Problem 50
Question
Simplify the radical expression by factoring out the largest perfect nth power. Assume that all variables are positive. $$ \sqrt[3]{-81 a^{5} b^{2}} $$
Step-by-Step Solution
Verified Answer
The simplified expression is
\(-3a\sqrt[3]{3a^2b^2}.\)
1Step 1: Factor the Expression inside the Radical
Start by factoring the expression inside the cube root. Identify the prime factorization of -81, which is \(-81 = -1 \times 3^4\). Therefore, \(-81 a^5 b^2 = -1 \times 3^4 \times a^5 \times b^2.\)
2Step 2: Group the Perfect Cube Factors
Next, group the factors into perfect cubes. Remember, a perfect cube has the form where the exponent is a multiple of 3. Here we have \(-1 = (-1)^1,\)\(3^4 = 3^3 \times 3,\)\(a^5 = a^3 \times a^2,\)\(b^2 = b^2\).
3Step 3: Simplify the Cube Root
Simplify \(\sqrt[3]{-1}\) as \(-1,\)\(\sqrt[3]{3^3} = 3.\)Thus, \(\sqrt[3]{-81 a^5 b^2} = (-1) \times 3 \times \sqrt[3]{3 \times a^2 \times a^3 \times b^2}.\)
4Step 4: Final Simplification
Extract the remaining perfect cubes: \(\sqrt[3]{a^3} = a.\)Thus, the expression simplifies to:\(-3a\sqrt[3]{3a^2b^2}.\)
Key Concepts
Prime FactorizationPerfect CubesCube Root SimplificationFactoring
Prime Factorization
Prime factorization is the process of expressing a number as the product of its prime numbers. Prime numbers are numbers greater than 1 that have no divisors other than 1 and themselves. This process helps to simplify complex expressions and identify components that can be further broken down, especially in expressions involving radicals.
To find the prime factorization, you repeatedly divide the number by its smallest prime factor until you're left with 1. For example, to factor -81:
To find the prime factorization, you repeatedly divide the number by its smallest prime factor until you're left with 1. For example, to factor -81:
- Start with the smallest prime number, which is 3, and check divisibility: 81 can be divided by 3.
- Divide 81 by 3, which gives 27. Divide 27 again by 3 to get 9, then by 3 to get 3, and finally 3 by 3 to get 1.
- Thus, the prime factorization of 81 is 3 raised to the power of 4, because you multiplied 3 by itself four times.
- Don't forget to include the negative sign as -1, making it -1 × 3⁴.
Perfect Cubes
A perfect cube is a number that can be expressed as another whole number raised to the power of three. These values have exponents that are multiples of 3, and they are essential in simplifying cube roots.
When simplifying radical expressions, recognizing perfect cubes allows you to rearrange and group parts of an expression easily. Consider the components like
When simplifying radical expressions, recognizing perfect cubes allows you to rearrange and group parts of an expression easily. Consider the components like
- -1 which is cube of -1 (since \((-1)^3 = -1\)),
- a misleading part \(3^4\), which can be broken down into \(3^3 imes 3\),
- a^5 which can be rewritten as \(a^3 imes a^2\) given that \(a^3\) is a perfect cube, and
- b² remains as it is since it does not form a perfect cube.
Cube Root Simplification
Simplifying cube roots involves extracting factors that are perfect cubes from inside the radical. The cube root of a number asks what number multiplied by itself three times yields the original number.
For the radical expression \(\sqrt[3]{-81a^{5}b^{2}}\):
For the radical expression \(\sqrt[3]{-81a^{5}b^{2}}\):
- Simplify \(\sqrt[3]{-1}\) as \(-1\).
- Recognize \(\sqrt[3]{3^3}\) as 3.
- \(a^3\) gives \(a\) since it’s a perfect cube itself.
Factoring
Factoring is breaking down an expression into a product of simple parts. In the context of simplifying radical expressions, it involves grouping like terms and identifying common factors or perfect powers like squares or cubes.
The key is to first factor the expression as much as possible. In this example, you start with \(-81a^5b^2\), converting primes and rewriting with factors that are perfect powers:
The key is to first factor the expression as much as possible. In this example, you start with \(-81a^5b^2\), converting primes and rewriting with factors that are perfect powers:
- Write \(-1\) as \((-1)^1\) and \(-81\) as \(-1 \times 3^4\).
- Rearrange terms like \(3^4\) to \(3^3 \times 3\), \(a^5\) as \(a^3 \times a^2\).
Other exercises in this chapter
Problem 50
Apply the distributive property. $$-3 x(5+x)$$
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Exercises \(45-54:\) Use the quotient rule to simplify the expression. Use positive exponents to write your answer. $$ \frac{10 x^{5}}{5 x^{-3}} $$
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Factor the expression completely. \(2 x^{3}+8 x^{2}-24 x\)
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Write the expression in radical notation. Then evaluate the expression when the result is an integer. $$ 81^{3 / 4} $$
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