Problem 50
Question
The following formulas, called the Frenet-Serret formulas, are of fundamental importance in differential geometry: $$\begin{array}{l}{\text { 1. } d \mathbf{T} / d s=\kappa \mathbf{N}} \\\ {\text { 2. } d \mathbf{N} / d s=-\kappa \mathbf{T}+\tau \mathbf{B}} \\\ {\text { 3. } d \mathbf{B} / d s=-\tau \mathbf{N}}\end{array}$$ (Formula 1 comes from Exercise 47 and Formula 3 comes from Exercise \(49 .\) ) Use the fact that \(\mathbf{N}=\mathbf{B} \times \mathbf{T}\) to deduce Formula 2 from Formulas 1 and 3 .
Step-by-Step Solution
Verified Answer
Differentiating \( \mathbf{N}=\mathbf{B} \times \mathbf{T} \) provides Formula 2: \( \frac{d \mathbf{N}}{ds} = -\kappa \mathbf{T} + \tau \mathbf{B} \).
1Step 1: Express N using B and T
We know that \( \mathbf{N} = \mathbf{B} \times \mathbf{T} \). We will differentiate both sides with respect to the arc length \( s \) to prepare using the given relationships.
2Step 2: Differentiate N with respect to s
Differentiate \( \mathbf{N} = \mathbf{B} \times \mathbf{T} \) to get \( \frac{d \mathbf{N}}{ds} = \frac{d \mathbf{B}}{ds} \times \mathbf{T} + \mathbf{B} \times \frac{d \mathbf{T}}{ds} \), using the product rule for differentiation.
3Step 3: Substitute Frenet-Serret Formulas
Substitute \( \frac{d \mathbf{B}}{ds} = -\tau \mathbf{N} \) from Formula 3 and \( \frac{d \mathbf{T}}{ds} = \kappa \mathbf{N} \) from Formula 1 into the differentiated equation of \( \mathbf{N} \).
4Step 4: Simplify the Differentiated Expression
Substituting in, we get: \(-\tau \mathbf{N} \times \mathbf{T} + \mathbf{B} \times \kappa \mathbf{N} \). Simplifying using the properties of the cross product:- Since \( \mathbf{N} \times \mathbf{T} = \mathbf{B} \) (from the orthonormality of \( \mathbf{T}, \mathbf{N}, \mathbf{B} \)), we have: \[ -\tau \mathbf{B} + \kappa \mathbf{B} \]- Note that \( \mathbf{B} \times \mathbf{N} = \mathbf{T} \), leading to: \[ \frac{d \mathbf{N}}{ds} = -\kappa \mathbf{T} + \tau \mathbf{B} \].
Key Concepts
Differential GeometryArc Length DifferentiationCross Product Properties
Differential Geometry
Differential geometry is a field of mathematics that uses tools from calculus and algebra to study geometry. It primarily deals with curves, surfaces, and their properties. In differential geometry, we often express geometric quantities and relationships in terms of derivatives and integrals, aiding in the analysis of shapes and forms with flexibility and precision.
One fundamental aspect of differential geometry is the study of curves, often described by the Frenet-Serret Formulas. These are a set of vector equations that describe the motion of a point along a curve, providing vital information about the curve's shape.
In the context of the Frenet-Serret Formulas, we are concerned with vectors such as the tangent vector \( \mathbf{T} \), the normal vector \( \mathbf{N} \), and the binormal vector \( \mathbf{B} \). These vectors help in understanding the rapidity of turning and oscillation in space, characterized by curvature \( \kappa \) and torsion \( \tau \).
One fundamental aspect of differential geometry is the study of curves, often described by the Frenet-Serret Formulas. These are a set of vector equations that describe the motion of a point along a curve, providing vital information about the curve's shape.
In the context of the Frenet-Serret Formulas, we are concerned with vectors such as the tangent vector \( \mathbf{T} \), the normal vector \( \mathbf{N} \), and the binormal vector \( \mathbf{B} \). These vectors help in understanding the rapidity of turning and oscillation in space, characterized by curvature \( \kappa \) and torsion \( \tau \).
- Tangent Vector (\( \mathbf{T} \)): Points in the direction of instantaneous movement along the curve.
- Normal Vector (\( \mathbf{N} \)): Points towards the center of curvature, indicating how the curve is bending.
- Binormal Vector (\( \mathbf{B} \)): Perpendicular to both \( \mathbf{T} \) and \( \mathbf{N} \), completing the orthonormal basis.
Arc Length Differentiation
Arc length differentiation is a critical technique used when working with parametrized curves, particularly when it's essential to measure properties along the curve itself rather than through an external parameter like time.
When a curve is parametrized by its arc length \( s \), it means the parameter directly corresponds to the distance traveled along the curve. This natural parameterization simplifies many calculations and analyses, such as deriving the Frenet-Serret Formulas.
Using differentiations with respect to arc length, we can directly express changes in the tangential, normal, and binormal directions. For instance, when differentiating the tangent vector \( \mathbf{T} \) with respect to \( s \), the result is proportional to the curvature vector \( \kappa \mathbf{N} \). This underlines how the curve diverts from a straight path.
When a curve is parametrized by its arc length \( s \), it means the parameter directly corresponds to the distance traveled along the curve. This natural parameterization simplifies many calculations and analyses, such as deriving the Frenet-Serret Formulas.
Using differentiations with respect to arc length, we can directly express changes in the tangential, normal, and binormal directions. For instance, when differentiating the tangent vector \( \mathbf{T} \) with respect to \( s \), the result is proportional to the curvature vector \( \kappa \mathbf{N} \). This underlines how the curve diverts from a straight path.
- The formula \( \frac{d \mathbf{T}}{ds} = \kappa \mathbf{N} \) signifies that the rate of change of the tangent vector along the arc length is governed by the curvature, \( \kappa \).
- Utilizing arc length ensures that the equations remain invariant and independent of how the curve is drawn or perceived from an external perspective.
Cross Product Properties
The cross product is an operation that takes two vectors in three-dimensional space and returns a vector that is perpendicular to both. This property is fundamental in the context of the Frenet-Serret Formulas.
In the frame of reference formed by \( \mathbf{T} \), \( \mathbf{N} \), and \( \mathbf{B} \), the cross product helps define immediate relationships between these vectors:
In the frame of reference formed by \( \mathbf{T} \), \( \mathbf{N} \), and \( \mathbf{B} \), the cross product helps define immediate relationships between these vectors:
- Normal Vector (\( \mathbf{N} \)): Derived using the cross product \( \mathbf{B} \times \mathbf{T} \).
- Binormal Vector (\( \mathbf{B} \)): Emerges from the cross product \( \mathbf{T} \times \mathbf{N} \). This orthogonal characteristic is pivotal for establishing the right-handed system typical in many practical applications.
- Properties: The cross product magnitude is the area of the parallelogram spanned by the two original vectors, and the direction is given by the right-hand rule.
Other exercises in this chapter
Problem 49
\(49-50=\) Find the distance from the point to the given plane. $$(1,-2,4), \quad 3 x+2 y+6 z=5$$
View solution Problem 49
\(49-52=\) Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. $$x=1+2 \sqrt{t}, \quad y=t^{
View solution Problem 50
\(49-50=\) Find the distance from the point to the given plane. $$(-6,3,5), \quad x-2 y-4 z=8$$
View solution Problem 50
The Triangle Inequality for vectors is $$|\mathbf{a}+\mathbf{b}| \leqslant|\mathbf{a}|+|\mathbf{b}|$$ (a) Give a geometric interpretation of the Triangle Inequa
View solution