Problem 50
Question
Give the center and radius of the circle described by the equation and graph each equation. Use the graph to identify the relation's domain and range. $$x^{2}+(y-2)^{2}=4$$
Step-by-Step Solution
Verified Answer
The center of the circle is at (0,2) and the radius is 2. The domain of the graph is \([-2,2]\) and the range is \([0,4]\).
1Step 1: Express in Standard Form
The given equation is already in the standard form of a circle's equation, which is \((x-h)^{2}+(y-k)^{2}=r^{2}\), where \((h,k)\) are the coordinates of the center and \(r\) is the radius. Therefore, no rewriting is necessary.
2Step 2: Identify the Center and Radius
Comparing the given equation, \(x^{2}+(y-2)^{2}=4\), to the standard form, we can identify the center as \((h,k)\)=(0,2) and the radius, \(r\), as \(\sqrt{4}\)=2.
3Step 3: Sketch the Graph
Plot the center of the circle at point (0,2) then sketch the circle with a radius of 2.
4Step 4: Identify Domain and Range
The domain and range can be identified from the graph. The domain is all the x-values that the graph covers. Looking at the graph, we can tell that the graph covers x-values from -2 to 2. Similarly, the range is all the y-values that the graph covers. Since the center is at y=2 and the radius is 2, the graph on the y-axis ranges from 0 to 4. Hence, the domain is \([-2, 2]\) and the range is \([0, 4]\).
Key Concepts
Domain and RangeCenter and RadiusStandard Form of a Circle
Domain and Range
The domain and range of a circle describe the set of all possible coordinates that the circle covers on a graph. These concepts are crucial in understanding the limits of a circle's reach within the coordinate plane. The domain relates to the x-values, while the range pertains to the y-values.
In the equation given, \(x^{2} + (y - 2)^{2} = 4\), the center is at \((0, 2)\) and has a radius of 2. This tells us that the circle extends 2 units in every direction from the center. Therefore:
In the equation given, \(x^{2} + (y - 2)^{2} = 4\), the center is at \((0, 2)\) and has a radius of 2. This tells us that the circle extends 2 units in every direction from the center. Therefore:
- The domain is the set of x-values from -2 to 2, since the circle extends 2 units left and right from the x-coordinate of the center, which is 0.
- The range is the set of y-values from 0 to 4, as the circle extends 2 units above and below the y-coordinate of the center, which is 2.
Center and Radius
Understanding the center and radius of a circle is fundamental when working with circle equations. These two components help determine the circle's position and size on a graph.
For a circle's equation in standard form \((x-h)^2 + (y-k)^2 = r^2\), the center is described by the coordinates \((h, k)\), and the radius \(r\) is the distance from the center to any point on the circumference.
For a circle's equation in standard form \((x-h)^2 + (y-k)^2 = r^2\), the center is described by the coordinates \((h, k)\), and the radius \(r\) is the distance from the center to any point on the circumference.
- In our equation, \(x^2 + (y-2)^2 = 4\), we directly compare this to \((x-h)^2 + (y-k)^2 = r^2\) to find the center at \((0, 2)\).
- The number 4 is the radius squared, so the actual radius \(r\) is the square root of that number, which is 2.
Standard Form of a Circle
The standard form of a circle's equation is crucial for quickly identifying a circle’s geometric properties. This form facilitates easy identification of the circle’s center and radius.
A circle's equation is generally expressed as:\[(x-h)^2 + (y-k)^2 = r^2\]
A circle's equation is generally expressed as:\[(x-h)^2 + (y-k)^2 = r^2\]
- This equation ensures that any point \((x, y)\) on the circle maintains a constant distance, or radius, \(r\), from the circle's center \((h, k)\).
- Here, \(h\) and \(k\) are the horizontal and vertical shifts from the origin to reach the center, respectively.
- The center is at \((0, 2)\)
- The radius is determined by taking the square root of the right-hand side, which is 2, since \(r^2 = 4\).
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