Problem 50
Question
If \(f(x)=x^{2}-4 x+10\), find \(f(-a), f(a-4)\), and \(f(a+h) .\)
Step-by-Step Solution
Verified Answer
\(f(-a) = a^2 + 4a + 10\); \(f(a-4) = a^2 - 12a + 42\); \(f(a+h) = a^2 + 2ah + h^2 - 4a - 4h + 10\).
1Step 1: Understand the Function
The function given is \( f(x) = x^2 - 4x + 10 \). It describes how each input \( x \) is transformed by squaring it, subtracting four times \( x \), and then adding 10.
2Step 2: Substitute for \( f(-a) \)
In this step, substitute \( -a \) into the function wherever \( x \) appears: \( f(-a) = (-a)^2 - 4(-a) + 10 \). This simplifies to: \[(-a)^2 = a^2,\ -4(-a) = 4a.\ \]So, \( f(-a) = a^2 + 4a + 10 \).
3Step 3: Substitute for \( f(a-4) \)
Substitute \( a-4 \) into the function wherever \( x \) appears: \( f(a-4) = (a-4)^2 - 4(a-4) + 10 \). Calculate each part:\[(a-4)^2 = a^2 - 8a + 16,\ -4(a-4) = -4a + 16.\ \]Thus, \( f(a-4) = a^2 - 8a + 16 - 4a + 16 + 10 \), simplifying to \( a^2 - 12a + 42 \).
4Step 4: Substitute for \( f(a+h) \)
Substitute \( a+h \) into the function wherever \( x \) appears: \( f(a+h) = (a+h)^2 - 4(a+h) + 10 \). Calculate each part:\[(a+h)^2 = a^2 + 2ah + h^2,\ -4(a+h) = -4a - 4h.\ \]So, \( f(a+h) = a^2 + 2ah + h^2 - 4a - 4h + 10 \).
Key Concepts
Understanding Polynomial FunctionsDecoding Algebraic ExpressionsExploring Quadratic Equations
Understanding Polynomial Functions
Polynomial functions are like the backbone of algebra. They are mathematical expressions where you find terms like variables raised to powers, multiplied by coefficients, and sometimes added or subtracted with constants. Think of them as building blocks that can take different shapes based on the powers and coefficients. For example, in the function given, \( f(x) = x^2 - 4x + 10 \), we have a quadratic polynomial function. Here, the highest power of \( x \) is 2, which makes it a quadratic. It's important to note the structure:
- The quadratic term: \( x^2 \) with coefficient 1.
- The linear term: \( -4x \) with coefficient -4.
- The constant term: 10.
Decoding Algebraic Expressions
Algebraic expressions consist of numbers, letters (variables), and operational signs that come together to create a mathematical statement. When you see something like \( f(x) = x^2 - 4x + 10 \), you're looking at an algebraic expression where:
- \( x \) is a placeholder for any real number you substitute in its place.
- Expressions are simplified using substitute techniques by replacing \( x \) with another variable or number.
Exploring Quadratic Equations
Quadratic equations are a significant milestone in algebra. They are written in the standard form \( ax^2 + bx + c = 0 \), where \( a, b, \) and \( c \) are constants. In our example, the expression \( x^2 - 4x + 10 \) is a part of a quadratic equation when set equal to zero.
- This quadratic has a "U" shape if graphed, often leading to two solutions (roots), one solution, or no real solution depending on the equation's discriminant.
- Simplifying substitutions in these can reveal different properties and paths to solving for unknowns.
Other exercises in this chapter
Problem 50
(a) find the inverse of the given function, and (b) graph the given function and its inverse on the same set of axes. (Objective 4) $$f(x)=x^{2}+2, x \geq 0$$
View solution Problem 50
Graph each of the functions. $$f(x)=-3|x|-4$$
View solution Problem 51
Does the function \(f(x)=4\) have an inverse? Explain your answer.
View solution Problem 51
Graph each of the following parabolas, and keep in mind that you may need to change the dimensions of the viewing window to obtain a good picture. (a) \(f(x)=x^
View solution