Problem 50
Question
If \(q^{2}-4 p r=0, p>0\), then the domain of the function \(f(x)=\log \left[p x^{3}+(p+q) x^{2}+(q+r) x+r\right]\) is (A) \(R-\left\\{-\frac{q}{2 p}\right\\}\) (B) \(R-\left[(-\infty,-1] \cup\left\\{-\frac{q}{2 p}\right\\}\right]\) (C) \(R-\left[(-\infty,-1) \cap\left\\{-\frac{q}{2 p}\right\\}\right]\) (D) None of these
Step-by-Step Solution
Verified Answer
Option A is correct. Domain: \(R-\left\{-\frac{q}{2 p}\right\}\).
1Step 1: Understanding the Function Inside the Logarithm
The function inside the logarithm is \(px^3 + (p+q)x^2 + (q+r)x + r\). For the logarithm function to be defined, this polynomial must be positive, i.e., \(px^3 + (p+q)x^2 + (q+r)x + r > 0\).
2Step 2: Analyzing the Given Condition
From the given condition \(q^2-4pr=0\), we can identify that this is the discriminant of a quadratic equation. This implies that the quadratic \(prx^2 + qx + r\) corresponding to the discriminant has equal roots, specifically at \(x = -\frac{q}{2p}\) since \(p > 0\).
3Step 3: Analyzing the Behavior Near the Root
The polynomial \(px^3 + (p+q)x^2 + (q+r)x + r\) can be rewritten by substituting the root: \(px^3 + (p+q)x^2 + (q+r)x + r = p(x + \frac{q}{2p})^2g(x)\), where \(g(x)\) is some polynomial function. The function inside the log becomes zero at \(x = -\frac{q}{2p}\).
4Step 4: Domain of the Function
The function \(f(x) = \log(px^3 + (p+q)x^2 + (q+r)x + r)\) is not defined at \(x = -\frac{q}{2p}\) because the logarithm of zero is undefined. Other than this point, the function is defined everywhere else on \(\mathbb{R}\) since there are no other restrictions indicated in the problem. Thus, the domain of \(f(x)\) is \(\mathbb{R} - \{-\frac{q}{2p}\}\).
5Step 5: Selection of the Correct Answer Option
Compare the obtained domain with the given answer options. The correct option is (A), which states the domain as \(\mathbb{R} - \{-\frac{q}{2p}\}\). This matches our derived domain.
Key Concepts
Polynomial FunctionsDiscriminant of Quadratic EquationsDomain of a Function
Polynomial Functions
Polynomial functions are algebraic expressions consisting of variables and coefficients. They involve only non-negative integer exponents of variables. A polynomial function can be presented in the form \( a_n x^n + a_{n-1} x^{n-1} + \cdots + a_1 x + a_0 \). Here, each \( a_i \) represents a coefficient and is a real number, while \( x \) is a variable raised to the power of \( i \), an integer. This function can have one or more terms depending on the degree of the polynomial, which is the highest exponent of the variable present in the expression.
Examples of polynomial functions include:
Examples of polynomial functions include:
- Linear polynomials: like \( 2x + 3 \)
- Quadratic polynomials: like \( 4x^2 + x + 1 \)
- Cubic polynomials: like \( x^3 - 3x + 5 \)
Discriminant of Quadratic Equations
The discriminant is a part of the quadratic formula used to find the roots of quadratic equations of the form \( ax^2 + bx + c = 0 \). The discriminant \( \Delta \) is given by the expression \( b^2 - 4ac \). It determines the nature and number of roots of the quadratic function:
- If \( \Delta > 0 \), the quadratic equation has two distinct real roots.
- If \( \Delta = 0 \), the quadratic equation has exactly one real root, also known as a repeated or double root.
- If \( \Delta < 0 \), the quadratic equation has no real roots, but two complex roots.
Domain of a Function
The domain of a function consists of all the input values \( x \) for which the function is defined. A function's domain is integral to understanding its usability and range of operation. In mathematical terms, it includes all real numbers \( x \) such that the function \( f(x) \) takes on real values.
To determine the domain of a logarithmic function like \( f(x) = \log(px^3 + (p+q)x^2 + (q+r)x + r) \), it is essential to consider where the inside of the logarithm is positive. Since the logarithm of zero or a negative number is undefined, the polynomial must be strictly greater than zero for the logarithm to exist.
To determine the domain of a logarithmic function like \( f(x) = \log(px^3 + (p+q)x^2 + (q+r)x + r) \), it is essential to consider where the inside of the logarithm is positive. Since the logarithm of zero or a negative number is undefined, the polynomial must be strictly greater than zero for the logarithm to exist.
- From our problem, we identified that the expression becomes zero at \( x = -\frac{q}{2p} \). Hence, this point is excluded from the domain.
- Other than this excluded point, \( f(x) \) is defined across all real numbers causing the domain to be \( \mathbb{R} - \{-\frac{q}{2p}\} \).
Other exercises in this chapter
Problem 48
Suppose \(f:[2,2] \rightarrow R\) is defined by, $$ f(x)= \begin{cases}-1 & \text { for }-2 \leq x \leq 0 \\ x-1 & \text { for } 0 \leq x \leq 2\end{cases} $$ t
View solution Problem 49
Let \(f(x)=[x]^{2}+[x+1]-3\), where \([x]\) is greatest integer less than or equal to \(x\), then (A) \(f(x)\) is a many one and into function (B) \(f(x)=0\) fo
View solution Problem 52
If \([x]\) denotes the integral part of \(x\), then the domain of the function \(f(x)=\sin ^{-1}\left[2 x^{2}-3\right]+\log _{2}\left[\log _{12}\left(x^{2}-5 x+
View solution Problem 53
If \(f(n+1)=\frac{2 f(n)+1}{2}, n=1,2, \ldots\) and \(f(1)=2\), then \(f(101)\) equals (A) 52 (B) 49 (C) 48 (D) 51
View solution