{0^2 + 0^2 + 1^2} = 1\)
This angle between the planes helps us understand their spatial relationship and is used in fields like robotics and computer graphics to control angles and rotations.
Other exercises in this chapter
Problem 50
Use similar triangles to find the coordinates of the point \(Q\) that divides the segment from \(P_{1}\left(x_{1}, y_{1}, z_{1}\right)\) to \(P_{2}\left(x_{2},
View solution Problem 50
Find the centers and radii of the spheres in Exercises \(47-50\) $$x^{2}+\left(y+\frac{1}{3}\right)^{2}+\left(z-\frac{1}{3}\right)^{2}=\frac{16}{9}$$
View solution Problem 51
Plot the surfaces in Exercises \(49-52\) over the indicated domains. If you can, rotate the surface into different viewing positions. $$z=x^{2}+y^{2}, \quad-3 \
View solution Problem 51
Use a calculator to find the acute angles between the planes in Exercises \(49-52\) to the nearest hundredth of a radian. $$ 2 x+2 y-z=3, \quad x+2 y+z=2 $$
View solution