Problem 50
Question
Loss of a \(\beta\) particle is equivalent to (a) increase of one proton only (b) decrease of one neutron only (c) both (a) and (b) (d) none of these
Step-by-Step Solution
Verified Answer
(c) both (a) and (b)
1Step 1: Understand Beta Decay
In beta decay, a neutron in the nucleus changes into a proton while an electron (called a beta particle) is emitted. This process causes the atomic number to increase by one because a neutron becomes a proton.
2Step 2: Identify Changes in Atomic Structure
With the emission of a beta particle, the nucleus loses a neutron but gains a proton. This changes the element because its atomic number increases by one, but the mass number remains unchanged since a neutron is converted into a proton.
3Step 3: Evaluate the Options
Looking at the options:
(a) Increase of one proton only - indicates that the atomic number increases by one.
(b) Decrease of one neutron only - implies that a neutron has been removed but not replaced.
(c) Both (a) and (b) - fits the situation of beta decay perfectly, as one neutron decreases, and one proton increases.
(d) None of these - doesn't fit since option (c) is applicable.
4Step 4: Choose the Correct Answer
Option (c) both (a) and (b) is correct because beta decay results in an increase of one proton and a decrease of one neutron simultaneously.
Key Concepts
Neutron to Proton ConversionAtomic Number ChangeNuclear Reactions
Neutron to Proton Conversion
In beta decay, a fascinating transformation occurs within an atom's nucleus where a neutron is converted into a proton. Let's break down what's happening here: Neutrons and protons reside in the nucleus of an atom, serving as core components of all atomic structures.
When beta decay occurs:
When beta decay occurs:
- A neutron is transformed into a proton.
- This process releases a beta particle, which is essentially an electron ejected from the nucleus.
Atomic Number Change
The transformation from neutron to proton during beta decay leads to one very significant change: the atomic number increases by one.
Atomic number refers to the number of protons in the nucleus of an atom. For every neutron that becomes a proton via beta decay, the atomic number jumps up by one, indicating a new element has formed. Yet, despite this increase:
Atomic number refers to the number of protons in the nucleus of an atom. For every neutron that becomes a proton via beta decay, the atomic number jumps up by one, indicating a new element has formed. Yet, despite this increase:
- The mass number—sum of protons and neutrons—remains unchanged since one nucleon is altered, not added or removed.
- This process doesn't add any additional particles to the atom but redistributes the existing ones.
Nuclear Reactions
Nuclear reactions are processes where the nucleus of an atom undergoes modification. Beta decay is a prime example of such a reaction, vividly demonstrating how the internal structure of an atom's nucleus can be rearranged without altering the overall mass of the atom.
During nuclear reactions like beta decay:
During nuclear reactions like beta decay:
- Energy is often released, sometimes in significant amounts.
- The identity of the element involved changes due to alterations within the nucleus.
- New particles, like beta particles and neutrinos, are emitted.
Other exercises in this chapter
Problem 48
If uranium (mass number 238 and atomic number 92 ) emits an \(\alpha\) particle, the product has mass number and atomic number (a) 234 and 90 (b) 236 and 92 (c)
View solution Problem 49
Which of the following notations shows the product incorrectly? (a) \({ }_{5} \mathrm{~B}^{10}(\alpha, \mathrm{n})_{7} \mathrm{~N}^{13}\) (b) \({ }_{96} \mathrm
View solution Problem 51
Which of the following is a fusion reaction? (a) \({ }_{98} \mathrm{U}^{255}+{ }_{0} \mathrm{n}^{1} \longrightarrow{ }_{36} \mathrm{Ba}^{141}+{ }_{36} \mathrm{K
View solution Problem 53
The binding energy of an element is \(64 \mathrm{meV}\). If \(\mathrm{BE} /\) Nucleon is \(6.4\), the number of nucleons are (a) 10 (b) 64 (c) 16 (d) \(6.4\)
View solution