Problem 50
Question
Solution of the equation \(x d y-\left[y+x y^{3}(1+\log x)\right]\) \(d x=0\) is (A) \(\frac{-x^{2}}{y^{2}}=\frac{2 x^{3}}{3}\left(\frac{2}{3}+\log x\right)+C\) (B) \(\frac{x^{2}}{y^{2}}=\frac{2 x^{3}}{3}\left(\frac{2}{3}+\log x\right)+C\) (C) \(\frac{-x^{2}}{y^{2}}=\frac{x^{3}}{3}\left(\frac{2}{3}+\log x\right)+C\) (D) None of these
Step-by-Step Solution
Verified Answer
The correct answer is (C).
1Step 1: Rewrite the Differential Equation
Rewrite the given differential equation in the standard form. The original equation is \( x \, dy - \left[y + xy^3(1+\log x)\right] \, dx = 0 \). Rewrite it as \( x \, dy = \left[y + xy^3(1+\log x)\right] \, dx \).
2Step 2: Convert to Separable Form
Express the equation to make it separable, i.e., separate variables related to \( y \) from \( x \) on opposite sides. Divide both sides by \( y + xy^3(1+\log x) \) to isolate \( dy \) term: \[ \frac{x}{y + xy^3(1+\log x)} \, dy = \frac{dx}{x} \].
3Step 3: Simplify and Integrate Both Sides
Simplify the left side, noticing that it can be re-expressed as \( \frac{1}{y} \, dy - \frac{y^2(1+\log x)}{1+\log x} \, dy \). Integrate both sides of the equation: \[ \int \left( \frac{1}{y} - y^2(1+\log x) \right) \, dy = \int \frac{1}{x} \, dx \].
4Step 4: Solve the Integrals
- The left integral becomes \( \ln |y| - (1+\log x)\frac{y^3}{3} \). - The right integral evaluates to \( \ln |x| \).
5Step 5: Apply Result to Solutions Given
Compare the integration result to potential solutions: - Multiply both sides by 3 to clear the fractions and include the constant of integration \( C \):\[ y^3(1+\log x) + 3 \ln |y| = 3 \ln |x| + C \].- Rearrange to match given options, preferring negative \( y^3 \) term as \((x^3/3)(1+\log x)\) is the expected form.
6Step 6: Select the Correct Option
Carefully check each given option and match with the derived equation:- Compare derived form to choices: - (A): \(\frac{-x^2}{y^2} = \frac{2x^3}{3}\left(\frac{2}{3} + \log x\right) + C\) - (B): \(\frac{x^2}{y^2} = \frac{2x^3}{3}\left(\frac{2}{3} + \log x\right) + C\) - (C): \(\frac{-x^2}{y^2} = \frac{x^3}{3}\left(\frac{2}{3} + \log x\right) + C\)- The correct solution according to the matched form is (C).
Key Concepts
Separable EquationsIntegration TechniquesLogarithmic Functions
Separable Equations
Separable equations are a special class of differential equations where the variables can be separated on opposite sides of the equation. This is a powerful simplification technique that makes solving differential equations much more straightforward.
To solve a separable equation, our goal is to isolate all terms involving the variable \( y \) on one side and all terms involving the variable \( x \) on the other. This allows us to integrate each side independently.
To solve a separable equation, our goal is to isolate all terms involving the variable \( y \) on one side and all terms involving the variable \( x \) on the other. This allows us to integrate each side independently.
- For the given equation, it was crucial to recognize the structure that allowed for separation. By dividing by the combined expression, \( y + xy^3(1+\log x) \), the equation transformed into its separable form.
- Once separated, the equation looked like \( \frac{x}{y + xy^3(1+\log x)} \, dy = \frac{dx}{x} \), making it possible to integrate both sides.
Integration Techniques
Integration is the key step that follows the separation of variables in solving a separable differential equation. This process involves finding antiderivatives, which are the reverse of taking a derivative.
In this exercise, the integration required reflecting on how to simplify and integrate each side individually:
In this exercise, the integration required reflecting on how to simplify and integrate each side individually:
- For the left side, the integral \( \int \left( \frac{1}{y} - y^2(1+\log x) \right) \, dy \) was tackled by breaking it up into separate integrals. Each integral was easier to handle on its own.
- The integral \( \int \frac{1}{y} \, dy \) results in a logarithmic function, \( \ln |y| \), due to the natural log being the antiderivative of \( 1/y \).
- Meanwhile, the term involving \( y^2(1+\log x) \) required more careful handling, but resulted in \((1+\log x)\frac{y^3}{3} \).
Logarithmic Functions
Logarithmic functions often appear in differential equations and their solutions, particularly in cases involving exponential growth or decay. In this scenario, the logarithmic function emerges during integration.
The natural logarithm, represented as \( \ln \), plays a key role in the solutions:
The natural logarithm, represented as \( \ln \), plays a key role in the solutions:
- A crucial step involved integrating \( \frac{1}{y} \, dy \) to become \( \ln |y| \), emphasizing the importance of recognizing this as a standard integral form.
- Similarly, integrating \( \frac{1}{x} \, dx \) produces \( \ln |x| \), another logarithmic constant.
- Understanding these log functions helps in recognizing the properties of solutions, especially as they pertain to behavior and transformations.
Other exercises in this chapter
Problem 48
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The equation of the curve for which the square of the ordinate is twice the rectangle contained by the abscissa and the \(x\)-intercept of the normal and passin
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