Problem 50
Question
In Exercises \(45-54\), evaluate the algebraic expression for the given values of the variables. If it is not possible, state the reason. \(\frac{5 x}{y-3}\) (a) \(x=2, y=4\) (b) \(x=2, y=3\)
Step-by-Step Solution
Verified Answer
(a) 10, (b) undefined due to division by zero
1Step 1: Substitute the given values for x and y (case a)
We first replace x by 2 and y by 4 in the expression, yielding \(\frac{5 * 2}{4 - 3}\),which simplifies to \(\frac{10}{1}\).
2Step 2: Perform the division (case a)
Perform the division gives us the final result, 10.
3Step 3: Substitute the given values for x and y (case b)
Next, we substitute x by 2 and y by 3 in the expression, yielding \(\frac{5 * 2}{3 - 3}\),which simplifies to \(\frac{10}{0}\).
4Step 4: Discuss the undefined result (case b)
As division by zero is undefined in mathematics, we conclude that the value of the algebraic expression is not defined for x = 2 and y = 3.
Key Concepts
SubstitutionUndefined ExpressionsAlgebraic Fractions
Substitution
Substitution is a fundamental technique in algebra that allows you to evaluate expressions by replacing variables with given values. When you come across an algebraic expression like \(\frac{5x}{y-3}\), and are asked to evaluate it for specific values, your first step is to substitute these values into the equation. This involves:
It's crucial to ensure that you substitute carefully to avoid simple mistakes, as these can change the problem entirely.
- Identifying the variables present in the expression.
- Replacing each variable with the numbers provided in the problem.
It's crucial to ensure that you substitute carefully to avoid simple mistakes, as these can change the problem entirely.
Undefined Expressions
In algebra, you might encounter situations where evaluating an expression leads to an undefined result. One classic case is division by zero. This is a crucial point to understand because mathematically, dividing by zero makes the expression meaningless or undefined.
For the expression \(\frac{5x}{y-3}\), when you substitute \(x=2\) and \(y=3\), the denominator becomes zero: \(3 - 3 = 0\). As a result:
For the expression \(\frac{5x}{y-3}\), when you substitute \(x=2\) and \(y=3\), the denominator becomes zero: \(3 - 3 = 0\). As a result:
- You try to evaluate \(\frac{10}{0}\).
- Since division by zero is undefined, the entire expression has no defined value.
Algebraic Fractions
Algebraic fractions are expressions that involve fractions with variables in the numerator, the denominator, or both. They resemble numerical fractions, but with the added complexity of variables, which means their values can change depending on the variables they contain.
For example, in \(\frac{5x}{y-3}\), \(5x\) is the numerator, and \(y-3\) is the denominator. Working with algebraic fractions involves steps like:
Knowing how to handle algebraic fractions is vital as they frequently appear in equations and inequalities in algebra, offering both challenges and opportunities for problem-solving.
For example, in \(\frac{5x}{y-3}\), \(5x\) is the numerator, and \(y-3\) is the denominator. Working with algebraic fractions involves steps like:
- Simplifying the fractions by canceling common factors.
- Substituting given values to solve.
Knowing how to handle algebraic fractions is vital as they frequently appear in equations and inequalities in algebra, offering both challenges and opportunities for problem-solving.
Other exercises in this chapter
Problem 50
In Exercises 45-50, an expression for the balance in an account is given. Use a guess, check, and revise strategy to determine the time (in years) necessary for
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In Exercises \(47-66\), simplify the expression by removing symbols of grouping and combining like terms. $$ (2 x-1) 2+x+9 $$
View solution Problem 51
In Exercises 51-54, determine whether each value of \(x\) is a solution of the equation. \(\frac{2}{x}-\frac{1}{x}=1\) (a) \(x=0\) (b) \(x=\frac{1}{3}\)
View solution Problem 51
The sides of a square have lengths of \(a\) centimeters. Draw the square. Draw the rectangle obtained by extending two parallel sides of the square 6 centimeter
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