Problem 50
Question
Show that the indicated implication is true. $$ |x+2|<0.3 \Rightarrow|4 x+8|<1.2 $$
Step-by-Step Solution
Verified Answer
The implication \(|x+2| < 0.3 \Rightarrow |4x+8| < 1.2\) is true, as \(4|x+2| = |4x+8| < 1.2\).
1Step 1: Understand the Given Condition
The problem asks us to show that if \(|x+2| < 0.3\), then \(|4x+8| < 1.2\). We first need to understand the implication by examining the condition \(|x+2| < 0.3\). This condition tells us that the distance between \(x\) and \(-2\) is less than 0.3.
2Step 2: Simplify the Implication
To prove the implication, we need to make \(|4x+8|\) in terms of \(x+2\). Notice that \(4x + 8\) can be rewritten as \(4(x+2)\). Using this, we have \(|4x+8| = |4(x+2)| = 4|x+2|\).
3Step 3: Apply the Given Condition
Substitute the condition \(|x+2| < 0.3\) into the expression for \(|4x+8|\). This gives us \(4|x+2| < 4 imes 0.3 = 1.2\). Now \(|4x+8| < 1.2\).
4Step 4: Conclusion
Since we have shown that the derived condition \(|4x+8| < 1.2\) directly follows from the given inequality \(|x+2| < 0.3\), the implication is true.
Key Concepts
Absolute Value InequalitiesLogical ImplicationsMathematical Proofs
Absolute Value Inequalities
Absolute value inequalities are a way to express the distance of a number from zero on the real number line. These inequalities help determine a range within which a number lies. For example, \(|x+2| < 0.3\) suggests that the distance between \(x\) and \(-2\) is less than 0.3.
When working with absolute value inequalities, it's helpful to think in terms of distance:
When working with absolute value inequalities, it's helpful to think in terms of distance:
- \(|x| < a\) translates to \(-a < x < a\).
- The inequality \(|x-a| < b\) can be expressed as \(a-b < x < a+b\), highlighting the range of \(x\) values within the bounds of \(a\) and \(b\).
Logical Implications
Logical implications are statements that express a dependability from one statement (the antecedent) to another (the consequent). In simpler terms, if the antecedent is true, then logically, the consequent will also be true.
In the exercise given, the logical implication is \(|x+2|<0.3 \Rightarrow |4x+8|<1.2\). Here, our job is to prove that whenever the condition \(|x+2| < 0.3\) is satisfied, it necessarily results in the condition \(|4x+8| < 1.2\).
In the exercise given, the logical implication is \(|x+2|<0.3 \Rightarrow |4x+8|<1.2\). Here, our job is to prove that whenever the condition \(|x+2| < 0.3\) is satisfied, it necessarily results in the condition \(|4x+8| < 1.2\).
- The initial statement, or antecedent, is \(|x+2|<0.3\).
- The concluding statement, or consequent, is \(|4x+8|<1.2\).
Mathematical Proofs
Mathematical proofs are structured arguments that ensure a statement or theorem to be true. In proving implications, a common method is showing how one statement logically follows another through a series of justified steps. Each step is based on fundamental principles or previously established results.
For this problem, by transforming the expression \(|4x+8|\) in terms of \(|x+2|\), we can use a simple arithmetic method for our proof:
For this problem, by transforming the expression \(|4x+8|\) in terms of \(|x+2|\), we can use a simple arithmetic method for our proof:
- Transform \(4x+8\) into \(4(x+2)\).
- Apply the condition that was initially given \(|x+2| < 0.3\) to find \(4|x+2| < 1.2\), demonstrating the required result.
Other exercises in this chapter
Problem 50
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