Problem 50
Question
Reduce each fraction to lowest terms. a. \(\frac{6}{42}\) b. \(\frac{6}{44}\) c. \(\frac{6}{45}\) d. \(\frac{6}{46}\) e. \(\frac{6}{48}\)
Step-by-Step Solution
Verified Answer
a. \(\frac{1}{7}\), b. \(\frac{3}{22}\), c. \(\frac{2}{15}\), d. \(\frac{3}{23}\), e. \(\frac{1}{8}\).
1Step 1: Understanding the Problem
The task is to simplify each given fraction \(\frac{a}{b}\) to its lowest terms by dividing both the numerator \(a\) and the denominator \(b\) by their greatest common divisor (GCD).
2Step 2: Simplifying \(\frac{6}{42}\)
Find the GCD of 6 and 42, which is 6. Divide both the numerator and the denominator by 6. \(\frac{6 \div 6}{42 \div 6} = \frac{1}{7}\). So, \(\frac{6}{42}\) simplifies to \(\frac{1}{7}\).
3Step 3: Simplifying \(\frac{6}{44}\)
Find the GCD of 6 and 44, which is 2. Divide both numbers by 2. \(\frac{6 \div 2}{44 \div 2} = \frac{3}{22}\). So, \(\frac{6}{44}\) simplifies to \(\frac{3}{22}\).
4Step 4: Simplifying \(\frac{6}{45}\)
Find the GCD of 6 and 45, which is 3. Divide both numbers by 3. \(\frac{6 \div 3}{45 \div 3} = \frac{2}{15}\). So, \(\frac{6}{45}\) simplifies to \(\frac{2}{15}\).
5Step 5: Simplifying \(\frac{6}{46}\)
Find the GCD of 6 and 46, which is 2. Divide both numbers by 2. \(\frac{6 \div 2}{46 \div 2} = \frac{3}{23}\). So, \(\frac{6}{46}\) simplifies to \(\frac{3}{23}\).
6Step 6: Simplifying \(\frac{6}{48}\)
Find the GCD of 6 and 48, which is 6. Divide both numbers by 6. \(\frac{6 \div 6}{48 \div 6} = \frac{1}{8}\). So, \(\frac{6}{48}\) simplifies to \(\frac{1}{8}\).
Key Concepts
Understanding the Greatest Common Divisor (GCD)Simplifying Fractions to Lowest TermsUnderstanding Numerators and Denominators
Understanding the Greatest Common Divisor (GCD)
The concept of the Greatest Common Divisor, or GCD, is a key element to understanding how to simplify fractions. The GCD of two numbers is the largest number that can evenly divide both of them.
For example, when you want to simplify the fraction \(\frac{6}{42}\), you look for the largest number that can divide both 6 and 42 without leaving a remainder.
To find the GCD, list out the factors of each number:
When you have the GCD, you can then divide both the numerator and the denominator of the fraction by this number to simplify the fraction.
For example, when you want to simplify the fraction \(\frac{6}{42}\), you look for the largest number that can divide both 6 and 42 without leaving a remainder.
To find the GCD, list out the factors of each number:
- Factors of 6: 1, 2, 3, 6
- Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42
When you have the GCD, you can then divide both the numerator and the denominator of the fraction by this number to simplify the fraction.
Simplifying Fractions to Lowest Terms
Simplifying a fraction to its lowest terms involves reducing it so that the numerator and the denominator have no common factors other than 1. This is where the GCD becomes crucial.
Let's take the fraction \(\frac{6}{44}\) as another example. The GCD here is 2.
By dividing both the numerator and the denominator by 2, you reduce the fraction:
By always checking for and dividing by the GCD, any fraction can be reduced to its lowest terms.
Let's take the fraction \(\frac{6}{44}\) as another example. The GCD here is 2.
By dividing both the numerator and the denominator by 2, you reduce the fraction:
- Numerator: \(6 \div 2 = 3\)
- Denominator: \(44 \div 2 = 22\)
By always checking for and dividing by the GCD, any fraction can be reduced to its lowest terms.
Understanding Numerators and Denominators
In any fraction \(\frac{a}{b}\), the numerator is the top number \(a\), and the denominator is the bottom number \(b\). These elements define how many parts the fraction is divided into and how many parts are being considered.
Let's consider the fraction \(\frac{6}{45}\). Here,
Simplification helps in better understanding and comparing fractions, as it presents them in their most concise form.
Let's consider the fraction \(\frac{6}{45}\). Here,
- Numerator (\(a\)): 6
- Denominator (\(b\)): 45
- New numerator: \(6 \div 3 = 2\)
- New denominator: \(45 \div 3 = 15\)
Simplification helps in better understanding and comparing fractions, as it presents them in their most concise form.
Other exercises in this chapter
Problem 50
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